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Solution

NEET > Chemistry > Solutions

Unit Progress

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Overview content

Chapter Snapshot - Solution

A high-yield physical chemistry chapter covering how dissolved particles alter the physical behaviour of a solvent. Raoult's Law, colligative properties (vapour pressure lowering, boiling point elevation, freezing point depression, osmotic pressure), Van't Hoff factor for association and dissociation, ideal vs non-ideal solutions, and azeotropes are the six pillars of NEET questions from this chapter. Concentration expressions (molality, molarity, normality, mole fraction) form the calculation backbone. The chapter demands algebraic precision: most marks are lost from unit confusion between molality and molarity or from forgetting the Van't Hoff factor when the solute is an electrolyte.

āœ“ Use This To Plan Your First 2–3 Hours
Expected Questions (Typical)
Q
2-3
NEET consistently draws 2 to 3 questions from this chapter. One numerical on colligative properties (freezing point depression or osmotic pressure calculation), one on Raoult's Law or ideal/non-ideal deviation, and occasionally one on Van't Hoff factor for dissociation or association.
Time Required (Practical)
ā±
8-10 hrs
Concentration units and interconversions 1.5 hrs; Raoult's Law with ideal/non-ideal solutions 2 hrs; colligative properties derivations and numericals 3 hrs; Van't Hoff factor with association/dissociation 1.5 hrs; osmotic pressure and MCQ practice 2 hrs.
Difficulty Level
⚔
Moderate
Conceptual framework is straightforward but numerical problems demand careful unit handling. Molality uses kg of solvent while molarity uses litres of solution. Forgetting to multiply by the Van't Hoff factor i for electrolytes is the single most common scoring error.
Most Asked Style: Numerical MCQ: calculate molecular mass from depression in freezing point or osmotic pressure; find Van't Hoff factor and degree of dissociation for an electrolyte; identify positive or negative deviation from Raoult's Law; calculate relative lowering of vapour pressure from mole fraction.Biggest Trap: Using molarity instead of molality in colligative property formulas. Colligative property equations use molality (moles of solute per kg of solvent), not molarity (moles per litre of solution). NEET distractors exploit this by providing data in molarity and expecting conversion before substitution.Fast Win: Memorise these four results: relative lowering = mole fraction of solute; delta-Tb = Kb times m; delta-Tf = Kf times m; pi = cRT. For electrolytes multiply each by i. For association: i = 1 minus alpha(1 minus 1/n). For dissociation: alpha = (i minus 1)/(M minus 1). These six formulas cover 90% of numericals.Revision-Friendly: Yes. Core formulas fit on one card: Raoult's Law, four colligative expressions, Van't Hoff factor formulas for association and dissociation. A 30-minute pre-exam sweep of these plus one worked numerical per colligative property covers the full scoring range.

Subtopics - Solution (NEET)

Six topic blocks: vapour pressure fundamentals and concentration expressions, Raoult's Law with ideal and non-ideal solutions, azeotropes (minimum and maximum boiling point types), four colligative properties with derivations and molecular mass determination, osmotic pressure via Van't Hoff equation, and the Van't Hoff factor for abnormal molecular masses from association or dissociation.

Revision tip: Before solving any colligative property numerical: (1) identify whether the solute is electrolyte or non-electrolyte, (2) if electrolyte, determine Van't Hoff factor i, (3) confirm you are using molality not molarity, (4) substitute into the correct formula. This four-step check eliminates the two most common NEET errors in this chapter.
NCERT LinesMCQsQuick Test

1) Vapour Pressure

Defines vapour pressure as the equilibrium pressure exerted by vapours on the walls of a closed container at a given temperature. Vapour pressure depends only on temperature, not on the volume or surface area of the container. Covers concentration expressions: mass percentage, volume percentage, molality, molarity, normality, mole fraction, and ppm.

VP depends on T onlyMolality = mol/kg solventMolarity = mol/L solutionMole fraction sum = 1
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Concept and Properties of Vapour PressureWhen a pure liquid is in a closed evacuated vessel, dynamic equilibrium is established: Liquid equilibrium Vapours. The Kp of this equilibrium equals the vapour pressure Pv. Since Kp is a constant at a given temperature, vapour pressure depends only on temperature and is independent of container volume, shape, or liquid surface area exposed. Vapour pressure increases with temperature. Concentration expressions (molality, molarity, normality, mole fraction, mass percentage, volume percentage, ppm) and their interconversion formulas provide the calculation framework for all colligative property problems.

2) Azeotropes or Azeotropic mixture

Liquid mixtures that distil without change in composition are azeotropes (constant boiling mixtures). Two types exist: minimum boiling point azeotropes formed by solutions showing positive deviation from Raoult's Law, and maximum boiling point azeotropes formed by solutions showing negative deviation. Cannot be separated by simple distillation.

Positive deviation: min BP azeotropeNegative deviation: max BP azeotropeConstant composition on distillationCannot separate by distillation
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Minimum Boiling Point AzeotropeFormed by non-ideal solutions showing positive deviation from Raoult's Law. The boiling point of the azeotrope is lower than the boiling point of either pure component. Example: cyclohexane and ethanol mixture. Cyclohexane molecules break hydrogen bonds between ethanol molecules, reducing intermolecular attraction and increasing vapour pressure above the Raoult's Law prediction.
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Maximum Boiling Point AzeotropeFormed by solutions showing negative deviation from Raoult's Law. The boiling point is higher than that of either pure component. Examples: acetone and chloroform (hydrogen bond forms between C=O of acetone and H-CCl3), HNO3 and water. The new intermolecular interaction increases attraction, decreases vapour pressure below the Raoult's Law value, and raises the boiling point.

3) Raoult's Law

States that the partial vapour pressure of any component in a solution is directly proportional to its mole fraction: PA = XA times PA-star. Combined with Dalton's Law: PT = PB-star plus (PA-star minus PB-star) times XA. Ideal solutions obey Raoult's Law at all compositions with delta-H-mixing = 0 and delta-V-mixing = 0. Non-ideal solutions show positive deviation (VP higher than predicted, delta-H > 0) or negative deviation (VP lower than predicted, delta-H < 0).

PA = XA times PA-starIdeal: delta-H-mix = 0Positive deviation: VP > predictedNegative deviation: VP < predicted
›
Raoult's Law Statement and ApplicationFor a binary solution of liquids A and B: PA = XA times PA-star and PB = XB times PB-star, where PA-star is the vapour pressure of pure A. For pure liquid XA = 1, so K = PA-star. Total pressure from Dalton's Law: PT = PA + PB = XA times PA-star + XB times PB-star = PB-star + (PA-star minus PB-star) times XA. Ideal solutions (e.g., ethyl chloride and ethyl bromide, n-hexane and n-heptane, CCl4 and SiCl4) obey this law at all compositions with zero enthalpy and volume of mixing. Non-ideal solutions deviate: positive deviation when A-B attraction is weaker than A-A and B-B (e.g., cyclohexane-ethanol), negative deviation when A-B attraction is stronger (e.g., acetone-chloroform).

4) Colligative Properties

Properties of dilute solutions that depend only on the number of solute particles, not their identity. Four types: lowering of vapour pressure (relative lowering = mole fraction of solute), elevation in boiling point (delta-Tb = Kb times m), depression in freezing point (delta-Tf = Kf times m), and osmotic pressure. Each property enables experimental determination of solute molecular mass.

Depend on particle count onlydelta-Tb = Kb times mdelta-Tf = Kf times mMolecular mass from any CP
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Overview of Colligative PropertiesColligative properties apply only to dilute solutions behaving as ideal solutions. Assumptions: the solute is non-volatile (does not contribute to vapour) and does not dissolve in solid solvent (pure solid solvent separates on freezing). Four colligative properties: lowering of vapour pressure, elevation in boiling point, depression in freezing point, and osmotic pressure. All four are proportional to the number of solute particles in solution.
›
Lowering in vapour pressureBy Raoult's Law: P-solvent = X-solvent times P-solvent-star. Therefore X-solute = (P-zero minus P) / P-zero, which is the relative lowering of vapour pressure. The relative lowering equals the mole fraction of solute. Addition of a non-volatile solute always decreases the vapour pressure because solute molecules occupy surface sites, reducing the number of solvent molecules that can escape into the vapour phase.
›
Elevation in boiling point (Ebullioscopy)The boiling point is the temperature at which vapour pressure equals atmospheric pressure. Since a non-volatile solute lowers vapour pressure, a higher temperature is needed to reach atmospheric pressure. delta-Tb = Kb times m, where Kb is the molal boiling point elevation constant (ebullioscopic constant) in K kg/mol. Molecular mass of solute: MB = (Kb times WB times 1000) / (delta-Tb times WA), where WB = mass of solute, WA = mass of solvent in grams.
›
Depression in freezing point (cryoscopy)Freezing point is the temperature at which vapour pressures of liquid and solid phases are equal. When solution freezes, only pure solvent separates as solid, causing depression. delta-Tf = Kf times m, where Kf is the molal freezing point depression constant (cryoscopic constant). Molecular mass: MB = (Kf times WB times 1000) / (delta-Tf times WA). Kf for water = 1.86 K kg/mol. Depression in freezing point is the most commonly used colligative property for molecular mass determination in NEET problems.

5) Abnormal Molecular Mass and Van't Hoff Factor

When solutes associate or dissociate in solution, colligative properties give abnormal molecular masses. Van't Hoff factor i = observed colligative property / theoretical colligative property. For dissociating solutes i > 1 (more particles). For associating solutes i < 1 (fewer particles). Modified formulas: delta-Tb = i Kb m; delta-Tf = i Kf m; pi = icRT.

i > 1 for dissociationi < 1 for associationi = 1 minus alpha(1 minus 1/n)alpha = (i minus 1)/(M minus 1)
›
Van't Hoff Factor (i)Defined as i = observed colligative property / theoretical colligative property = actual number of particles / expected number of particles. For ideal non-associating, non-dissociating solutes: i = 1. For electrolytes that dissociate: i > 1. For solutes that associate in non-aqueous solvents: i < 1. All colligative property formulas must be multiplied by i when the solute is an electrolyte or undergoes association.
›
Association and Degree of AssociationIn non-aqueous solvents, two or more solute molecules combine to form a bigger molecule: nA equilibrium (A)n. If alpha is the degree of association, unassociated moles = 1 minus alpha, associated moles = alpha/n, total effective moles = 1 minus alpha + alpha/n. Therefore i = 1 minus alpha(1 minus 1/n), and since i < 1 the observed molecular mass is higher than the true value. Classic examples: acetic acid dimerises in benzene through hydrogen bonding; chloroacetic acid associates in naphthalene.
›
Degree of DissociationFor electrolytes dissociating in solution, the number of particles increases so i > 1. The degree of dissociation alpha = (i minus 1) / (M minus 1), where M is the number of particles produced per formula unit in solution. For NaCl: M = 2; for BaCl2: M = 3; for K3[Fe(CN)6]: M = 4. Modified colligative formulas: delta-Tb = i Kb m; delta-Tf = i Kf m; pi = icRT. Forgetting to include i for electrolyte solutes is the single most common error in NEET solution numericals.

6) Osmotic Pressure

Osmosis is the flow of solvent through a semi-permeable membrane from higher solvent concentration (pure solvent) to lower solvent concentration (solution). Osmotic pressure pi = (n/V)RT = cRT, where c is molar concentration. Preferred method for determining molecular mass of macromolecules (proteins, polymers) because osmotic pressure is measurable even for dilute macromolecular solutions where other colligative effects are too small.

pi = cRTSPM allows solvent onlyBest for macromolecule MWMB = wRT / (pi V)
›
Osmosis and Osmotic PressureOsmosis: solvent moves from a region of higher concentration (pure solvent) to lower concentration (solution) through a semi-permeable membrane that allows only solvent molecules to pass. The rising solution level creates hydrostatic pressure; at equilibrium this excessive hydrostatic pressure is the osmotic pressure pi. Van't Hoff equation: pi = (n/V)RT = cRT, where n = moles of solute, V = volume of solution in litres, R = gas constant, T = temperature in Kelvin. Molecular mass formula: MB = (w times R times T) / (pi times V). Osmotic pressure method gives the most precise molecular masses for proteins and polymers because pi is large and measurable even at high dilution where delta-Tb and delta-Tf are negligibly small.

Solution Download Notes & Weightage Plan

For each topic in the Solution chapter below, you get (2) the exact resources to download and how to use them, and (3) a simple importance & time plan so NEET students know what to do first and what to revise last.

2 Downloads

Vapour Pressure

Foundation topic: defines vapour pressure, its temperature dependence, and all concentration units (molality, molarity, normality, mole fraction, ppm) used throughout the chapter.

Prerequisite for all CP workConcentration conversions testedVP = f(T) only1-2 Q on unit conversions

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Vapour pressure: equilibrium pressure of vapours over liquid in closed vessel. Depends only on temperature. Independent of container volume, shape, or liquid surface area. Concentration units: mass % = (wt solute/wt solution) times 100; molality m = mol solute / kg solvent; molarity M = mol solute / L solution; normality N = g-equiv / L solution; mole fraction X = n/(n+N), sum of all mole fractions = 1; ppm = mass fraction times 10^6. Key interconversion: N = M times (molecular mass / equivalent mass).
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Write a quick-reference table with columns: Unit | Formula | Denominator (solvent vs solution). The critical distinction: molality denominator is kg of SOLVENT; molarity denominator is L of SOLUTION. Practise 5 conversion problems between molality, molarity, and mole fraction. Sketch the closed-vessel equilibrium diagram.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One question on concentration conversion (molarity to molality or mole fraction calculation) appears in most NEET papers. Direct vapour pressure definition is rarely tested as a standalone question.
Time Required1.5 hrs30 min theory on VP concept; 30 min on all concentration units with interconversion formulas; 30 min practising unit conversion MCQs.
DifficultyEasyConceptual and formulaic. The only challenge is keeping solvent vs solution denominators straight and not confusing molality with molarity in later colligative calculations.
  • Scoring Focus: Molality versus molarity distinction. Every concentration conversion problem uses this. Know that molality is temperature-independent (mass-based) while molarity changes with temperature (volume-based).
  • High-risk Area: Using litres of solution when the formula requires kg of solvent, or vice versa. NEET distractors are designed precisely around this confusion.
  • Best Practice Style: For every numerical, first identify whether the problem gives you solvent mass or solution volume, then pick the correct concentration unit before substituting.
Priority rule: Medium priority. Concentration conversions are the prerequisite for all colligative property numericals. Master units before moving to Raoult's Law and colligative properties.

Azeotropes or Azeotropic mixture

Constant boiling mixtures that cannot be separated by distillation; directly linked to positive and negative deviation from Raoult's Law.

Min BP = positive deviationMax BP = negative deviationConceptual MCQ onlyKnow 2-3 examples each

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Azeotropes: liquid mixtures distilling without change in composition. Two types: (1) Minimum boiling point azeotrope from positive deviation (VP > Raoult prediction, delta-H-mix > 0, delta-V-mix > 0, A-B attraction weaker than A-A/B-B; e.g. cyclohexane-ethanol). (2) Maximum boiling point azeotrope from negative deviation (VP < Raoult prediction, delta-H-mix < 0, delta-V-mix < 0, A-B attraction stronger than A-A/B-B; e.g. acetone-chloroform, HNO3-water). Azeotropes cannot be separated by simple distillation.
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Make a two-column comparison table: Positive deviation (min BP, delta-H > 0, examples) vs Negative deviation (max BP, delta-H < 0, examples). Memorise at least two examples per column. Sketch VP vs composition graphs for both deviations.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions0-1Azeotropes rarely appear as standalone NEET questions but are combined with ideal/non-ideal solution questions. When tested, the question asks to identify the type of deviation from given examples.
Time Required1 hr30 min concept with deviation types and examples; 30 min MCQ practice linking deviation to azeotrope type.
DifficultyEasyPurely conceptual recall: match deviation type to azeotrope type and know examples. No calculations involved.
  • Scoring Focus: Link the sign of delta-H-mixing to deviation type: positive delta-H means positive deviation means minimum boiling azeotrope. Negative delta-H means negative deviation means maximum boiling azeotrope.
  • High-risk Area: Confusing which deviation type gives which azeotrope. Positive deviation gives MINIMUM boiling point (not maximum) because higher VP means lower boiling point.
  • Best Practice Style: Mnemonic: Positive deviation = More VP = Less BP needed = Minimum boiling azeotrope. The chain is P-M-L-Min.
Priority rule: Low priority. Quick conceptual topic. Spend 1 hour then move to colligative properties which carry more numerical marks.

Raoult's Law

The central law of liquid-liquid solutions: PA = XA times PA-star. Combined with Dalton's Law for total vapour pressure. Defines ideal and non-ideal solutions.

PA = XA PA-starIdeal: delta-H-mix = 0Positive/negative deviation examplesCombined with Dalton's Law

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Raoult's Law: partial VP of component A in solution is proportional to its mole fraction: PA = XA times PA-star (PA-star = VP of pure A). For binary solution: PT = XA PA-star + XB PB-star = PB-star + (PA-star minus PB-star) XA. Ideal solution: obeys Raoult's Law at all compositions; delta-H-mix = 0; delta-V-mix = 0; A-A, B-B, A-B attractions similar. Examples: ethyl chloride-ethyl bromide, n-hexane-n-heptane, CCl4-SiCl4. Non-ideal: positive deviation (PA > XA PA-star; VP too high; A-B weaker), negative deviation (PA < XA PA-star; VP too low; A-B stronger).
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Write Raoult's Law equation and the combined Dalton's Law total pressure expression. Draw three graphs side by side: ideal (straight line VP vs X), positive deviation (VP above line), negative deviation (VP below line). Annotate each with sign of delta-H and delta-V.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One question testing Raoult's Law application: calculate total VP of binary mixture given mole fractions and pure component VPs, or identify positive/negative deviation from given molecular pair.
Time Required2 hrs45 min derivation of Raoult's Law and combination with Dalton's Law; 30 min ideal/non-ideal solution characteristics; 45 min MCQ practice on VP calculation and deviation identification.
DifficultyModerateThe formula is simple but applying it correctly requires keeping track of mole fractions (which must sum to 1) and remembering that positive deviation means VP is ABOVE the ideal line.
  • Scoring Focus: Total pressure calculation from mole fraction data: PT = PB-star + (PA-star minus PB-star) times XA. Know the three criteria for ideal solution: Raoult's Law obeyed, delta-H = 0, delta-V = 0.
  • High-risk Area: Forgetting that mole fractions in vapour phase differ from those in liquid phase. NEET sometimes asks for vapour-phase mole fraction using yA = PA/PT.
  • Best Practice Style: For every Raoult's Law problem: (1) write PA = XA PA-star for each component, (2) add to get PT, (3) if asked for vapour composition, calculate yA = PA/PT.
Priority rule: High priority. Raoult's Law is the foundation for all colligative property derivations. Master this before attempting colligative property numericals.

Colligative Properties

Four solution properties depending only on solute particle count: relative lowering of VP, elevation in boiling point, depression in freezing point. Each with molecular mass determination formula.

VP lowering = X-solutedelta-Tb = Kb mdelta-Tf = Kf mMW from any CP formula

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Four colligative properties: (1) Relative lowering of VP: (P-zero minus P)/P-zero = X-solute. (2) Elevation in BP: delta-Tb = Kb times m; Kb = molal elevation constant (ebullioscopic constant); MB = (Kb times WB times 1000)/(delta-Tb times WA). (3) Depression in FP: delta-Tf = Kf times m; Kf = molal depression constant (cryoscopic constant, Kf for water = 1.86 K kg/mol); MB = (Kf times WB times 1000)/(delta-Tf times WA). (4) Osmotic pressure (covered separately). All assume non-volatile solute, dilute solution behaving ideally, pure solid solvent separates on freezing.
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Write all four formulas in a 2x2 grid. For each, note: what is measured, what constant is used, and the molecular mass expression. Solve one numerical for each property type. The molecular mass formula MB = (K times WB times 1000)/(delta-T times WA) is structurally identical for both Kb and Kf; only the constant and the direction of T-change differ.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1-2One to two numericals per NEET paper. Depression in freezing point and osmotic pressure are the most frequently tested. Molecular mass determination from given delta-Tf or pi data is the dominant format.
Time Required3 hrs1 hr on VP lowering and boiling point elevation with derivations; 1 hr on freezing point depression with Kf values and worked examples; 1 hr MCQ practice on molecular mass calculations.
DifficultyModerateThe formulas are straightforward but careful unit management is needed. WA must be in grams (the 1000 factor converts to kg). Mixing up Kb and Kf values or forgetting the 1000 multiplier leads to wrong molecular mass by a factor of 1000.
  • Scoring Focus: Molecular mass determination: MB = (K times WB times 1000)/(delta-T times WA). Whether using Kb or Kf, the formula structure is identical. Depression in freezing point problems dominate because Kf for water is a standard given value (1.86 K kg/mol).
  • High-risk Area: The 1000 factor in the MW formula accounts for converting WA from grams to kilograms. Omitting it gives molecular mass off by three orders of magnitude. Also, delta-T is always positive (magnitude of temperature change).
  • Best Practice Style: Always write the full formula with units. Confirm that WA is in grams and the factor 1000 is present. Cross-check: if MW comes out in thousands for a simple organic solute, you probably dropped the 1000.
Priority rule: Highest priority. This topic alone carries 1 to 2 guaranteed NEET questions. Depression in freezing point and molecular mass determination must be thoroughly practised before the exam.

Abnormal Molecular Mass and Van't Hoff Factor

Explains why electrolytes and associating solutes give abnormal colligative effects. Van't Hoff factor i corrects all four colligative property formulas.

i = observed/theoretical CPDissociation: i > 1Association: i < 1alpha from i formula

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Van't Hoff factor: i = observed CP / theoretical CP = actual particles / expected particles. For non-electrolyte: i = 1. Dissociation (electrolyte in water): i > 1. Association (organic in non-aqueous solvent): i < 1. Association formula: nA equilibrium (A)n; total moles = 1 minus alpha + alpha/n; i = 1 minus alpha(1 minus 1/n). Dissociation: alpha = (i minus 1)/(M minus 1), M = ions per formula unit. Modified formulas: delta-Tb = iKbm; delta-Tf = iKfm; pi = icRT; relative VP lowering = i times X-solute.
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Make a table: NaCl (i=2, M=2), CaCl2 (i=3, M=3), BaCl2 (i=3, M=3), K3[Fe(CN)6] (i=4, M=4) for full dissociation. For acetic acid in benzene: n=2, dimerisation. Solve one numerical each for dissociation and association. The key formula pair: association i = 1 minus alpha(1 minus 1/n); dissociation alpha = (i minus 1)/(M minus 1).

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One question per paper on Van't Hoff factor: either calculating degree of dissociation from observed colligative property, or determining which electrolyte gives highest osmotic pressure based on i value.
Time Required1.5 hrs30 min theory on why molecular masses are abnormal; 30 min association and dissociation formulas with derivation; 30 min MCQ practice.
DifficultyModerateThe formulas are compact but require clear thinking about whether the solute dissociates or associates. The biggest conceptual pitfall: confusing M (number of particles produced) with molecular mass.
  • Scoring Focus: Quick calculation of i for common electrolytes (NaCl = 2, BaCl2 = 3, AlCl3 = 4 at full dissociation) and using i in the modified colligative formula. NEET asks: which solution has highest osmotic pressure given equimolar NaCl, glucose, BaCl2 - answer is BaCl2 because i = 3 is highest.
  • High-risk Area: Using M (number of ions produced per formula unit) and confusing it with molar mass. In the dissociation formula alpha = (i minus 1)/(M minus 1), M is the count of particles from one formula unit, NOT the molar mass in g/mol.
  • Best Practice Style: Before substituting into any Van't Hoff formula, first write the dissociation equation and count the number of ions produced. That count is M. Then i = 1 + alpha(M minus 1) for dissociation.
Priority rule: High priority. Van't Hoff factor is tested every year in combination with colligative properties. Master the dissociation formula and memorise i values for NaCl, CaCl2, BaCl2, K3[Fe(CN)6].

Osmotic Pressure

Osmosis through semi-permeable membranes and the Van't Hoff equation pi = cRT. Preferred for macromolecular mass determination.

pi = cRTSPM: solvent onlyBest for proteins/polymersMB = wRT/(pi V)

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Osmosis: solvent flows from pure solvent side to solution side through SPM. At equilibrium, hydrostatic pressure = osmotic pressure pi. Van't Hoff equation: pi = (n/V)RT = cRT. Molecular mass: MB = (w times R times T)/(pi times V). For electrolytes: pi = icRT. Osmotic pressure method is preferred for macromolecules (proteins, polymers, colloids) because pi is measurably large even at high dilution where delta-Tb and delta-Tf are negligibly small. Berkeley and Hartley method is the most accurate experimental technique for measuring osmotic pressure.
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Memorise pi = cRT as structurally identical to PV = nRT. The molecular mass formula MB = wRT/(pi V) follows directly. Practise 3 numericals: one with non-electrolyte (glucose/urea), one with electrolyte (NaCl with i), one macromolecule (protein with large MW). Note R = 0.0821 L atm/(mol K) or 8.314 J/(mol K) depending on units of pi.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One numerical on osmotic pressure calculation or molecular mass from osmotic pressure data. NEET sometimes asks which colligative property is best for determining molar mass of proteins (answer: osmotic pressure).
Time Required1.5 hrs30 min on osmosis concept and SPM; 30 min on Van't Hoff equation and molecular mass formula; 30 min MCQ practice with unit conversions.
DifficultyEasy-ModerateThe formula is a direct analogue of the ideal gas equation. The challenge is unit consistency: pressure in atm requires R = 0.0821, volume in litres, temperature in K.
  • Scoring Focus: Two scoring points: (1) pi = cRT numerical with given concentration and temperature, (2) conceptual question on why osmotic pressure is preferred for macromolecular mass determination (answer: other CPs are too small to measure).
  • High-risk Area: Unit mismatch: if pi is in bar, use R = 0.083 L bar/(mol K); if in atm, use R = 0.0821 L atm/(mol K). Using the wrong R value gives wrong molecular mass. Also, V must be in litres, not mL.
  • Best Practice Style: Write pi = cRT with units explicitly. Circle the units of pressure and match R accordingly. Convert V to litres and T to Kelvin before substituting.
Priority rule: High priority. Osmotic pressure numericals are among the most frequently tested colligative property questions in NEET. The formula is simple but unit errors are common.

Solution Chapter NEET Traps & Common Mistakes (Topic-Wise)

Each subtopic below is of the Solution chapter and shows what NEET students usually do wrong in NEET examination, a short example of the mistake, and how NEET frames the question to trick you with close options are given below.

! Avoid Easy Negatives
Colligative Properties and Molality
NEETFreezing pointBoiling pointMolality vs Molarity

Mistake Snapshot (What Students Do Wrong)

  • Using molarity instead of molality in colligative property formulas: Colligative property equations use molality (mol solute / kg solvent). NEET provides data as molarity or mass in solution volume. Substituting molarity directly into delta-Tf = Kf times m gives a wrong answer because molarity uses litres of solution, not kg of solvent.
  • Dropping the factor 1000 in molecular mass formula: The formula MB = (Kf times WB times 1000) / (delta-Tf times WA) requires WA in grams. The 1000 converts grams to kilograms. Omitting it gives molecular mass exactly 1000 times too small, which NEET places as a distractor.
2–3 Line Example (Typical Error)

A solution contains 6 g of urea (MW = 60) in 500 g of water. Correct molality = (6/60) / (500/1000) = 0.2 m. If you mistakenly use 500 mL of solution as denominator for molarity, you get 0.2 M which happens to match here but fails when density is not 1 g/mL. For a sugar solution with density 1.2 g/mL, the error produces a 20% deviation.

How NEET Frames The Trap

NEET gives solute mass and solvent mass in grams. You must convert solvent mass to kg (divide by 1000) to get molality. Distractors are calculated using solution volume or omitting the 1000 factor.

NEET-Style Trap Question Format

Q. What is the depression in freezing point when 3 g of urea (MW = 60) is dissolved in 500 g of water? (Kf = 1.86 K kg/mol)
A. 0.186 K   B. 1.86 K   C. 0.0186 K   D. 18.6 K  
Trick: m = (3/60) / (500/1000) = 0.1 mol/kg. delta-Tf = 1.86 times 0.1 = 0.186 K (Option A). Option B (1.86) uses m = 1 by forgetting to divide mass by MW. Option C (0.0186) forgets to convert 500 g to 0.5 kg, using 5 instead of 0.5. Option D (18.6) multiplies instead of dividing.

Quick rule: Colligative formulas always use MOLALITY. Molality denominator is kg of SOLVENT, not litres of solution. Three-step check: mass of solute divided by MW gives moles; mass of solvent in grams divided by 1000 gives kg; moles divided by kg gives molality.
Van't Hoff Factor for Electrolytes
NEETVan't Hoff factorDissociationOsmotic pressure

Mistake Snapshot (What Students Do Wrong)

  • Forgetting to multiply by i for electrolyte solutes: For electrolytes like NaCl (i = 2), BaCl2 (i = 3), the colligative property formulas must include i: delta-Tf = iKfm, pi = icRT. Using the non-electrolyte formula gives the theoretical value, not the observed value. NEET distractors are computed without i.
  • Confusing M (ion count) with molecular mass in the dissociation formula: In alpha = (i minus 1) / (M minus 1), M is the number of particles produced per formula unit on complete dissociation, NOT the molar mass. For NaCl, M = 2 (one Na-plus and one Cl-minus). Plugging in molar mass 58.5 instead of 2 gives an absurdly small alpha.
2–3 Line Example (Typical Error)

Osmotic pressure of 0.1 M NaCl at 300K. Without i: pi = 0.1 times 0.0821 times 300 = 2.463 atm. With i = 2: pi = 2 times 2.463 = 4.926 atm. NEET provides 2.463 atm as a distractor (no i correction). Students who forget NaCl is an electrolyte pick the distractor.

How NEET Frames The Trap

NEET identifies the solute as an electrolyte (NaCl, CaCl2, etc.) in the problem. If student does not recognise it as an electrolyte or forgets to apply i, they calculate the non-electrolyte answer which is always one of the four options.

NEET-Style Trap Question Format

Q. Which 0.1 M aqueous solution will show the highest osmotic pressure at 25 degrees C?
A. Glucose   B. NaCl   C. BaCl2   D. Urea  
Trick: Osmotic pressure pi = icRT. For glucose (i=1): pi = 0.1RT. For NaCl (i=2): pi = 0.2RT. For BaCl2 (i=3): pi = 0.3RT. For urea (i=1): pi = 0.1RT. BaCl2 has highest i = 3, so highest pi. Students who ignore i pick glucose or urea (same pi) and miss BaCl2.

Quick rule: See an ionic compound as solute? Multiply the colligative property by i. Count the ions: NaCl gives 2 ions (i=2), CaCl2 gives 3 (i=3), AlCl3 gives 4 (i=4), K3[Fe(CN)6] gives 4 (i=4). Non-electrolytes (glucose, urea, sucrose): i = 1.
Raoult's Law and Ideal vs Non-ideal Solutions
NEETRaoult's LawPositive deviationNegative deviationAzeotropes

Mistake Snapshot (What Students Do Wrong)

  • Confusing which deviation gives which azeotrope type: Positive deviation (VP higher than Raoult prediction) gives MINIMUM boiling point azeotrope. Negative deviation (VP lower) gives MAXIMUM boiling point azeotrope. Students reverse this because positive sounds like it should go with maximum.
  • Mixing up liquid-phase and vapour-phase mole fractions: Raoult's Law PA = XA PA-star uses liquid-phase mole fraction XA. The vapour-phase mole fraction yA = PA / PT is different from XA. NEET asks for vapour composition which requires the extra step of dividing PA by PT.
2–3 Line Example (Typical Error)

A mixture of A (PA-star = 300 torr) and B (PB-star = 100 torr) with XA = 0.4. PA = 0.4 times 300 = 120 torr; PB = 0.6 times 100 = 60 torr; PT = 180 torr. Vapour mole fraction of A: yA = 120/180 = 0.667 (NOT 0.4). Students who report XA = 0.4 as vapour mole fraction lose the mark.

How NEET Frames The Trap

NEET asks for the mole fraction of component A in the VAPOUR phase above an ideal solution. Students who do not distinguish liquid-phase XA from vapour-phase yA give the wrong answer by reporting XA directly.

NEET-Style Trap Question Format

Q. An ideal solution contains A (PA-star = 400 mmHg) and B (PB-star = 200 mmHg). If XA = 0.3, what is the total vapour pressure?
A. 260 mmHg   B. 300 mmHg   C. 200 mmHg   D. 400 mmHg  
Trick: PT = XA PA-star + XB PB-star = 0.3(400) + 0.7(200) = 120 + 140 = 260 mmHg (Option A). Option B (300) is the arithmetic mean of 400 and 200, ignoring mole fractions. Option C and D are the pure component VPs.

Quick rule: For ideal binary solution: PT = XA PA-star + XB PB-star. For vapour composition: yA = PA / PT. Positive deviation means VP above Raoult's line, so lower BP needed to boil, so minimum BP azeotrope. Negative deviation is the reverse.
Osmotic Pressure and Macromolecular Mass
NEETOsmotic pressureProteinUnit mismatchR value

Mistake Snapshot (What Students Do Wrong)

  • Using wrong value of R for given pressure units: If osmotic pressure is in atm, R = 0.0821 L atm / (mol K). If in bar, R = 0.083 L bar / (mol K). Using the wrong R value gives molecular mass off by approximately 1.3%. NEET distractors are spaced to catch this error.
  • Substituting volume in mL instead of litres: In pi = (n/V)RT, V must be in litres. Substituting 200 mL instead of 0.2 L makes pi 1000 times too small or MW 1000 times too large. This is the most common careless error in osmotic pressure numericals.
2–3 Line Example (Typical Error)

1.26 g protein in 200 mL solution at 300 K gives pi = 2.57 times 10 to the power minus 3 bar. MB = (1.26 times 0.083 times 300) / (2.57E-3 times 0.200) = 31.374 / 5.14E-4 = 61038 g/mol. If V = 200 (not 0.200 L), MB = 61.038 g/mol, which is absurdly small for a protein. NEET places this as a distractor.

How NEET Frames The Trap

NEET gives volume in mL and pressure in bar or atm. The student must convert mL to L and match R to the pressure unit before substituting. Both conversions are tested simultaneously.

NEET-Style Trap Question Format

Q. 200 mL of an aqueous protein solution (1.26 g) at 300 K has osmotic pressure 2.57 x 10^-3 bar. What is the molar mass? (R = 0.083 L bar / mol K)
A. 61038 g/mol   B. 61.038 g/mol   C. 31011 g/mol   D. 122044 g/mol  
Trick: MB = wRT / (pi V) = (1.26 x 0.083 x 300) / (2.57E-3 x 0.200) = 61038 g/mol (Option A). Option B (61.038) uses V = 200 instead of 0.2 L. Option C halves the result (wrong factor). Option D doubles it.

Quick rule: Always convert mL to L before substituting into pi = cRT. Match R units to pressure units: atm uses 0.0821, bar uses 0.083, Pa uses 8.314. If you get a protein MW under 1000 or over 10 million, recheck your unit conversions.
Association in Non-Aqueous Solvents
NEETAssociationAcetic acid in benzeneVan't Hoff factorAbnormal MW

Mistake Snapshot (What Students Do Wrong)

  • Calculating i > 1 for associating solutes instead of i < 1: Association reduces the number of particles (molecules combine). Therefore i < 1 and observed molecular mass is HIGHER than expected. Students who confuse association with dissociation calculate i > 1, giving a MW lower than expected.
  • Using aqueous dissociation formula for non-aqueous association: The formula alpha = (i minus 1)/(M minus 1) is for dissociation. For association: i = 1 minus alpha(1 minus 1/n), where n is the number of molecules combining. Using the wrong formula gives a negative alpha, which is physically meaningless.
2–3 Line Example (Typical Error)

Acetic acid (MW = 60) dimerises in benzene (n = 2). If observed MW = 100: i = expected MW / observed MW = 60/100 = 0.6. From i = 1 minus alpha(1 minus 1/2): 0.6 = 1 minus 0.5 alpha, so alpha = 0.8 (80% association). If student uses dissociation formula: alpha = (0.6 minus 1)/(2 minus 1) = minus 0.4, which is nonsensical.

How NEET Frames The Trap

NEET specifies the solvent is benzene or another non-aqueous solvent and the solute is an organic acid. This is the association signal. The observed MW will be higher than the true MW, and i < 1.

NEET-Style Trap Question Format

Q. Acetic acid (MW = 60) forms a dimer in benzene. If the degree of association is 0.8, what is the Van't Hoff factor?
A. 0.6   B. 1.4   C. 1.8   D. 2.0  
Trick: i = 1 minus alpha(1 minus 1/n) = 1 minus 0.8(1 minus 0.5) = 1 minus 0.4 = 0.6 (Option A). Option B (1.4) uses the dissociation formula i = 1 + alpha(n minus 1) = 1 + 0.8(1) = 1.8 (which matches C). Students who forget association gives i < 1 will pick B or C.

Quick rule: Association: i < 1, observed MW > true MW, happens in non-aqueous solvents (benzene, naphthalene). Dissociation: i > 1, observed MW < true MW, happens in aqueous solution for electrolytes. See benzene/naphthalene? Think association. See water? Think dissociation.
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