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Floatation

NEET > Physics > Properties of Bulk Matter > Fluid Mechanics > Floatation

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Overview content

Topic 5 of 14 • Chapter: Fluid Mechanics • Physics

Floatation – Complete Notes, Revision, Important Questions & Downloads

This topic has three TOC blocks: Translatory Equilibrium, Rotatory Equilibrium and Stability, and Applications of Floatation. NEET tests floatation through density conditions for sinking, full immersion, or partial immersion, the role of the metacentre in stability, fraction of volume submerged or outside the liquid, and floating-platform numericals. The OCR begins by equating weight and upthrust for translatory equilibrium, then shifts to rotational stability through the relative position of metacentre and centre of gravity. That separation matters: one set of questions is about whether a body floats, and the other is about whether it stays upright when tilted.

⬇ Download Notes PDFView Important Questions →
High YieldStabilitySubmerged Fraction
Expected QuestionsQ
1
Commonly appears as a direct density or floating-fraction question and sometimes as a stability question involving the metacentre.
Time Required⏱
60 min
About 25 minutes for density and submerged-volume conditions, 15 minutes for metacentre logic, and 20 minutes for application numericals.
Difficulty⚡
Medium
The translatory formulas are short, but students often confuse stable floatation with merely floating, and they may mix centre of buoyancy with centre of gravity.
NRI USA Curriculum GapUS
Gap
Many classes stop at Archimedes Principle, while NEET expects explicit density conditions, metacentric stability, and fraction-of-volume results for floating bodies.
7Subtopics
4Practice Questions
2Free Downloads
60 minPrep Time
⬇ Get Free Downloads

NEET Weightage - Floatation

Fluid Mechanics
NEET YearQuestions from this TopicBarMarks
NEET 20240
 
0 Q
0
NEET 20230
 
0 Q
0
NEET 20221
 
1 Q
4
NEET 20210
 
0 Q
0
NEET 20200
 
0 Q
0
NEET 20190
 
0 Q
0
Total (2019-2024)1 4
A body floats when its weight equals the upthrust from the displaced liquid.
For translatory equilibrium, ρ > σ means sinking, ρ = σ means fully submerged neutral floatation, and ρ < σ means partial immersion.

Stable rotational equilibrium requires the metacentre to lie above the centre of gravity.

Applications reduce to volume fractions and platform-depression relations once Vρ = Vinσ is written correctly.
📊
0.2
Avg Questions / Year
🎯
4
Total Marks (6 yrs)
📈
Mixed
Pattern
⚠️
Medium
Difficulty

Floatation Strategy for NEET

1

Begin with translatory equilibrium Write weight equals upthrust for the floating condition before thinking about stability. That single equation identifies whether the body sinks, floats fully submerged, or floats partially submerged.

2

Use densities to predict the mode of floatation Compare body density ρ with liquid density σ first. This qualitative check tells you whether the immersed fraction should be less than one, equal to one, or impossible for floatation.

3

Treat metacentre as a stability condition A body can float and still be unstable. Rotational equilibrium depends on whether the metacentre lies above, at, or below the centre of gravity after a small tilt.

4

Convert volume fractions into density ratios From Vρ = Vinσ, you can immediately get submerged fraction, outside fraction, or compare the same body in different liquids.

5

Use the platform relation as an Archimedes extension For a floating platform, additional load causes extra displacement. The depression y directly encodes the added weight through the displaced liquid volume.

Floatation Study Materials

PDF · Cheat Sheet · MCQ Set · PYQ
📘
Full Notes - Floatation
Notes covering density conditions for floatation, metacentric stability, and application formulas for submerged fraction and floating platforms.
7 subtopicsMetacentreVolume fractions
Download Notes
📗
Formula Sheet - Floatation
Quick sheet for Vρ = Vinσ, fraction of volume outside, and the floating-platform relation mg = Aσyg.
Vρ = Vinσfout formulaPlatform depression
Download Formula Sheet
📙
MCQ Practice Questions - Floatation
MCQs focused on whether a body sinks or floats, how much remains submerged, and what the metacentre says about stability.
4 core MCQsDensity comparisonStability check
Download MCQ Set
📒
Previous Year Questions (PYQ) - Floatation
Revision set aligned with standard NEET patterns on floating fractions, metacentre position, and platform-depression numericals.
Quick revisionFraction problemsStability logic
Download PYQ Set

Floatation Subtopics

2-Column Table
Column AColumn B
Translatory Equilibrium↗
Rotatory Equilibrium and Stability↗
Applications of Floatation↗
Stream line flow↗
Laminar flow↗
Turbulent flow↗
The velocity of flow↗

Rapid Revision - Floatation

Concept → Trap → Example

1) Translatory Equilibrium

When a body floats

A body floats when its weight equals upthrust, so Vρg = Vinσg. Hence a body will float in a liquid if and only if ρ ≤ σ.

  • If ρ > σ, the body sinks because its weight exceeds upthrust.
  • If ρ = σ, the body floats fully submerged in neutral equilibrium.
  • The trap is to treat every floating body as partially immersed, which is false when densities are equal.
Example (NEET-style)A wooden block of density 600 kg/m^3 in water with density 1000 kg/m^3 has submerged fraction 600/1000 = 0.6, so 40% of its volume remains above the water.

2) Rotatory Equilibrium and Stability

Metacentre decides stability

After a small tilt, the new vertical through the shifted centre of buoyancy meets the original vertical at the metacentre M. Stable equilibrium requires M above the centre of gravity G, neutral equilibrium requires M at G, and unstable equilibrium occurs when M lies below G.

  • A floating body can satisfy translatory equilibrium and still be rotationally unstable.
  • Raising the centre of gravity makes toppling easier.
  • Students often confuse centre of buoyancy with metacentre; they are not the same point.
Example (NEET-style)A boat becomes easier to capsize if standing passengers raise the centre of gravity, because the metacentre may then fall below it during tilt.

3) Applications of Floatation

Volume fractions and floating platforms

From Vρ = Vinσ, the fraction of volume outside the liquid is fout = 1 - ρ/σ. For a floating platform, an added mass m causing extra depression y obeys mg = Aσyg.

  • The same body floats deeper in a less dense liquid because Vin must increase.
  • Comparing submerged fractions directly compares body and fluid densities.
  • The trap is to use total platform height instead of the additional depression caused by the added load.
Example (NEET-style)If a platform of area 0.5 m^2 in water sinks an extra 2 cm under a load, the added weight is 0.5 × 1000 × 0.02 × 9.8 = 98 N.

US Curriculum Gaps - Floatation

What U.S. Students Usually Miss

Courses often stop at 'object floats if less dense' and do not formalise the exact equilibrium cases

NEET expects all three cases: sinking, fully submerged neutral floatation, and partial immersion, each read from the density comparison ρ versus σ and from Vρ = Vinσ.

  • Use density comparison before calculating anything.
  • Remember that equal densities imply full immersion without sinking.

Metacentric stability is not always included in introductory buoyancy units

The OCR treats stability as a separate rotational criterion after tilt, based on the relative positions of metacentre and centre of gravity. This distinction is a typical NEET conceptual checkpoint.

  • Floatation does not automatically imply stability.
  • Metacentre above centre of gravity gives restoring tendency.

Concept IQ Check - Floatation

4 NEET-style MCQs with Answers
1A body will float in a liquid ifTranslatory Equilibrium
ρ > σ
ρ = 0
ρ ≤ σ
ρ ≥ σ
The OCR states the condition explicitly: a body floats in a liquid if and only if its density is less than or equal to the density of the liquid. If ρ > σ, its weight exceeds the maximum upthrust available for the full volume and the body sinks. Equality corresponds to full submerged floatation in neutral equilibrium.
2A floating body is in stable equilibrium whenRotatory Equilibrium and Stability
metacentre is below centre of gravity
metacentre is above centre of gravity
centre of buoyancy and centre of gravity coincide necessarily
upthrust becomes zero
After a small tilt, the restoring couple exists only if the metacentre lies above the centre of gravity. Then the lines of action of weight and upthrust generate a couple that returns the body toward its original position. If the metacentre falls below the centre of gravity, the couple overturns the body instead.
3If a body of density 0.8σ floats in a liquid of density σ, the fraction of volume outside the liquid isApplications of Floatation
0.2
0.8
1.0
1.2
For a floating body, fout = 1 - ρ/σ. With ρ = 0.8σ, we get fout = 1 - 0.8 = 0.2. That means 20% of the body remains above the liquid and 80% stays submerged. This question tests whether the density ratio is translated into the correct fraction.
4For a floating body, apparent weight isTranslatory Equilibrium
equal to actual weight
zero
negative always
equal to density
The OCR states that in floatation, weight equals upthrust. Apparent weight is actual weight minus upthrust, so it becomes zero. This is a direct consequence of translatory equilibrium for a freely floating body, not a special extra law.

Practice Questions - Floatation

Click "Reveal Answer" after attempting
1A block of density 750 kg/m^3 floats in water. What fraction of its volume is submerged?
0.25
0.50
0.75
1.00
👁 Reveal Answer
Correct option: 3. For floatation, submerged fraction is Vin/V = ρ/σ = 750/1000 = 0.75. Therefore 75% of the volume remains inside water and 25% stays above the surface.
2What fraction of the same block remains outside water?
0.75
0.25
1.25
0.50
👁 Reveal Answer
Correct option: 2. The fraction outside is fout = 1 - ρ/σ = 1 - 0.75 = 0.25. This follows directly from the submerged-fraction result and is often asked as a separate step.
3A floating platform of area 0.4 m^2 sinks by 1 cm when a body is placed on it in water. What is the weight of the body? Take g = 9.8 m/s^2.
19.6 N
39.2 N
49.0 N
98.0 N
👁 Reveal Answer
Correct option: 2. The added weight equals the extra buoyant force: W = Aσyg = 0.4 × 1000 × 0.01 × 9.8 = 39.2 N. The extra depression y, not the total depth of immersion, is the needed quantity.
4A floating body is slightly tilted and the metacentre lies below the centre of gravity. What happens?
It remains in stable equilibrium
It returns to its original position immediately
It topples further, showing unstable equilibrium
It sinks completely
👁 Reveal Answer
Correct option: 3. If the metacentre is below the centre of gravity, the couple due to weight and upthrust tends to rotate the body further away from its original position. This is the unstable case described in the OCR for rotatory equilibrium.

NEET Physics Revision Checklist

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Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

Floatation FAQs

Notes · Downloads · Revision · Important Questions
Why does a body float when its density is less than the liquid density?
Because only part of the body needs to be submerged to displace enough liquid for the upthrust to match its weight. Once weight equals buoyant force, translatory equilibrium is achieved with some volume still outside the liquid.
Can a body float fully submerged?
Yes. If the density of the body equals the density of the liquid, then the weight equals the upthrust for the full body volume. In that case the body floats fully submerged in neutral equilibrium, exactly as the OCR describes.
Why is apparent weight zero for a freely floating body?
Because for floatation the upward buoyant force equals the downward weight. Apparent weight is actual weight minus upthrust, so the two cancel. This does not mean gravity disappears; it means the fluid supplies an equal upward force.
What is the metacentre?
When a floating body is tilted slightly, the centre of buoyancy shifts because the displaced-liquid shape changes. The vertical through the new centre of buoyancy meets the original vertical at the metacentre. Its location relative to the centre of gravity decides stability.
Why can a body float but still be unstable?
Floating only requires translatory equilibrium, meaning weight equals upthrust. Stability is a rotational issue. If a small tilt produces an overturning couple because the metacentre lies below the centre of gravity, the body will still float but will capsize rather than return upright.
Why does raising the centre of gravity make a boat less stable?
A higher centre of gravity makes it easier for the metacentre to fall below it during a tilt. Once that happens, the restoring couple becomes an overturning couple. The OCR uses standing passengers in a boat as a typical example of this effect.
How do I find the fraction of a floating body outside the liquid?
Write the floating condition Vρg = Vinσg. This gives Vin/V = ρ/σ for the submerged fraction. The fraction outside is therefore 1 - ρ/σ. This is the fastest route in direct objective problems.
What does the floating-platform formula mean physically?
It says that placing a load on a floating platform forces the platform to displace additional liquid. The extra depression y measures that extra displaced volume A y, and the extra buoyant force Aσyg exactly balances the added weight.
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Translatory Equilibrium

Rotatory Equilibrium and Stability

Applications of Floatation

Stream line flow

Laminar flow

Turbulent flow

The velocity of flow

Subtopics

Translatory Equilibrium

Rotatory Equilibrium and Stability

Applications of Floatation

Stream line flow

Laminar flow

Turbulent flow

The velocity of flow

Previous
Floatation > The velocity of flow > The velocity of flow
Next
Translatory Equilibrium

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