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Excess Pressure

NEET > Physics > Properties of Bulk Matter > Surface Tension > Excess Pressure

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Overview content

Topic 5 of 8 • Chapter: Surface Tension • Physics

Excess Pressure – Complete Notes, Revision, Important Questions & Downloads

This topic is built from four TOC blocks: Definition and General Concept, Excess Pressure Formulas, Double Bubble Formation, and Single Bubble Formation. NEET tests this topic through direct formula questions on drops, soap bubbles, bubbles at depth, and communicating bubbles, and it also uses the coalescence relation as a fast numerical check. The OCR emphasis is simple: surface tension tries to contract the surface, so the pressure inside is greater than outside, and the radius decides how large that difference becomes. Once you separate one free surface, two free surfaces, and the special double-bubble interface, most numerical questions reduce to choosing the correct geometry before substitution.

⬇ Download Notes PDFView Important Questions →
Formula HeavyBubble NumericalsRadius Sensitive
Expected QuestionsQ
0-1
Usually shows up as a direct formula or comparison question inside Surface Tension, especially on soap bubble versus liquid drop.
Time Required⏱
60 min
About 25 minutes for the formula table and 35 minutes for double-bubble and coalescence cases where students mix up pressure relations.
Difficulty⚡
Medium
The algebra is short, but many wrong answers come from treating a soap bubble like a drop or forgetting that smaller bubbles have higher internal pressure.
NRI USA Curriculum GapUS
Gap
Many school courses stop at surface tension as a force law, while NEET expects quick pressure comparisons for curved interfaces and bubble combinations.
9Subtopics
4Practice Questions
2Free Downloads
60 minPrep Time
⬇ Get Free Downloads

NEET Weightage - Excess Pressure

Surface Tension
NEET YearQuestions from this TopicBarMarks
NEET 20240
 
0 Q
0
NEET 20230
 
0 Q
0
NEET 20220
 
0 Q
0
NEET 20210
 
0 Q
0
NEET 20200
 
0 Q
0
NEET 20190
 
0 Q
0
Total (2019-2024)0 0
Excess pressure is the pressure difference across a curved liquid surface, not the absolute pressure inside the liquid or gas.
A liquid drop or a single bubble in liquid has one liquid-air surface contribution of 2T/R, while a soap bubble in air has two surfaces and therefore 4T/R.

Smaller bubbles have higher internal pressure, so when two unequal bubbles communicate, air moves from the smaller bubble to the larger one.

Double-bubble and coalescence questions are still surface-tension questions; the only new step is writing the correct pressure relation before conserving volume.
📊
0.0
Avg Questions / Year
🎯
0
Total Marks (6 yrs)
📈
Irregular
Pattern
⚠️
Medium
Difficulty

Excess Pressure Strategy for NEET

1

Identify the interface first Before using any formula, decide whether the question is about a drop, soap bubble, bubble in liquid, cylindrical surface, or common film between two bubbles. The number of effective free surfaces fixes the coefficient of T/R.

2

Check which side is concave Pressure is higher on the concave side of the curved liquid surface. In double-bubble questions this tells you why the common film bends toward the smaller bubble.

3

Use radius comparison immediately If two bubbles have different radii, write the smaller radius first because 1/r is larger. That single comparison predicts the direction of air flow without any arithmetic.

4

Keep coalescence separate from simple excess-pressure formulae Single Bubble Formation is not solved by 2T/R or 4T/R alone. Write pressure-times-volume conservation under isothermal conditions, then insert the surface-tension correction terms.

5

Include outside liquid pressure when depth is given For a bubble at depth h, the outside liquid is already under atmospheric plus hydrostatic pressure, so the final pressure difference becomes 2T/R + hdg in the OCR convention.

Excess Pressure Study Materials

PDF · Cheat Sheet · MCQ Set · PYQ
📘
Full Notes - Excess Pressure
Key formulas, interface logic, and one worked comparison for each of the four subtopics from drops to bubble coalescence.
9 subtopicsFormula tableBubble cases
Download Notes
📗
Formula Sheet - Excess Pressure
Quick sheet for 2T/R, 4T/R, unequal-radii surfaces, double-bubble interface radius, and the isothermal coalescence relation.
2T/R vs 4T/RInterface radiusAt depth
Download Formula Sheet
📙
MCQ Practice Questions - Excess Pressure
NEET-style application set that forces you to distinguish drops, soap bubbles, communicating bubbles, and coalescence equations.
4 core MCQsScenario basedRadius traps
Download MCQ Set
📒
Previous Year Questions (PYQ) - Excess Pressure
Revision-focused set built around the standard exam patterns on bubble pressure comparisons and curved-surface pressure formulas.
Revision useFormula recallChapter link
Download PYQ Set

Excess Pressure Subtopics

2-Column Table
Column AColumn B
Definition and General Concept↗
Excess Pressure Formulas↗
Double Bubble Formation↗
Single Bubble Formation↗
Soluble impurities decreases the angle of contact↗
Partially soluble impurities increases the angle of contact↗
A towel soaks water↗
Capillary action for various liquid-solid pair↗
Ploughing of fields↗

Rapid Revision - Excess Pressure

Concept → Trap → Example

1) Definition and General Concept

Why inside pressure is larger

Due to the property of surface tension a drop or bubble tends to contract and so compresses the matter enclosed. Hence in equilibrium the pressure inside a bubble or drop is greater than outside, and that difference is called excess pressure.

  • In a liquid drop, the inward pull is balanced by hydrostatic pressure of the enclosed liquid.
  • In a gas bubble, the balancing term is the gauge pressure of the confined gas.
  • Do not call absolute internal pressure itself the excess pressure; only the inside-minus-outside difference counts.
Example (NEET-style)A smaller raindrop has larger excess pressure than a larger raindrop because the radius appears in the denominator, so 2T/R increases when R decreases.

2) Excess Pressure Formulas

Choose the right interface

Plane surface: ΔP = 0; drop or single curved liquid surface: ΔP = 2T/R; soap bubble in air: ΔP = 4T/R; cylindrical liquid surface: ΔP = T/R; unequal radii surface: ΔP = T[1/R1 + 1/R2].

  • A soap bubble has two liquid surfaces, so its excess pressure is twice that of a drop of the same radius.
  • A bubble at depth h carries the curved-surface term plus the hydrostatic contribution of the surrounding liquid.
  • The common trap is to use 4T/R for every bubble even when the bubble is inside liquid and only one liquid surface matters.
Example (NEET-style)For T = 0.03 N/m and R = 2 mm, a soap bubble gives ΔP = 4T/R = 60 Pa, while a liquid drop of the same radius gives ΔP = 2T/R = 30 Pa.

3) Double Bubble Formation

Common film between unequal bubbles

If two soap bubbles of radii r1 and r2 are in contact, the pressure difference is ΔP = 4T[1/r1 - 1/r2], and the radius of the common interface is r = r1r2/(r2 - r1).

  • Take r1 as the smaller radius so that 1/r1 - 1/r2 is positive.
  • The common interface is concave toward the smaller bubble because the smaller bubble has larger internal pressure.
  • Students often reverse the direction of curvature by looking only at size, not at which side carries higher pressure.
Example (NEET-style)If r1 = 1 cm and r2 = 2 cm, then 1/r = 1/1 - 1/2 = 1/2, so r = 2 cm for the common film, and the film bows toward the smaller bubble.

4) Single Bubble Formation

Isothermal coalescence

For two isothermal soap bubbles of radii a and b coalescing to radius c, 4T(a^2 + b^2 - c^2) = P0(c^3 - a^3 - b^3). In vacuum this reduces to c^2 = a^2 + b^2.

  • This relation comes from conservation of gas mass using PV proportional to mT under isothermal conditions.
  • Do not conserve only volume without correcting the internal pressure terms of the original and final bubbles.
  • If P0 = 0, the vacuum result is a direct square-law relation, not c^3 = a^3 + b^3.
Example (NEET-style)Two bubbles of radii 3 cm and 4 cm coalesce in vacuum to form a new bubble with c = √(3^2 + 4^2) = 5 cm, a common one-step NEET numerical.

US Curriculum Gaps - Excess Pressure

What U.S. Students Usually Miss

AP Physics 2 often treats surface tension qualitatively, not as a curved-interface pressure law

Students may know that bubbles try to shrink, but NEET expects immediate use of 2T/R, 4T/R, and the unequal-radii expression without re-deriving them each time.

  • Memorise which geometry gives one surface and which gives two.
  • Use radius comparison to predict the sign of pressure difference before calculating.

Introductory university fluids courses rarely include double-bubble interface numericals

The chapter goes beyond a single bubble and asks for the radius and curvature of the common film between two touching soap bubbles. That specific interface logic is a NEET-style differentiator.

  • Write P1 - P2 first, then match it with 4T/r for the common film.
  • Keep the film concave toward the smaller bubble because its internal pressure is greater.

Concept IQ Check - Excess Pressure

4 NEET-style MCQs with Answers
1A soap bubble and a liquid drop have the same radius R and the same surface tension T. What is the ratio of their excess pressures?Excess Pressure Formulas
1 : 1
1 : 2
2 : 1
4 : 1
For a liquid drop, excess pressure is 2T/R because there is one curved liquid surface. For a soap bubble in air, excess pressure is 4T/R because the soap film has both inner and outer liquid surfaces. Therefore the bubble-to-drop ratio is (4T/R):(2T/R) = 2:1. The wrong options come from either ignoring the second surface or doubling the relation again without reason.
2Two soap bubbles of unequal radii are connected by a tube. Which statement is correct immediately after connection?Definition and General Concept
Air flows from the larger bubble to the smaller bubble
Air flows from the smaller bubble to the larger bubble
No air flows because both are exposed to atmosphere
Both collapse at the same time
The OCR explicitly notes that excess pressure is inversely proportional to radius, so the smaller bubble has larger internal pressure. Once the two bubbles communicate, gas must move from higher pressure to lower pressure. Hence air rushes from the smaller bubble to the larger bubble, causing the small one to shrink and the larger one to expand. The atmospheric pressure outside both bubbles is common, so it does not cancel this internal-pressure difference.
3For two touching soap bubbles of radii r1 < r2, the common film isDouble Bubble Formation
plane because both are open to atmosphere
convex toward the smaller bubble
concave toward the smaller bubble
concave toward the larger bubble
The smaller bubble has internal pressure P1 = P0 + 4T/r1 and the larger bubble has P2 = P0 + 4T/r2. Since r1 < r2, P1 > P2. Excess pressure across the common film acts from its concave side to its convex side, so to sustain the larger pressure on the smaller-bubble side, the interface must be concave toward the smaller bubble and convex toward the larger bubble. A plane interface would imply zero pressure difference, which is impossible here.
4Two soap bubbles of radii 3 cm and 4 cm coalesce in vacuum. The radius of the final bubble isSingle Bubble Formation
5 cm
7 cm
√7 cm
25 cm
In vacuum the OCR relation becomes c^2 = a^2 + b^2. With a = 3 cm and b = 4 cm, c^2 = 9 + 16 = 25, so c = 5 cm. Option 7 cm comes from adding radii linearly, which is not valid. Option √7 cm comes from mishandling the squares, and 25 cm is the value of c^2, not c. NEET often uses this result as a quick one-step check on whether the student remembers the special vacuum case.

Practice Questions - Excess Pressure

Click "Reveal Answer" after attempting
1A water drop of radius 1 mm has surface tension 0.072 N/m. What is its excess pressure?
72 Pa
144 Pa
36 Pa
288 Pa
👁 Reveal Answer
Correct option: 2. For a liquid drop, ΔP = 2T/R. Substituting T = 0.072 N/m and R = 1 mm = 10^-3 m gives ΔP = 2 × 0.072 / 10^-3 = 144 Pa. Options 1 and 3 come from missing the factor 2 or halving the radius effect, while 288 Pa would correspond to treating the drop like a soap bubble.
2A soap bubble in air has radius 2 mm and surface tension 0.03 N/m. Find the excess pressure inside it.
15 Pa
30 Pa
60 Pa
120 Pa
👁 Reveal Answer
Correct option: 3. A soap bubble has two liquid surfaces, so ΔP = 4T/R. Using T = 0.03 N/m and R = 2 × 10^-3 m gives ΔP = 4 × 0.03 / (2 × 10^-3) = 60 Pa. A student who uses 2T/R gets 30 Pa, which is the standard drop-versus-bubble mistake.
3Two communicating soap bubbles have radii 1 cm and 2 cm. Which bubble expands and why?
The 1 cm bubble expands because it has lower pressure
The 2 cm bubble expands because the 1 cm bubble has higher pressure
Both remain unchanged because atmospheric pressure is same
Both burst because pressure difference cannot exist
👁 Reveal Answer
Correct option: 2. Internal pressure of a soap bubble is P0 + 4T/r, so the smaller bubble with radius 1 cm has the larger excess pressure. Gas therefore flows from the 1 cm bubble to the 2 cm bubble, causing the larger bubble to expand and the smaller one to shrink. Equal atmospheric pressure outside both bubbles does not remove the internal pressure difference.
4Two soap bubbles of radii 6 cm and 8 cm coalesce in vacuum. What is the final radius?
10 cm
14 cm
7 cm
100 cm
👁 Reveal Answer
Correct option: 1. In vacuum, coalescence obeys c^2 = a^2 + b^2. So c^2 = 6^2 + 8^2 = 36 + 64 = 100, hence c = 10 cm. Option 14 cm is the linear sum, option 7 cm is an arbitrary underestimate, and 100 cm confuses c with c^2.

NEET Physics Revision Checklist

Check off chapters as you revise

Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

Excess Pressure FAQs

Notes · Downloads · Revision · Important Questions
Why is pressure inside a bubble greater than outside?
Surface tension pulls the curved liquid surface inward and tries to contract it. Equilibrium is possible only when the material inside the bubble pushes outward strongly enough to balance that contraction, so the inside pressure must exceed the outside pressure by a definite amount called excess pressure.
Why does a soap bubble have 4T/R while a liquid drop has 2T/R?
A liquid drop has one free liquid surface in contact with air, so the curvature contribution comes once. A soap bubble is a thin liquid film with both inner and outer liquid-air surfaces, and each surface contributes the same pressure difference. That doubles the result from 2T/R to 4T/R.
Why do smaller bubbles have higher excess pressure?
All standard expressions put radius in the denominator. If surface tension stays the same, reducing radius makes 1/R larger and therefore increases excess pressure. This is why a smaller soap bubble is less stable in communication problems and tends to lose air to a larger bubble.
What is the difference between a bubble in liquid and a soap bubble in air?
A bubble in liquid encloses gas inside a single liquid surface, so its excess pressure follows the one-surface form 2T/R in the OCR table. A soap bubble in air is a liquid film with two liquid-air surfaces, so its excess pressure is 4T/R. The physical picture, not the word bubble alone, decides the formula.
Why is the common film concave toward the smaller bubble in a double bubble?
The smaller bubble has higher internal pressure because its radius is smaller. The common film must then support a larger pressure on the side of the smaller bubble. That happens when the film is concave toward the smaller bubble and convex toward the larger bubble, matching the OCR pressure-direction rule.
When should I use the coalescence equation instead of ordinary excess-pressure formulas?
Use ordinary excess-pressure formulas when the question asks for pressure difference across a known curved surface. Use the coalescence equation when two separate soap bubbles merge into one final bubble and the problem asks for final radius, surface tension, or a relation among a, b, c, and P0.
Why does the vacuum case give c^2 = a^2 + b^2?
The general isothermal relation contains the atmospheric pressure term P0(c^3 - a^3 - b^3). In vacuum, P0 = 0, so only 4T(a^2 + b^2 - c^2) = 0 remains. That directly reduces to c^2 = a^2 + b^2, which is the special shortcut used in many objective problems.
Can excess pressure ever be zero?
Yes. The OCR table states that a plane surface has ΔP = 0 because there is no curvature. Excess pressure arises from curvature of the interface; if the surface is plane, the inside and outside pressures at that interface are equal.
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Definition and General Concept

Excess Pressure Formulas

Double Bubble Formation

Single Bubble Formation

Soluble impurities decreases the angle of contact

Partially soluble impurities increases the angle of contact

A towel soaks water

Capillary action for various liquid-solid pair

Ploughing of fields

Subtopics

Definition and General Concept

Excess Pressure Formulas

Double Bubble Formation

Single Bubble Formation

Soluble impurities decreases the angle of contact

Partially soluble impurities increases the angle of contact

A towel soaks water

Capillary action for various liquid-solid pair

Ploughing of fields

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Excess Pressure > Ploughing of fields > Ploughing of fields
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Definition and General Concept

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NEET > Physics > Properties of Bulk Matter Chapters

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