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Ionic Equilibrium

NEET > Chemistry > Equilibrium

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Chapter Snapshot - Ionic Equilibrium

The longest and most formula-dense chapter in physical chemistry, covering every equilibrium that involves ions in aqueous solution. Bronsted-Lowry and Lewis acid-base theories, pH and pOH calculations, Ostwald's dilution law, ionic product of water Kw, common ion effect, salt hydrolysis with pH formulas for four salt types, buffer solutions with Henderson-Hasselbalch equations, and solubility product Ksp with selective precipitation form the nine scoring pillars. NEET draws 3 to 4 questions from this chapter, making it the single highest-yield chapter in physical chemistry.

āœ“ Use This To Plan Your First 2–3 Hours
Expected Questions (Typical)
Q
3-4
NEET consistently draws 3 to 4 questions from this chapter. At least one on pH calculation (strong acid, weak acid, or buffer), one on acid-base theory (Lewis acid identification or conjugate pair), one on salt hydrolysis or buffer pH, and occasionally one on Ksp and selective precipitation.
Time Required (Practical)
ā±
14-16 hrs
Acid-base theories 2 hrs; pH scale, Kw, and strong acid/base pH 2 hrs; Ostwald's dilution law and weak acid/base pH 2 hrs; common ion effect 1 hr; salt hydrolysis with four pH formulas 3 hrs; buffer solutions with Henderson-Hasselbalch 2 hrs; Ksp, solubility, and selective precipitation 2 hrs; MCQ practice 2 hrs.
Difficulty Level
⚔
High
The sheer number of pH formulas (strong acid, weak acid, weak base, three salt types, two buffer types) creates memorisation burden. Each formula has specific conditions (dilute solution, h much less than 1, etc.). Mixing up which formula applies to which salt type is the single largest source of errors.
Most Asked Style: Numerical MCQ: calculate pH of a weak acid or buffer solution; identify Lewis acid from given options; determine whether a salt solution is acidic, basic, or neutral; calculate Ksp from solubility data or predict precipitation from ionic product comparison.Biggest Trap: Applying the wrong hydrolysis pH formula. The pH formula for a salt of weak acid with strong base (pH = 7 + (1/2)pKa + (1/2)log C) is different from the formula for a salt of strong acid with weak base (pH = 7 - (1/2)pKb - (1/2)log C). Swapping these gives a pH on the wrong side of 7.Fast Win: Memorise the pH formula family: strong acid pH = -log[H+]; weak acid pH = (1/2)(pKa - log C); salt of weak acid + strong base pH = 7 + (1/2)pKa + (1/2)log C; salt of strong acid + weak base pH = 7 - (1/2)pKb - (1/2)log C; acidic buffer pH = pKa + log([salt]/[acid]); basic buffer pOH = pKb + log([salt]/[base]). These six formulas cover 90% of all numerical questions.Revision-Friendly: Moderate. The six pH formulas can be written on one revision card, but each requires understanding the conditions under which it applies. A 45-minute revision covering the formula family plus one worked example per formula type is the minimum effective coverage.

Subtopics - Ionic Equilibrium (NEET)

Seven topic blocks: acid-base theories (Bronsted-Lowry and Lewis with conjugate pairs and acid/base types), pH scale and ionic product of water, Ostwald's dilution law for weak electrolytes, common ion effect, salt hydrolysis with pH formulas for four salt categories, buffer solutions with Henderson-Hasselbalch equation and buffer capacity, and solubility product with selective precipitation rules.

Revision tip: Before solving any ionic equilibrium numerical: (1) identify the species (strong acid, weak acid, salt, buffer), (2) select the correct pH formula from the six-formula family, (3) check whether the approximation h << 1 or alpha << 1 applies, (4) verify that pH is on the expected side of 7 (acidic solution pH < 7, basic solution pH > 7). This four-step protocol eliminates the two most common NEET errors in this chapter.
NCERT LinesMCQsQuick Test

1) Acid and Bases

Covers three acid-base theories in order of generality: Arrhenius (limited to aqueous solutions), Bronsted-Lowry (proton transfer, applicable to non-aqueous media), and Lewis (electron pair donation/acceptance, the most general). Includes conjugate acid-base pairs, types of Lewis acids (incomplete octet, cations, empty d-orbitals, multiple bonds), and types of Lewis bases (lone pair donors, anions).

Bronsted: proton donor/acceptorLewis: electron pair acceptor/donorKa times Kb = Kw for conjugate pairBF3 is classic Lewis acid
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Bronsted and Lowry conceptAn acid is a proton (H+) donor; a base is a proton acceptor. After losing H+, an acid becomes its conjugate base. After gaining H+, a base becomes its conjugate acid. The strengths of conjugate pairs are inversely related: a strong acid has a weak conjugate base and vice versa. Ka times Kb = Kw for any conjugate pair. This concept extends acid-base behaviour beyond aqueous solutions and includes ionic species.
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Lewis conceptA Lewis acid accepts a pair of electrons (electrophile); a Lewis base donates a pair of electrons (nucleophile). The bond formed is a coordinate covalent bond. Lewis concept is more general than Bronsted-Lowry: all Bronsted bases are Lewis bases, but not all Bronsted acids are Lewis acids. Types of Lewis acids: molecules with incomplete octets (BF3, AlCl3), simple cations (H+, Ag+), molecules with empty d-orbitals (SiX4, SnX4, SF4), and molecules with polar multiple bonds (CO2, SO2, SO3). Lewis bases: neutral species with lone pairs (NH3, amines, alcohols) and anions (Cl-, CN-, OH-).
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Types of Lewis acidsFour categories of Lewis acids: (1) Electron-deficient molecules with incomplete octet: BF3, BCl3, AlCl3, BeCl2. (2) Simple cations with high charge density: H+, Ag+, Cu2+, Fe3+. Cations like Na+ and K+ have very little Lewis acid character. (3) Molecules with empty d-orbitals on the central atom: SiX4, GeX4, TiCl4, SnX4, PF5, SF4. These can expand their octet by accepting electron pairs. (4) Molecules with polar multiple bonds between atoms of dissimilar electronegativity: CO2, SO2, SO3; the pi electrons shift toward the more electronegative atom under attack by a Lewis base.
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Types of Lewis basesTwo categories: (1) Neutral species with at least one lone pair of electrons: NH3, amines (R-NH2), alcohols (R-OH), ethers (R-O-R), water (H2O). The lone pair is donated to the Lewis acid. (2) Negatively charged species (anions): CN-, Cl-, OH-, F-. These have extra electron density readily available for donation. All nucleophiles are Lewis bases.

2) Strength of Acids and Bases and pH scales

Defines acidic and basic strength in terms of H+ and OH- ion donation. Introduces the pH scale (Sorenson), ionic product of water Kw = [H+][OH-] = 10^-14 at 298 K, and the relation pH + pOH = pKw = 14 at 298 K. Covers self-ionisation of water and the temperature dependence of Kw.

pH = -log[H+]Kw = 10^-14 at 298KpH + pOH = 14Neutral pH = 7 only at 298K
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Self ionisation of waterPure water undergoes very slight ionisation: H2O to H+ + OH-. The ionic product Kw = [H+][OH-] = K times [H2O], where [H2O] is constant for dilute solutions. At 298 K, Kw = 10^-14. For pure water: [H+] = [OH-] = 10^-7 M, giving pH = pOH = 7. pH + pOH = pKw = 14 at 298 K. Kw increases with temperature (ionisation is endothermic), so the neutral pH decreases below 7 at higher temperatures. The temperature dependence follows: log(Kw2/Kw1) = (delta-H / 2.303R)(1/T1 - 1/T2).
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Common ion effectWhen a strong electrolyte sharing a common ion is added to a solution of a weak electrolyte, the dissociation of the weak electrolyte is suppressed. For example, adding CH3COONa (provides CH3COO-) to CH3COOH solution suppresses acetic acid ionisation because the common acetate ion shifts the equilibrium backward. Similarly, adding NH4Cl (provides NH4+) to NH4OH solution suppresses ammonium hydroxide dissociation. The common ion effect is used in qualitative analysis to control S2- ion concentration in Group II and OH- concentration in Group III.

3) Hydrolysis of salts and their pH

When a salt dissolves in water and its constituent ions react with H+ or OH- from water to regenerate the parent weak acid or base, the process is called hydrolysis. Three salt types hydrolyse: weak acid + strong base (basic solution), strong acid + weak base (acidic solution), and weak acid + weak base (pH depends on Ka vs Kb). A fourth type, strong acid + strong base, does not hydrolyse.

Weak acid + strong base: basicStrong acid + weak base: acidicKh = Kw/Ka or Kw/KbpH formulas differ by salt type
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Salts of weak acid with strong baseThe anion of the weak acid undergoes hydrolysis: CH3COO- + H2O to CH3COOH + OH-. The hydrolysis constant Kh = Kw/Ka. Degree of hydrolysis h = sqrt(Kw/(Ka times C)) when h << 1. The solution is basic because OH- ions are produced. pH = (1/2)pKw + (1/2)pKa + (1/2)log C = 7 + (1/2)pKa + (1/2)log C at 298 K. Example: CH3COONa solution is basic.
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Salts of strong acid and weak baseThe cation of the weak base undergoes hydrolysis: NH4+ + H2O to NH4OH + H+. The hydrolysis constant Kh = Kw/Kb. Degree of hydrolysis h = sqrt(Kw/(Kb times C)) when h << 1. The solution is acidic because H+ ions are produced. pH = (1/2)pKw - (1/2)pKb - (1/2)log C = 7 - (1/2)pKb - (1/2)log C at 298 K. Example: NH4Cl solution is acidic.
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Salt of a weak acid with weak baseBoth ions undergo hydrolysis: CH3COO- + NH4+ + H2O to CH3COOH + NH4OH. The hydrolysis constant Kh = Kw/(Ka times Kb). The degree of hydrolysis h/(1-h) = sqrt(Kw/(Ka times Kb)) and is independent of concentration. pH = (1/2)pKw + (1/2)pKa - (1/2)pKb. If Ka > Kb the solution is acidic; if Ka < Kb the solution is basic; if Ka = Kb the solution is neutral. Example: CH3COONH4 gives a nearly neutral solution because Ka of acetic acid is close to Kb of ammonia.

4) Buffer Solutions, Mechanism of Action and their pH

A buffer solution resists pH changes upon addition of small amounts of acid or base and upon dilution. Contains a weak acid/base and its conjugate. Acidic buffer: weak acid + salt of that acid. Basic buffer: weak base + salt of that base. Salt buffer: salt of weak acid with weak base. The Henderson-Hasselbalch equation gives pH directly.

Acidic buffer: pH = pKa + log([salt]/[acid])Basic buffer: pOH = pKb + log([salt]/[base])Buffer range: pKa +/- 1Buffer capacity = moles added / delta-pH
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Acidic bufferConsists of a weak acid and its conjugate base (salt). Example: CH3COOH + CH3COONa. The common ion from the salt suppresses acid dissociation. Adding H+ shifts equilibrium backward, consuming the added acid. Adding OH- neutralises some H+ but the equilibrium shifts forward to compensate. pH = pKa + log([conjugate base]/[acid]) (Henderson-Hasselbalch equation). Since the acid dissociation is suppressed, [conjugate base] approximately equals [salt] and [acid] approximately equals initial acid concentration.
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Basic bufferConsists of a weak base and its conjugate acid (salt). Example: NH4OH + NH4Cl. Adding OH- shifts equilibrium backward; adding H+ is consumed by the base. pOH = pKb + log([conjugate acid]/[base]); then pH = pKw - pOH = 14 - pOH at 298 K.
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Salt bufferA salt of a weak acid with a weak base (e.g., CH3COONH4) also acts as a buffer. Adding acid: H+ combines with CH3COO- to form CH3COOH. Adding base: OH- combines with NH4+ to form NH4OH. The pH is given by the salt hydrolysis formula: pH = (1/2)pKw + (1/2)pKa - (1/2)pKb, which is independent of concentration.
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Buffer capacityDefined as the number of equivalents of acid or base required per litre of buffer to change pH by one unit. A buffer works effectively when [salt]/[acid] lies between 0.1 and 10, which corresponds to pH in the range pKa +/- 1. Acetic acid (pKa = 4.75) can buffer from pH 3.75 to 5.75. Higher total concentrations of acid and salt give higher buffer capacity.

5) Solubility and Solubility product

Defines solubility as the maximum amount of salt that dissolves at a given temperature. For a sparingly soluble salt AxBy: Ksp = x^x times y^y times s^(x+y), where s is molar solubility. Covers five cases: solubility in pure water, with common ion, with complex formation, for salts of weak acid (hydrolysis correction), and simultaneous solubility of two salts.

Ksp = [A+]^x [B-]^y at saturationCommon ion decreases solubilityIP > Ksp: precipitationIP < Ksp: unsaturated
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Different cases of calculating solubilitiesFive standard cases: (1) Pure water: for CaF2, Ksp = 4s^3 where s is molar solubility. (2) Common ion: for AgCl in 0.1 M AgNO3, Ksp = (0.1 + s) times s; since s is small, approximately Ksp = 0.1s. (3) Complex formation: AgCl in NH3, with formation constant Kf for [Ag(NH3)2]+; solve Ksp and Kf equations simultaneously. (4) Salt of weak acid: CH3COOAg in water; the acetate ion hydrolyses, creating two simultaneous equilibria (Ksp and Kh). (5) Simultaneous solubility: AgCl and AgBr dissolving together share the common Ag+ ion; Ksp(AgCl) = (s + s') times s and Ksp(AgBr) = (s + s') times s'.

6) Selective precipitation

Compares the ionic product (IP) with Ksp to predict whether precipitation occurs. If IP > Ksp, precipitation continues until IP = Ksp. If IP < Ksp, no precipitation. Used in qualitative analysis to selectively precipitate one ion while keeping another in solution.

IP > Ksp: precipitate formsIP < Ksp: no precipitateIP = Ksp: saturated (just begins)Used in qualitative analysis
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Ionic product and precipitation rulesFor any sparingly soluble salt, the ionic product (IP) is the product of ion concentrations raised to stoichiometric powers, calculated from all sources of those ions in solution. Three rules: (1) IP > Ksp means the solution is supersaturated and precipitation occurs until IP reduces to Ksp. (2) IP < Ksp means the solution is unsaturated and no precipitation occurs. (3) IP = Ksp means the solution is exactly saturated (precipitation is about to begin but has not yet occurred in a practical sense). Example: mixing 500 mL of 0.005 M AgNO3 with 500 mL of 0.001 M KCl gives IP = (0.0025)(0.0005) = 1.25 times 10^-6, which exceeds Ksp of AgCl (1.56 times 10^-10), so AgCl precipitates.

Ionic Equilibrium Download Notes & Weightage Plan

For each topic in the Ionic Equilibrium chapter below, you get (2) the exact resources to download and how to use them, and (3) a simple importance & time plan so NEET students know what to do first and what to revise last.

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Acid and Bases

Three acid-base theories in order of generality: Arrhenius, Bronsted-Lowry, and Lewis. Conjugate acid-base pairs, types of Lewis acids and bases.

Conceptual MCQ topicLewis acid ID is tested yearlyConjugate pairs: Ka Kb = KwKnow 4 types of Lewis acids

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

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Topic Notes (Condensed)Bronsted-Lowry: acid = proton donor, base = proton acceptor. Conjugate pairs: acid loses H+ to form conjugate base; base gains H+ to form conjugate acid. Ka times Kb = Kw for conjugate pairs. Inverse strength rule: strong acid has weak conjugate base. Lewis: acid = electron pair acceptor (electrophile), base = electron pair donor (nucleophile). Lewis acids: (1) incomplete octet (BF3, AlCl3), (2) cations (H+, Ag+), (3) empty d-orbitals (SiX4, SnX4), (4) polar multiple bonds (CO2, SO2). Lewis bases: lone pair neutral species (NH3, H2O) and anions (Cl-, OH-). All Bronsted bases are Lewis bases; not all Bronsted acids are Lewis acids.
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Make a comparison table: Arrhenius vs Bronsted-Lowry vs Lewis with examples. Memorise the four types of Lewis acids with two examples each. Know that BF3, AlCl3 are tested most frequently. Practise identifying conjugate pairs from given equilibria.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One MCQ per NEET paper on acid-base theory, most commonly asking to identify a Lewis acid from four options (BF3 is the classic answer) or to identify the strongest conjugate base from a list of anions.
Time Required2 hrs45 min on Bronsted-Lowry with conjugate pairs; 45 min on Lewis acids and bases with all four types; 30 min MCQ practice.
DifficultyEasy-ModerateConceptual recall. The four types of Lewis acids require memorisation but the logic is clear: any species that can accept an electron pair is a Lewis acid.
  • Scoring Focus: Lewis acid identification: BF3, AlCl3, SiF4 are Lewis acids because of electron deficiency or empty d-orbitals. NH3 is a Lewis base (lone pair donor). BF3 is the most tested Lewis acid in NEET.
  • High-risk Area: Students confuse Lewis acids with Bronsted acids. CO2 is a Lewis acid (accepts electron pair via pi bond shift) but is NOT a Bronsted acid (it does not donate H+). NEET uses CO2 as a Lewis acid option to test this distinction.
  • Best Practice Style: For Lewis acid questions: check if the species can accept an electron pair. Look for incomplete octets, positive charges, or empty orbitals. If yes, it is a Lewis acid.
Priority rule: High priority for conceptual marks. Lewis acid/base identification is tested every year. Spend 2 hours and memorise the four Lewis acid categories.

Strength of Acids and Bases and pH scales

Defines pH, pOH, Kw, and the pH scale. Covers self-ionisation of water, the temperature dependence of Kw, and the common ion effect on weak electrolyte dissociation.

pH = -log[H+]Kw = 10^-14 at 298KpH + pOH = 14Common ion suppresses dissociation

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)pH = -log[H+]; pOH = -log[OH-]; pH + pOH = pKw = 14 at 298K. Self-ionisation of water: H2O to H+ + OH-; Kw = [H+][OH-] = 10^-14 at 298K. Pure water: [H+] = [OH-] = 10^-7, pH = 7. Kw increases with temperature (endothermic ionisation), so neutral pH falls below 7 at higher temperatures. Common ion effect: adding a strong electrolyte with a common ion suppresses dissociation of a weak electrolyte. Example: CH3COONa suppresses CH3COOH ionisation via common CH3COO- ion. Application in qualitative analysis: control [S2-] in Group II and [OH-] in Group III.
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Memorise: pH + pOH = 14 at 298K; Kw = 10^-14 at 298K; neutral pH = 7 only at 298K. Practise pH calculations for strong acids and strong bases. Remember that pH of a strong acid with [H+] = 10^-8 M cannot simply be -log(10^-8) = 8 (acidic solution cannot have pH > 7); the autoionisation of water must be added.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One pH calculation for a strong acid or strong base, or one question on the common ion effect (e.g., which addition suppresses NH4OH dissociation).
Time Required2 hrs30 min on pH/pOH definitions; 30 min on Kw and self-ionisation; 30 min on common ion effect; 30 min MCQ practice.
DifficultyEasy-ModeratepH calculations for strong acids are straightforward. The subtle case is very dilute strong acids where [H+] from the acid is comparable to 10^-7 from water autoionisation.
  • Scoring Focus: For strong acids with concentration greater than 10^-6 M: pH = -log C. For very dilute acids (10^-7 to 10^-8 M): add water contribution. Common ion effect: know that adding NaCl to AgCl equilibrium or CH3COONa to CH3COOH suppresses dissociation.
  • High-risk Area: Very dilute strong acid (e.g., 10^-8 M HCl) gives pH = 6.98, not 8. Students who blindly apply pH = -log(10^-8) = 8 conclude the acid is basic, which is absurd. The water autoionisation contribution (10^-7 M) must be included.
  • Best Practice Style: If [H+] from the acid is less than 10^-6 M, add the water contribution: total [H+] = [H+]acid + [H+]water. Solve the quadratic if needed.
Priority rule: High priority. pH calculations appear in every NEET paper. Master strong acid/base pH first, then move to weak acids.

Hydrolysis of salts and their pH

Derives pH formulas for three types of hydrolysable salts: weak acid + strong base (basic), strong acid + weak base (acidic), and weak acid + weak base (depends on Ka vs Kb). Strong acid + strong base salts do not hydrolyse.

SA + SB: no hydrolysis, pH = 7WA + SB: basic, Kh = Kw/KaSA + WB: acidic, Kh = Kw/KbWA + WB: pH depends on Ka vs Kb

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Hydrolysis: salt ions react with water to regenerate parent acid or base. (1) Weak acid + strong base (e.g., CH3COONa): anion hydrolyses; Kh = Kw/Ka; h = sqrt(Kw/(Ka C)); pH = 7 + (1/2)pKa + (1/2)log C (basic). (2) Strong acid + weak base (e.g., NH4Cl): cation hydrolyses; Kh = Kw/Kb; h = sqrt(Kw/(Kb C)); pH = 7 - (1/2)pKb - (1/2)log C (acidic). (3) Weak acid + weak base (e.g., CH3COONH4): both ions hydrolyse; Kh = Kw/(Ka Kb); h/(1-h) = sqrt(Kw/(Ka Kb)); pH = 7 + (1/2)pKa - (1/2)pKb (independent of C). If Ka > Kb: acidic; Ka < Kb: basic; Ka = Kb: neutral. (4) Strong acid + strong base (e.g., NaCl): no hydrolysis, pH = 7.
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Write the three pH formulas side by side with the salt type: WA+SB (basic, + terms), SA+WB (acidic, - terms), WA+WB (Ka vs Kb comparison). Solve one numerical for each type. The WA+WB formula has no concentration term, which is a distinguishing feature.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One question asking whether a given salt solution is acidic, basic, or neutral, or asking to calculate pH of a salt solution using the hydrolysis formula.
Time Required3 hrs1 hr on WA+SB derivation and numericals; 1 hr on SA+WB; 30 min on WA+WB; 30 min on comparison MCQs.
DifficultyModerate-HighThe derivations involve multiple substitutions. The formulas must be memorised precisely because sign errors invert the pH answer. The WA+WB case requires careful Ka vs Kb comparison.
  • Scoring Focus: Quick classification: see Na2CO3 or CH3COONa? Weak acid + strong base, pH > 7. See NH4Cl? Strong acid + weak base, pH < 7. See NaCl? No hydrolysis, pH = 7. Then apply the corresponding formula.
  • High-risk Area: Swapping the WA+SB formula with the SA+WB formula. Remember: WA+SB has PLUS signs (pH = 7 + ... + ...) because the solution is basic (pH > 7). SA+WB has MINUS signs (pH = 7 - ... - ...) because the solution is acidic (pH < 7). The signs match the expected side of 7.
  • Best Practice Style: First determine the salt type. Then recall: basic solution has + signs, acidic solution has - signs. Substitute pKa or pKb and log C. Verify: is the final pH on the correct side of 7?
Priority rule: Highest priority. Salt hydrolysis pH is tested every year. Master the three formulas and the quick classification of salt types.

Buffer Solutions, Mechanism of Action and their pH

Defines buffer solutions and explains their mechanism of resisting pH change. Covers acidic buffers (weak acid + conjugate base salt), basic buffers (weak base + conjugate acid salt), and salt buffers. Henderson-Hasselbalch equation and buffer capacity.

pH = pKa + log([salt]/[acid])pOH = pKb + log([salt]/[base])Buffer range: pKa +/- 1Buffer capacity = mol/(delta pH)

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Buffer: resists pH change on adding small amounts of acid/base or on dilution. Acidic buffer: weak acid + its salt (e.g., CH3COOH + CH3COONa). pH = pKa + log([salt]/[acid]) (Henderson-Hasselbalch). Mechanism: added H+ consumed by conjugate base; added OH- consumed by weak acid; dilution shifts equilibrium forward. Basic buffer: weak base + its salt (e.g., NH4OH + NH4Cl). pOH = pKb + log([salt]/[base]). Salt buffer: salt of WA + WB (e.g., CH3COONH4); acts as buffer, pH = 7 + (1/2)pKa - (1/2)pKb. Buffer capacity: moles of H+ or OH- per litre needed to change pH by one unit. Effective range: [salt]/[acid] between 0.1 and 10, giving pH = pKa +/- 1.
Download NotesPrintable PDF
ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Memorise Henderson-Hasselbalch: acidic buffer pH = pKa + log([salt]/[acid]); basic buffer pOH = pKb + log([salt]/[base]). Remember that when [salt] = [acid], pH = pKa (maximum buffer capacity). Practise: given 0.1 M CH3COOH and 0.1 M CH3COONa with pKa = 4.75, pH = 4.75 + log(1) = 4.75.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One numerical on buffer pH using Henderson-Hasselbalch, or one conceptual question asking which pair forms a buffer (e.g., CH3COOH + CH3COONa versus HCl + NaCl).
Time Required2 hrs45 min on Henderson-Hasselbalch derivation and mechanism; 45 min on buffer capacity and effective range; 30 min MCQ practice.
DifficultyModerateThe Henderson-Hasselbalch equation is simple but requires identifying which component is the acid, which is the salt, and using the correct ratio. Problems sometimes give moles instead of molarity, requiring volume calculation.
  • Scoring Focus: Henderson-Hasselbalch equation: pH = pKa + log([salt]/[acid]). When equal concentrations of acid and salt are mixed, pH = pKa. This is the single most important result for NEET buffer questions.
  • High-risk Area: Confusing [salt] with [acid] in the Henderson-Hasselbalch ratio. The ratio is always conjugate base (salt) over acid. Inverting it gives pH = pKa - log([salt]/[acid]) = pKa + log([acid]/[salt]), which is the wrong formula.
  • Best Practice Style: Write the Henderson-Hasselbalch equation with labels: pH = pKa + log(BASE/ACID). The base (conjugate base or salt) is always in the numerator.
Priority rule: High priority. Buffer pH calculations are tested frequently. Practise at least 5 numericals with different acid-salt ratios.

Solubility and Solubility product

Relates molar solubility to the solubility product Ksp. Covers the general formula Ksp = x^x y^y s^(x+y) for AxBy salts. Five cases: pure water, common ion, complex formation, hydrolysis correction, and simultaneous solubility.

Ksp = x^x y^y s^(x+y)Common ion reduces sIP > Ksp: precipitateIP = Ksp: saturated

1) Download Packs For This Topic (And How To Use Them)

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Topic Notes (Condensed)Solubility (s) = max moles of salt per litre at saturation. For AxBy(s) to xA^y+(aq) + yB^x-(aq): Ksp = [A^y+]^x[B^x-]^y = (xs)^x(ys)^y = x^x y^y s^(x+y). Five cases: (1) Pure water: straightforward Ksp to s conversion. CaF2: Ksp = 4s^3, s = (Ksp/4)^(1/3). (2) Common ion: AgCl in 0.1M AgNO3; [Ag+] = 0.1 + s approximately 0.1; Ksp = 0.1 times s, so s = Ksp/0.1 (much smaller than in pure water). (3) Complex: AgCl in NH3; Ksp and Kf equations solved simultaneously. (4) Weak acid salt: CH3COOAg in water; hydrolysis of CH3COO- creates two equilibria. (5) Simultaneous: AgCl and AgBr together share [Ag+] = s1 + s2.
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ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Practise converting Ksp to s for three salt types: AB (Ksp = s^2), AB2 (Ksp = 4s^3), A2B (Ksp = 4s^3), A2B3 (Ksp = 108s^5). The pattern: multiply coefficients raised to their stoichiometric powers. For common ion problems, approximate: ignore s relative to the common ion concentration.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1One numerical: calculate solubility from Ksp, or calculate Ksp from given solubility, or predict whether precipitation occurs by comparing IP with Ksp.
Time Required2 hrs45 min on Ksp derivation for different salt types; 30 min on common ion effect on solubility; 30 min on IP vs Ksp comparison; 15 min MCQ practice.
DifficultyModerateThe formula Ksp = x^x y^y s^(x+y) requires careful coefficient handling. Common ion problems need the approximation that s is negligible compared to the added ion concentration.
  • Scoring Focus: Two high-yield moves: (1) For AB2 type (e.g., CaF2): Ksp = 4s^3, so s = (Ksp/4)^(1/3). (2) IP vs Ksp comparison: if calculated IP exceeds Ksp, precipitation occurs. These two skills answer most NEET Ksp questions.
  • High-risk Area: Forgetting the coefficient multipliers in Ksp expressions. For PbCl2 (PbCl2 to Pb2+ + 2Cl-): Ksp = s times (2s)^2 = 4s^3, not s^3. Missing the factor of 4 gives s that is too large by a factor of (4)^(1/3) = 1.587. NEET places the wrong value as a distractor.
  • Best Practice Style: Always write the dissociation equation with stoichiometric coefficients. Each ion concentration = coefficient times s. Then substitute into Ksp expression and simplify.
Priority rule: High priority. Ksp problems appear in most NEET papers. Practise the AB, AB2, and A2B3 types until automatic.

Selective precipitation

Uses the IP vs Ksp comparison to predict and control precipitation of specific ions from a mixture. Foundational to qualitative inorganic analysis.

IP > Ksp: precipitateIP < Ksp: stays dissolvedControls ion separationQualitative analysis basis

1) Download Packs For This Topic (And How To Use Them)

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Topic Notes (Condensed)Selective precipitation: in a solution containing multiple ions, the salt with the smallest Ksp precipitates first when the common ion concentration is gradually increased. Rules: IP > Ksp leads to precipitation until IP = Ksp. IP < Ksp means no precipitate. IP = Ksp means saturated but no visible precipitate yet. Example: mixing 500 mL of 0.005 M AgNO3 with 500 mL of 0.001 M KCl gives [Ag+] = 0.0025 M, [Cl-] = 0.0005 M, IP = 1.25 times 10^-6 which is much greater than Ksp(AgCl) = 1.56 times 10^-10, so AgCl precipitates. This principle is used in Group II-III separation in qualitative analysis.
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ā˜…
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Review the IP vs Ksp three-way comparison. Practise one selective precipitation problem: given Ksp of AgCl and AgBr, determine which precipitates first when Ag+ is added to a solution containing both Cl- and Br-. Answer: AgBr precipitates first (lower Ksp).

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions0-1Occasionally tested as: will a precipitate form when two solutions are mixed? Calculate IP and compare with Ksp.
Time Required1 hr30 min on the three IP vs Ksp rules; 30 min on selective precipitation examples.
DifficultyModerateThe comparison is simple but requires careful dilution calculation when two solutions are mixed (concentrations halve if equal volumes are mixed).
  • Scoring Focus: When two solutions are mixed, first calculate the new concentrations (account for dilution), then calculate IP, then compare with Ksp. If IP > Ksp, precipitation occurs.
  • High-risk Area: Forgetting to account for dilution when solutions are mixed. If 500 mL of 0.005 M AgNO3 is mixed with 500 mL of 0.001 M KCl, the total volume is 1000 mL, so [Ag+] = 0.005 times 500/1000 = 0.0025 M, not 0.005 M. Using undiluted concentrations gives an IP that is 4 times too large.
  • Best Practice Style: Step 1: calculate diluted concentrations. Step 2: calculate IP. Step 3: compare with Ksp. Three steps, no shortcuts.
Priority rule: Medium priority. The IP vs Ksp comparison is simple but the dilution calculation needs practice.

Ionic Equilibrium Chapter NEET Traps & Common Mistakes (Topic-Wise)

Each subtopic below is of the Ionic Equilibrium chapter and shows what NEET students usually do wrong in NEET examination, a short example of the mistake, and how NEET frames the question to trick you with close options are given below.

! Avoid Easy Negatives
Salt Hydrolysis pH Formulas
NEETHydrolysispHSalt type

Mistake Snapshot (What Students Do Wrong)

  • Using the wrong pH formula for the salt type: The pH formula for weak acid + strong base salt has PLUS signs (pH = 7 + ...) while the formula for strong acid + weak base salt has MINUS signs (pH = 7 - ...). Swapping them gives pH on the wrong side of 7: a basic salt appears acidic and vice versa.
  • Forgetting that WA+WB salt pH is independent of concentration: For salts of weak acid with weak base, pH = (1/2)pKw + (1/2)pKa - (1/2)pKb with no log C term. Students who add a concentration term get a wrong answer.
2–3 Line Example (Typical Error)

0.1 M CH3COONa (weak acid + strong base). pH = 7 + (1/2)(4.75) + (1/2)(log 0.1) = 7 + 2.375 + (-0.5) = 8.875. If student uses the SA+WB formula: pH = 7 - 2.375 - (-0.5) = 5.125, which incorrectly shows acidic solution for a basic salt.

How NEET Frames The Trap

NEET asks for pH of a salt solution. The distractors are calculated using the wrong formula for the salt type.

NEET-Style Trap Question Format

Q. The pH of 0.01 M NH4Cl solution is (Kb of NH4OH = 1.8 x 10^-5)
A. 6.13   B. 7.87   C. 7.00   D. 4.75  
Trick: NH4Cl = strong acid + weak base, so pH < 7. pKb = -log(1.8 x 10^-5) = 4.74. pH = 7 - (1/2)(4.74) - (1/2)log(0.01) = 7 - 2.37 - (-1) = 7 - 2.37 + 1 = 5.63. Wait, the correct calculation: pH = 7 - (1/2)(4.74) - (1/2)(log 0.01) = 7 - 2.37 - (-1) = 5.63. Option A (6.13) is closest. Option B uses the WA+SB formula giving pH > 7 for an acidic salt.

Quick rule: Identify salt type first. WA+SB = basic (plus signs in pH formula). SA+WB = acidic (minus signs). WA+WB = no concentration term. SA+SB = pH 7.
Henderson-Hasselbalch and Buffer pH
NEETBufferHenderson-HasselbalchpH

Mistake Snapshot (What Students Do Wrong)

  • Inverting the [salt]/[acid] ratio in Henderson-Hasselbalch: pH = pKa + log([salt]/[acid]). Inverting to [acid]/[salt] changes the sign of the log term. If [salt] > [acid], the correct formula gives pH > pKa, but the inverted formula gives pH < pKa.
  • Using molarity instead of moles when volumes differ: When acid and salt solutions of different volumes are mixed, the concentrations change. Using initial molarities without adjusting for final volume gives the wrong ratio. Since both acid and salt are in the same final volume, the volume cancels and only moles matter.
2–3 Line Example (Typical Error)

500 mL of 0.1 M CH3COOH mixed with 500 mL of 0.2 M CH3COONa. pKa = 4.75. Moles acid = 0.05, moles salt = 0.10. Ratio = 0.10/0.05 = 2. pH = 4.75 + log 2 = 4.75 + 0.30 = 5.05. If student uses molarities directly without volume: pH = 4.75 + log(0.2/0.1) = 5.05. Same answer here because equal volumes, but if volumes differ (say 500 mL acid + 250 mL salt): moles acid = 0.05, moles salt = 0.05, ratio = 1, pH = 4.75. Using molarities: log(0.2/0.1) = log 2, giving wrong pH = 5.05.

How NEET Frames The Trap

NEET gives different volumes of acid and salt solutions. Students who use molarities instead of moles after mixing get the wrong ratio.

NEET-Style Trap Question Format

Q. What is the pH of a buffer made by mixing 200 mL of 0.1 M CH3COOH with 300 mL of 0.1 M CH3COONa? (pKa = 4.75)
A. 4.93   B. 4.75   C. 5.05   D. 4.57  
Trick: Moles acid = 0.02, moles salt = 0.03. Ratio = 0.03/0.02 = 1.5. pH = 4.75 + log(1.5) = 4.75 + 0.176 = 4.93 (Option A). Option B ignores the ratio (assumes equal). Option C uses molarities (both 0.1) giving log 1 = 0. Option D inverts the ratio.

Quick rule: In Henderson-Hasselbalch, always use MOLES (not molarity) when solutions of different volumes are mixed. The ratio [salt]/[acid] = moles of salt / moles of acid because both share the same final volume.
Ksp and Solubility Calculations
NEETKspSolubilityCoefficient error

Mistake Snapshot (What Students Do Wrong)

  • Forgetting stoichiometric coefficient multipliers in Ksp: For CaF2 to Ca2+ + 2F-: [F-] = 2s, so Ksp = s(2s)^2 = 4s^3. Students who write Ksp = s^3 miss the factor of 4 and get solubility that is 4^(1/3) = 1.587 times too large.
  • Not accounting for dilution in precipitation problems: When two solutions are mixed, the total volume increases and all concentrations decrease proportionally. Using original concentrations instead of diluted ones gives an ionic product that is too large.
2–3 Line Example (Typical Error)

Ksp of PbCl2 = 1.6 x 10^-5. PbCl2 to Pb2+ + 2Cl-. Ksp = s times (2s)^2 = 4s^3. s = (Ksp/4)^(1/3) = (4 x 10^-6)^(1/3) = 1.587 x 10^-2 M. If student writes Ksp = s^3: s = (1.6 x 10^-5)^(1/3) = 2.52 x 10^-2 M, which is 59% too large. NEET places this as a distractor.

How NEET Frames The Trap

NEET gives Ksp and asks for solubility. The incorrect answer calculated without the coefficient multiplier is always one of the four options.

NEET-Style Trap Question Format

Q. The solubility product of Ag2CrO4 is 1.1 x 10^-12. What is the solubility in mol/L?
A. 6.5 x 10^-5   B. 1.03 x 10^-4   C. 1.1 x 10^-4   D. 5.5 x 10^-7  
Trick: Ag2CrO4 to 2Ag+ + CrO4^2-. [Ag+] = 2s, [CrO4^2-] = s. Ksp = (2s)^2 times s = 4s^3. s = (Ksp/4)^(1/3) = (2.75 x 10^-13)^(1/3) = 6.5 x 10^-5 (Option A). Option B uses Ksp = s^3 (no factor 4). Option D uses Ksp = 2s^2.

Quick rule: Write the dissociation equation. Each ion = coefficient times s. Substitute all terms into Ksp = [cation]^p [anion]^q. Do not forget the coefficient in front of s when it is squared or cubed.
pH of Very Dilute Strong Acids
NEETpHDilute acidWater autoionisation

Mistake Snapshot (What Students Do Wrong)

  • Getting pH > 7 for a strong acid solution: For 10^-8 M HCl, blindly applying pH = -log(10^-8) = 8 gives a basic pH for an acid, which is physically impossible. The water autoionisation contribution (10^-7 M H+) must be added.
  • Ignoring that very dilute acids still produce acidic solutions: Any acid in water makes [H+] > 10^-7, giving pH < 7. The correct calculation for 10^-8 M HCl: total [H+] approximately 1.05 x 10^-7, so pH approximately 6.98.
2–3 Line Example (Typical Error)

10^-8 M HCl. Incorrect: pH = -log(10^-8) = 8 (basic? impossible for an acid!). Correct: total [H+] = 10^-8 + [H+]water. From Kw = [H+][OH-] and charge balance: [H+]^2 - 10^-8[H+] - 10^-14 = 0. [H+] = 1.05 x 10^-7. pH = 6.98. The acid gives pH just below 7, as expected.

How NEET Frames The Trap

NEET asks for pH of a very dilute strong acid (10^-7 to 10^-9 M). The distractor pH = 8 catches students who do not account for water autoionisation.

NEET-Style Trap Question Format

Q. What is the pH of 10^-8 M HCl solution?
A. 6.98   B. 8.00   C. 7.00   D. 6.00  
Trick: Total [H+] = 10^-8 (from HCl) + approximately 10^-7 (from water) = approximately 1.05 x 10^-7. pH = -log(1.05 x 10^-7) = 6.98 (Option A). Option B directly uses -log(10^-8). Option C is pure water pH. Option D is -log(10^-6).

Quick rule: If the acid concentration is 10^-6 M or lower, you MUST add the water autoionisation contribution. Any acid in water always gives pH < 7.
Lewis Acid Identification
NEETLewis acidElectron deficiencyConceptual

Mistake Snapshot (What Students Do Wrong)

  • Confusing Lewis acids with Bronsted acids: CO2 and SO2 are Lewis acids (accept electron pairs via pi bond shifting) but are NOT Bronsted acids (they do not donate H+). Students who think acid = H+ donor miss CO2 as a Lewis acid.
  • Thinking BF3 is not an acid because it has no H+: BF3 has an incomplete octet on boron (6 electrons) and readily accepts an electron pair. It is the most classic Lewis acid. Students conditioned by Bronsted theory may not recognise it.
2–3 Line Example (Typical Error)

Which of the following is a Lewis acid? (a) NH3 (b) BF3 (c) H2O (d) C2H5OH. Answer: BF3 (Option B). BF3 has only 6 electrons around B and can accept an electron pair. NH3, H2O, and C2H5OH all have lone pairs and are Lewis bases.

How NEET Frames The Trap

NEET gives four molecules and asks which is a Lewis acid. Three options are Lewis bases (lone pair donors) and one is the Lewis acid (electron deficient or has empty orbitals).

NEET-Style Trap Question Format

Q. Which of the following acts as a Lewis acid?
A. BF3   B. NH3   C. H2O   D. (CH3)3N  
Trick: BF3 (Option A) has an incomplete octet on boron (6 valence electrons). It accepts an electron pair to complete its octet. NH3 (lone pair on N), H2O (two lone pairs on O), and (CH3)3N (lone pair on N) are all Lewis bases.

Quick rule: Look for electron deficiency: incomplete octet (BF3, AlCl3), positive charge (H+, Ag+), or empty d-orbitals (SiF4). If a species can accept an electron pair, it is a Lewis acid.
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