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Simple Harmonic Motion

NEET > Physics > Oscillations and Waves

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Overview content

Chapter Snapshot - Simple Harmonic Motion

Simple Harmonic Motion is the cornerstone of oscillation theory — it appears in springs, pendulums, molecules, AC circuits and sound waves. You will master the restoring-force definition (F = −kx), displacement/velocity/acceleration equations, energy inter-conversion between KE and PE, time-period formulae for spring and simple pendulum, spring combinations (series/parallel), special pendulums, and damped/forced oscillations with resonance. Every NEET Biology, Chemistry and Physics paper has at least 3-4 questions rooted directly in this chapter.

✓ Use This To Plan Your First 2–3 Hours
Expected Questions (Typical)
Q
3-4
NEET consistently yields 3-4 SHM questions per paper, typically one on v = ω√(A²−x²), one on T = 2π√(m/k) or T = 2π√(l/g), one energy question, and one conceptual on phase or resonance.
Time Required (Practical)
⏱
8-10 hrs
Theory + derivations: ~3 hrs; displacement/velocity/acceleration/energy numericals: ~3 hrs; pendulum and spring combination problems: ~2 hrs; MCQ revision: ~2 hrs.
Difficulty Level
⚡
Moderate
Formulae are straightforward once the core set (x, v, a, E as functions of displacement) is internalised. Traps arise in phase analysis, spring combination, and pendulum variations (lift, electric field, liquid medium).
Most Asked Style: Numerical — given amplitude A, angular frequency ω and position x, find velocity or acceleration. Also frequent: 'time period of spring combination' and 'time period of pendulum in a lift'.Biggest Trap: Confusing velocity and acceleration maxima positions — velocity is maximum at x = 0 (mean position) while acceleration is maximum at x = ±A (extreme positions); students often swap these.Fast Win: Memorise v = ω√(A²−x²) and a = −ω²x together: one gives velocity at any position, the other gives acceleration. These two formulae answer ~50% of all SHM numericals.Revision-Friendly: The single energy-position graph (PE = ½mω²x², KE = ½mω²(A²−x²), TE = ½mω²A² = constant) is a one-diagram revision of the entire energy section. Add the table of values at x = 0, x = ±A, x = ±A/2, x = ±A/√2 for instant MCQ recall.

Subtopics - Simple Harmonic Motion (NEET)

From pendulums to springs — master the mathematics and physics of oscillation

Revision tip: Memorise the three kinematic equations in SHM — displacement x = a sinωt, velocity v = aω cosωt = ω√(a²−x²), acceleration A = −ω²x — then derive all energy, time-period and phase facts from them. Never rote-learn values; always trace them back to these three.
NCERT LinesMCQsQuick Test

1) Periodic Motion and SHM Definition

Periodic vs oscillatory vs harmonic motion, the defining characteristic of SHM (restoring force ∝ −displacement), angular SHM via restoring torque, and the key terminologies: time period, frequency, angular frequency and phase.

F = −kxPeriodic MotionHarmonic OscillationAngular Frequency ω = 2πnPhase φInitial Phase
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Periodic and Oscillatory MotionPeriodic motion repeats after regular interval T. Oscillatory motion: body moves to-and-fro about a fixed mean position. All SHM is periodic but not all periodic motion is SHM.
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Harmonic vs Non-Harmonic OscillationHarmonic: expressible as single sine/cosine, y = a sinωt. Non-harmonic: combination of two or more harmonics, y = a sinωt + b sin2ωt.
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Restoring Force and SHM DefinitionF ∝ −x ⇒ F = −kx. Force constant k: SI unit N/m, dimension [MT⁻²]. Angular SHM: τ ∝ −θ. Time period independent of amplitude.
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Time Period, Frequency and Angular FrequencyT = least time interval for repetition (SI: second). Frequency n = oscillations per second (SI: Hz). Angular frequency ω = 2πn (rad/s).
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Phase and Initial PhasePhase θ = ωt + φ₀ completely describes position and direction at any instant. φ₀ = initial phase (epoch). Same phase: Δφ = 2nπ; opposite phase: Δφ = (2n+1)π.

2) Displacement, Velocity and Acceleration in SHM

Mathematical equations for displacement as projection of uniform circular motion, velocity as time-derivative of displacement with its ellipse graph vs displacement, acceleration as proportional to −displacement with its straight-line graph, and phase relationships between the three.

x = a sinωtv = ω√(a²−x²)a = −ω²xv_max = aω at x=0a_max = ω²a at x=±aPhase Leads
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Displacement Equationy = a sinωt (from mean), y = a cosωt (from extreme), y = a sin(ωt ± φ) (general). SHM as projection of UCM on a diameter.
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Velocity in SHMv = aω cosωt = ω√(a²−y²). Max at y = 0: v_max = aω. Zero at y = ±a. Graph of v vs y is an ellipse (circle for ω = 1).
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Acceleration in SHMA = −ω²y. Max at y = ±a: A_max = ω²a. Zero at y = 0. Graph A vs y is a straight line with slope −ω².
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Phase RelationshipsVelocity leads displacement by π/2; acceleration leads velocity by π/2; acceleration is π ahead of displacement. All three vary with same period.
›
Comparative Table at Key PositionsAt mean (y=0): v = max, a = 0, F = 0. At extreme (y=±a): v = 0, a = max = ω²a, F = max = mω²a.

3) Energy in SHM

Potential energy, kinetic energy and total mechanical energy as functions of displacement and time. Average values over a complete cycle, and energy-position and energy-time graphs.

KE = ½mω²(a²−y²)PE = ½mω²y²TE = ½mω²a²KE = PE at y = a/√2Average KE = Average PE = ½E
›
Potential EnergyU = ½ky² = ½mω²y². Max at y = ±a: U_max = ½mω²a² = E. Zero at y = 0. Varies with double frequency of SHM.
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Kinetic EnergyK = ½mv² = ½mω²(a²−y²). Max at y = 0: K_max = ½mω²a² = E. Zero at y = ±a. Varies with double frequency.
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Total Mechanical EnergyE = K + U = ½mω²a² = constant (independent of position). TE ∝ a² and ∝ ω².
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Energy at Key PositionsAt y = ±a/2: U = E/4, K = 3E/4. At y = ±a/√2: U = K = E/2. At y = 0: U = 0, K = E.
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Average EnergiesK_avg = U_avg = ½E = ¼mω²a². Equal average values — energy splits equally between KE and PE over a full cycle.

4) Simple Pendulum

Derivation of T = 2π√(l/g), independence of period from mass and amplitude (for small θ), effective length, and the effect of various factors (amplitude, mass, length, g, temperature, liquid medium, electric field) on the time period. Second's pendulum and special pendulum types.

T = 2π√(l/g)Independent of mass and amplitudeT ∝ √lT ∝ 1/√gSecond's pendulum l ≈ 1 mPendulum in lift
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Derivation of Time Periodτ = −mgl sinθ ≈ −mglθ for small θ. α = −(g/l)θ ⇒ ω² = g/l ⇒ T = 2π√(l/g). Valid for small amplitude (sinθ ≈ θ).
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Factors Affecting Time PeriodAmplitude: independent (for small oscillations). Mass: independent. Length l: T ∝ √l (effective l = suspension to CM). g: T ∝ 1/√g — slower on hills and in mines, faster on dense planets.
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Temperature EffectRising temperature increases l (thermal expansion) ⇒ T increases ⇒ clock runs slow. ΔT/T ≈ ½ α Δθ.
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Pendulum in a LiftLift at rest or uniform velocity: T = 2π√(l/g). Lift accelerating up: g_eff = g+a ⇒ T decreases (faster). Lift accelerating down: g_eff = g−a ⇒ T increases (slower). Free fall (a=g): T = ∞, no oscillation.
›
Pendulum in Liquid / Electric FieldIn liquid (density σ < ρ): g_eff = g(1−σ/ρ) < g ⇒ T increases. In upward electric field (charge q): g_eff = g − qE/m ⇒ T increases. Downward E: g_eff = g + qE/m ⇒ T decreases. Horizontal E: g_eff = √(g² + (qE/m)²).
›
Second's Pendulum and Special TypesSecond's pendulum: T = 2 s, l ≈ 99.3 cm (≈ 1 m on Earth). Infinite-length pendulum: T_max ≈ 84.6 min. Compound pendulum: T = 2π√(I/mgl) = 2π√((K²/l + l)/g). Torsional pendulum: T = 2π√(I/C).

5) Spring System and Combinations

Spring constant properties, spring pendulum time period, massive spring, reduced mass, and the rules for springs in series and parallel — their effective spring constants and resulting time periods.

T = 2π√(m/k)k ∝ 1/lengthSeries: 1/k_s = 1/k₁ + 1/k₂Parallel: k_p = k₁ + k₂T_series > T_parallelMassive spring: m_eff = m + M/3
›
Spring Constant Propertiesk ∝ 1/length. If spring is cut into n equal parts: each part has constant nk. Spring constant dimensional formula [MT⁻²]. k depends on radius, length and material of wire in spring.
›
Spring Pendulum Time PeriodT = 2π√(m/k); f = (1/2π)√(k/m). T ∝ √m, T ∝ 1/√k. Independent of g — spring clock keeps correct time on moon, in satellite, inside liquid (if damping neglected).
›
Massive Spring and Reduced MassMassive spring (mass M): m_eff = m + M/3. Reduced mass for two masses: 1/m_r = 1/m₁ + 1/m₂.
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Series CombinationEqual forces act, different extensions. 1/k_s = 1/k₁ + 1/k₂ ⇒ k_s = k₁k₂/(k₁+k₂). T_series = 2π√(m(k₁+k₂)/k₁k₂) = √(T₁²+T₂²).
›
Parallel CombinationDifferent forces act, equal displacement. k_p = k₁ + k₂. T_parallel = 2π√(m/(k₁+k₂)) = T₁T₂/√(T₁²+T₂²). T_parallel < T_series (stiffer effective spring).

6) Damped, Forced Oscillations and Resonance

Free oscillations (natural frequency), exponentially decaying amplitude in damped oscillations, forced oscillations under an external periodic force, and resonance — when driving frequency equals natural frequency resulting in maximum amplitude.

Damping force F_d = −bvAmplitude ∝ e^(−bt/2m)Resonance: ω_d = ω₀Forced oscillationEnergy resonanceLissajous figures
›
Free OscillationsOscillation at natural frequency under restoring force alone. Amplitude, frequency and energy remain constant.
›
Damped OscillationsAmplitude decreases exponentially: x = x_m e^(−bt/2m) sin(ω't + φ). Damped ω' = √(ω₀² − (b/2m)²). Energy: E = ½Kx_m² e^(−bt/m).
›
Forced OscillationsExternal driving force F(t) = F₀cosω_d t. Amplitude: x₀ = (F₀/m)/√((ω₀²−ω_d²)² + (bω_d/m)²). Oscillator frequency locks to ω_d.
›
ResonanceWhen ω_d = ω₀: amplitude and power absorption are maximum. Sharpness depends on damping. Energy resonance: at ω_d = ω₀, driven oscillator absorbs maximum KE; velocity is in phase with driving force.
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Lissajous FiguresTwo perpendicular SHMs → resultant paths: straight line (φ=0°), ellipse, or circle (φ=90°, a₁=a₂). General equation: x²/a₁² + y²/a₂² − 2xy cosφ/(a₁a₂) = sin²φ.

Simple Harmonic Motion Download Notes & Weightage Plan

For each topic in the Simple Harmonic Motion chapter below, you get (2) the exact resources to download and how to use them, and (3) a simple importance & time plan so NEET students know what to do first and what to revise last.

2 Downloads

Periodic Motion and SHM Definition

Establishing what SHM is and the language used to describe it — restoring force, time period, frequency, angular frequency and phase.

F = −kxω = 2πnPhase θ = ωt + φ₀Same/Opposite PhaseHarmonic vs Non-Harmonic

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)SHM: F = −kx; k in N/m, [MT⁻²]. Periodic motion repeats after T. Oscillatory: to-and-fro about mean. SHM is periodic but not vice versa. Harmonic: single sine/cosine; non-harmonic: sum thereof. ω = 2πn (rad/s). Phase = ωt + φ₀; φ₀ = epoch. Same phase: Δφ = 2nπ (or path diff = nλ). Opposite phase: Δφ = (2n+1)π. Time period independent of amplitude in SHM.
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Write the definition of SHM in one formula (F = −kx) and state the three consequences: (i) acceleration ∝ −displacement, (ii) time period independent of amplitude, (iii) motion expressible as sine/cosine. Do 5 identification MCQs on 'which of the following is SHM?'

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions0-1Conceptual — identification of SHM from description, or phase difference calculation.
Time Required1 hr30 min theory + 30 min MCQs on phase and SHM identification.
DifficultyEasyDefinitional — no calculation. Traps only arise in same- vs opposite-phase questions.
  • Scoring Focus: All SHM is periodic but not all periodic is SHM. Same phase: Δφ = even multiple of π; opposite: odd multiple.
  • High-risk Area: Confusing 'same phase' (Δφ = 2π, path diff = λ) with 'in step' vs 'opposite phase' (Δφ = π, path diff = λ/2).
  • Best Practice Style: Assertion-reason and statement-based conceptual MCQs.
Priority rule: Cover first — all subsequent topics build on the language here.

Displacement, Velocity and Acceleration in SHM

The three kinematic quantities as functions of time and position, with their extreme values, phase relationships and graphical features.

x = a sinωtv = ω√(a²−x²)a = −ω²xv-x ellipsea-x straight linePhase leads

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)x = a sinωt (from mean) or a cosωt (from extreme). v = aω cosωt = ω√(a²−x²). At x=0: v_max = aω; at x=±a: v = 0. a = −ω²x. At x=±a: a_max = ω²a; at x=0: a = 0. Velocity leads displacement by π/2; acceleration leads velocity by π/2; acceleration is π ahead of displacement. v-x graph: ellipse (v²/(aω)² + x²/a² = 1), circle if ω=1. a-x graph: straight line, slope = −ω².
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Start from x = a sinωt, differentiate once for v, twice for a. Then verify all extreme values and phase leads. Practise 10 numericals: given x (or position) find v and a. Draw both the ellipse (v vs x) and the straight line (a vs x) from memory.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1-2Numerical: given A, ω (or T), find v at a specific x; or find x when v is a given fraction of v_max. One of the most common SHM question types in NEET.
Time Required2 hrs45 min derivations + 1.25 hrs numericals (at least 15 problems).
DifficultyModerateFormula substitution is straightforward; traps are in choosing sin vs cos form and forgetting to take square root of x² term.
  • Scoring Focus: v = ω√(A²−x²) is the single most tested formula in SHM. Internalise it so it can be applied in 10 seconds.
  • High-risk Area: Swapping max velocity (at mean) and max acceleration (at extreme) positions. Also: forgetting a = −ω²x while writing magnitude |a| = ω²x.
  • Best Practice Style: Direct substitution numericals; graph-interpretation questions asking where KE or velocity is maximum.
Priority rule: Highest priority — this topic alone accounts for ~30% of all SHM exam marks.

Energy in SHM

Potential and kinetic energy as functions of position; total energy as a constant; average values and special positions where KE = PE.

KE = ½mω²(A²−x²)PE = ½mω²x²TE = ½mω²A²KE = PE at x = A/√2Both vary at 2ω

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)PE = ½mω²y². KE = ½mω²(a²−y²). TE = ½mω²a² = constant. Both KE and PE vary at double the SHM frequency. At y = ±a/√2: KE = PE = E/2. At y = ±a/2: PE = E/4, KE = 3E/4. Average KE = Average PE = E/2 = ¼mω²a². TE ∝ a² (doubles if amplitude √2 times). TE ∝ ω² (doubles if ω √2 times).
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Draw the energy-position graph from memory (inverted parabola for KE, upright parabola for PE, horizontal line for TE). Mark x = 0, ±a/2, ±a/√2, ±a on x-axis with the exact energy fractions. Solve 8 energy MCQs.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One energy question per NEET paper is standard: 'KE equals PE at what displacement?', 'energy stored when amplitude changes', etc.
Time Required1.5 hrs45 min notes + 45 min problems on energy at specific positions.
DifficultyEasy-ModerateFormulae are simple; the trap is in the average energy question and the double-frequency of PE/KE.
  • Scoring Focus: KE = PE at y = a/√2 (not a/2). Average KE = Average PE = E/2. TE ∝ a².
  • High-risk Area: Students write 'KE = PE at y = a/2' — the correct answer is y = a/√2. Also: energy varies at 2ω not ω.
  • Best Practice Style: Graph-reading MCQs; calculation of displacement when given KE = (3/4)TE or similar.
Priority rule: High priority — energy questions are almost guaranteed in NEET SHM.

Simple Pendulum

Time period derivation, factors that change or do not change T, and special pendulum situations tested in NEET.

T = 2π√(l/g)Independent of massT ∝ √l, T ∝ 1/√gLift problemsSecond's pendulumCompound pendulum

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)T = 2π√(l/g); independent of mass and amplitude (for small θ). T ∝ √l: girl stands → l decreases → T decreases. T ∝ 1/√g: higher altitude/mine → g decreases → T increases → clock slows. Temperature rise: l = l₀(1+αΔθ) → ΔT/T ≈ ½αΔθ. Lift: g_eff = g±a; free-fall: T = ∞. Liquid (σ<ρ): g_eff = g(1−σ/ρ) → T increases. Second's pendulum: T = 2 s, l ≈ 99.3 cm. Infinite length: T_max ≈ 84.6 min. Compound: T = 2π√(I/mgl).
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Make a one-page table: Situation → g_eff → T change → clock behavior (fast/slow). Cover lift (4 cases), altitude, temperature, liquid, electric field. Practice 10 pendulum MCQs.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One pendulum question per NEET — most commonly on lift scenario or g-change effect on clock behavior ('clock runs fast/slow').
Time Required2 hrs1 hr reading the factor table + 1 hr solving scenario-based MCQs.
DifficultyModerateDerivation is standard; the difficulty is in the many special cases (lift, electric field, liquid medium).
  • Scoring Focus: Pendulum in lift: 4 cases (rest/uniform, accelerating up, accelerating down, free-fall). Clock behavior: if T increases → clock runs slow.
  • High-risk Area: Reversing behavior when lift accelerates down vs free-falls. Also: forgetting that mass independence extends even to hollow spheres filled with water.
  • Best Practice Style: Situation-based MCQs: 'A pendulum is taken to the moon — what happens to its time period?'
Priority rule: High priority — pendulum appears in nearly every NEET paper.

Spring System and Combinations

Spring constant rules, spring pendulum time period, and the critical formula rules for series and parallel spring combinations.

T = 2π√(m/k)k ∝ 1/lengthSeries k_s = k₁k₂/(k₁+k₂)Parallel k_p = k₁+k₂T_series = √(T₁²+T₂²)T_parallel = T₁T₂/√(T₁²+T₂²)

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)k ∝ 1/length → halve spring → k doubles. Spring cut into n parts: each part = nk. n parts in parallel: k_eff = n²k, T = T₀/n. Spring T = 2π√(m/k); independent of g. Massive spring: m_eff = m + M/3. Reduced mass for two-body system: 1/m_r = 1/m₁ + 1/m₂. Series: 1/k_s = 1/k₁ + 1/k₂; T_series = √(T₁²+T₂²). Parallel: k_p = k₁+k₂; T_parallel = T₁T₂/√(T₁²+T₂²). T_parallel < T_series always.
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Do at least 10 spring combination problems — including a spring-cut problem and a two-mass reduced-mass problem. Verify T_series > T_parallel with a numerical example (k₁ = k₂ = k gives T_series = T√2, T_parallel = T/√2).

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1Spring combination or spring-cut problem appears in most NEET physics papers. Two masses on a spring is an emerging trend.
Time Required1.5 hrs30 min spring rules + 1 hr problems on combinations and cutting.
DifficultyModerateSeries/parallel rules are analogous to resistors (parallel) and capacitors (series) — remember that the analogy is reversed.
  • Scoring Focus: T_series = √(T₁²+T₂²) is frequently directly tested. Also: spring constant of each piece when spring is cut.
  • High-risk Area: Using capacitor analogy for springs — spring series formula looks like resistor parallel (1/k_s = Σ1/kᵢ), not like capacitor series.
  • Best Practice Style: Computation MCQs with two specific spring constants; also spring-cutting problems.
Priority rule: High priority — appears in most NEET papers and is directly calculable.

Damped, Forced Oscillations and Resonance

Qualitative and semi-quantitative understanding of how oscillations lose energy, respond to external driving forces, and achieve maximum amplitude at resonance.

Amplitude ∝ e^(−bt/2m)Resonance: ω_d = ω₀Forced oscillation frequency = driving frequencyEnergy resonanceMaintained oscillation

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Free oscillation: natural frequency, constant amplitude. Damped: amplitude x = x_m e^(−bt/2m), energy E = ½Kx_m² e^(−bt/m). Forced: amplitude x₀ = (F₀/m)/√((ω₀²−ω_d²)²+(bω_d/m)²). Resonance: ω_d = ω₀ → maximum amplitude (finite due to damping), maximum power absorption. At resonance: velocity in phase with driving force. Maintained oscillation compensates energy loss from external source. Lissajous figures: two perpendicular SHMs; φ=0→line, φ=π/2 & a₁=a₂→circle, general→ellipse.
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Draw the resonance curve (amplitude vs ω_d) showing peak at ω₀ for different damping values. Note: larger damping → broader, lower peak. Memorise the four oscillation types (free/damped/forced/maintained) with one-line definitions.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions0-1Conceptual questions on resonance conditions, or identification of oscillation type. Sometimes a Lissajous figure shape question.
Time Required1 hr45 min reading + 15 min MCQs.
DifficultyEasyMostly conceptual — no complex numericals on damped oscillations in NEET.
  • Scoring Focus: Resonance condition (ω_d = ω₀), effect of damping on resonance amplitude, Lissajous figures shapes.
  • High-risk Area: Confusing 'amplitude resonance' (maximum displacement) with 'energy/velocity resonance' (maximum power absorption, velocity in phase with force).
  • Best Practice Style: Conceptual MCQs and assertion-based questions on damping effects.
Priority rule: Medium priority — one conceptual question possible; skip numerical details of damping equations.

Simple Harmonic Motion Chapter NEET Traps & Common Mistakes (Topic-Wise)

Each subtopic below is of the Simple Harmonic Motion chapter and shows what NEET students usually do wrong in NEET examination, a short example of the mistake, and how NEET frames the question to trick you with close options are given below.

! Avoid Easy Negatives
Velocity Maximum Position
VelocityAccelerationMean PositionExtreme PositionCommon Misconception

Mistake Snapshot (What Students Do Wrong)

  • Max v at extreme, max a at mean: Students swap the two: velocity is maximum at the mean position (x=0) where acceleration = 0, and acceleration is maximum at the extreme (x=±A) where velocity = 0.
  • Both max at same point: Some students think v and a peak at the same instant — they actually peak a quarter-cycle (T/4) apart.
2–3 Line Example (Typical Error)

In a spring-mass system with A = 10 cm and ω = 5 rad/s: at x = 0, v = 50 cm/s (max) and a = 0; at x = 10 cm, v = 0 and a = 250 cm/s² (max).

How NEET Frames The Trap

NEET questions often ask 'at what position is kinetic energy maximum?' or 'where is restoring force zero?' — both answers are mean position, but students pick extreme position.

NEET-Style Trap Question Format

Q. A particle executing SHM has amplitude A and angular frequency ω. The acceleration of the particle is maximum at:
A. Mean position (x = 0)   B. Extreme position (x = ±A)   C. x = A/2   D. x = A/√2  
Trick: a = −ω²x: acceleration is maximum when x is maximum, i.e., at the extreme position x = ±A. Velocity is maximum at x = 0.

Quick rule: v_max at x = 0 (mean); a_max at x = ±A (extreme). KE max at mean; PE max at extreme. They are π/2 out of phase with each other.
KE equals PE Displacement
EnergyKE = PEDisplacementOff-by-√2 Error

Mistake Snapshot (What Students Do Wrong)

  • KE = PE at y = A/2: The most common wrong answer — students halve the amplitude. The correct answer is y = A/√2 ≈ 0.707A.
  • Setting KE = ½E instead of KE = PE: Correct approach: ½mω²(A²−y²) = ½mω²y² ⇒ A² − y² = y² ⇒ y = A/√2.
2–3 Line Example (Typical Error)

If A = 10 cm: KE = PE when y = 10/√2 ≈ 7.07 cm, NOT at y = 5 cm.

How NEET Frames The Trap

NEET options typically include both A/2 and A/√2 — the A/2 option is placed first to trap students who guess by symmetry.

NEET-Style Trap Question Format

Q. At what displacement from the mean position is the kinetic energy equal to the potential energy in SHM?
A. A/4   B. A/2   C. A/√2   D. A√2  
Trick: Set KE = PE: ½mω²(A²−y²) = ½mω²y² ⇒ y² = A²/2 ⇒ y = A/√2. Option (b) A/2 is the classic trap.

Quick rule: KE = PE at y = A/√2. Remember: √2 not 2 in denominator.
Time Period of Spring Pendulum — Effect of g
SpringTime PeriodGravity IndependenceMoonSatellite

Mistake Snapshot (What Students Do Wrong)

  • Spring clock slows on moon: T = 2π√(m/k) has no g. A spring pendulum clock keeps the same time on moon, on a hill, in a satellite — unlike a simple pendulum.
  • Confusing spring pendulum with simple pendulum: T_simple pendulum = 2π√(l/g) depends on g. T_spring = 2π√(m/k) does NOT depend on g. These two cannot be treated identically.
2–3 Line Example (Typical Error)

A spring-mass clock on the moon: g_moon = g/6, but T = 2π√(m/k) unchanged. Contrast: simple pendulum clock on moon has T' = √6 × T_Earth and runs 2.45× slower.

How NEET Frames The Trap

Questions give scenario 'on the moon' or 'in a satellite' and ask about time period — the correct answer is 'remains the same' for spring, 'increases' for simple pendulum.

NEET-Style Trap Question Format

Q. A clock based on a spring-mass oscillator is taken to the moon where g is one-sixth of that on Earth. The time period of the spring clock will:
A. Increase by a factor of √6   B. Decrease by a factor of √6   C. Remain the same   D. Become infinite  
Trick: T = 2π√(m/k) — g does not appear. Time period remains unchanged. Only simple pendulum (T = 2π√(l/g)) changes with g.

Quick rule: Spring clock: independent of g. Simple pendulum clock: depends on g. On moon, spring clock → same; pendulum clock → runs slower.
Series vs Parallel Spring Combination
Spring CombinationsSeriesParallelTime Period Comparison

Mistake Snapshot (What Students Do Wrong)

  • Series spring formula confused with parallel: Series springs: 1/k_s = 1/k₁ + 1/k₂ (softer, longer T). Parallel springs: k_p = k₁+k₂ (stiffer, shorter T). Students often reverse the two.
  • Using resistor analogy directly: Springs in series behave like resistors in parallel (1/k_s = Σ1/kᵢ). Springs in parallel behave like resistors in series (k_p = Σkᵢ). The analogy is reversed.
2–3 Line Example (Typical Error)

k₁ = k₂ = k: in series k_s = k/2, T_series = 2π√(2m/k) = √2 × T₀; in parallel k_p = 2k, T_parallel = 2π√(m/2k) = T₀/√2. T_series is always greater.

How NEET Frames The Trap

NEET presents 'compare T_series and T_parallel' — a common wrong answer is T_series < T_parallel (confusing which combination is stiffer).

NEET-Style Trap Question Format

Q. A mass m is attached to two springs of spring constants k₁ and k₂ separately, giving time periods T₁ and T₂. If the springs are connected in series, the time period is:
A. T₁ + T₂   B. √(T₁² + T₂²)   C. T₁T₂/√(T₁²+T₂²)   D. (T₁+T₂)/2  
Trick: T_series = √(T₁²+T₂²). This is derived from 1/k_s = 1/k₁+1/k₂ and T ∝ 1/√k. Option (c) is T_parallel — the classic confusion.

Quick rule: Series: T = √(T₁²+T₂²). Parallel: T = T₁T₂/√(T₁²+T₂²). Series T is always larger (softer spring).

Topics

Periodic and Oscillatory Motion

Simple Harmonic Motion Fundamentals

Displacement in S.H.M.

Important Definitions in S.H.M.

Velocity in S.H.M.

Acceleration in S.H.M.

Average Value of PE and KE

Comparative Study of Displacement, Velocity and Acceleration

Differential Equation of S.H.M.

Energy in S.H.M.

Factors Affecting Time Period of Simple Pendulum

How to Find Frequency and Time Period

Simple Pendulum

Oscillations of Pendulum in Different Situations

Some Other Types of Pendulum

Spring Pendulum

Spring System

Equilibrium and Oscillation of Spring in Vertical Motion

Oscillation of Spring Combination

Various Formulae of S.H.M.

Free, Damped, Forced and Maintained Oscillations

Superposition of S.H.M.'s and Lissajous Figures

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