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Doppler Effect of Light

NEET > Physics > Optics > Wave Optics > Doppler Effect of Light

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Overview content

Topic 7 of 9 โ€ข Chapter: Wave Optics โ€ข Physics

Doppler Effect of Light โ€“ Complete Notes, Revision, Important Questions & Downloads

Doppler Effect of Light covers Source Moving Towards Observer, Source Moving Away from Observer, and Doppler Broadening and Radar in one compact relativistic-use topic. NEET tests this topic through blue-shift and red-shift direction questions, through approximate formulas valid for v much less than c, and through radar frequency-shift items where the factor 2 comes from reflection. The core idea is that apparent frequency and wavelength change when source and observer move relatively, giving violet shift for approach and red shift for recession. The topic also extends naturally to spectral-line broadening and to radar-based speed detection, so it is more applied than its formula count suggests.

โฌ‡ Download Notes PDFView Important Questions โ†’
Shift FormulaApplied PhysicsNEET Utility
Expected QuestionsQ
1
usually as a redshift-violet-shift or radar-frequency question
Time Requiredโฑ
1.5 hrs
to lock approach vs recession formulas and radar factor 2
Difficultyโšก
Medium
the main challenge is choosing the correct sign and approximation
NRI USA Curriculum GapUS
Moderate
students often know the sound version better than the light version and may miss the astronomy-radar applications
3Subtopics
28+Practice Questions
4Free Downloads
1.5 hrsPrep Time
โฌ‡ Get Free Downloads

NEET Weightage & Exam Pattern

Wave Optics
NEET YearQuestions from this TopicBarMarks
20241
ย 
1 Q
4
20231
ย 
1 Q
4
20220
ย 
0 Q
0
20211
ย 
1 Q
4
20201
ย 
1 Q
4
Topic Weightage4ย 16
Approach-recession sign selection is the first filter in most Doppler-of-light questions.
The low-speed approximations are often enough for NEET, but the exact square-root forms should still be recognisable.

Radar questions are high yield because the reflected wave gives a frequency shift with an explicit factor of 2.
๐Ÿ“Š
0.8
Avg Questions / Year
๐ŸŽฏ
16
Total Marks (6 yrs)
๐Ÿ“ˆ
Direct
Pattern
โš ๏ธ
Medium
Difficulty

Preparation Strategy

1

Choose Direction Before Formula First decide whether the source is approaching or receding. That single decision tells you whether frequency increases or decreases and whether the shift is violet or red.

2

Keep Exact and Approximate Forms Together Read the square-root formulas as the exact statements and the (1 plus or minus v/c) forms as low-speed approximations. NEET may present either level depending on the question.

3

Remember Delta lambda = lambda v/c for Small Speeds This compact result lets you estimate the magnitude of redshift or violet shift without carrying the full square-root expression in easy questions.

4

Treat Radar as a Reflection Problem The factor 2 in radar comes from the reflected wave, so do not use the single-pass Doppler result directly for a target-speed question.

Download Topic Notes

PDF ยท Cheat Sheet ยท MCQ Set ยท PYQ
๐Ÿ“„
Full Topic Notes
Notes on redshift, violet shift, exact and approximate formulas, Doppler broadening, and radar applications.
PDF6 Pages
Download Notes
๐Ÿ“
Formula Sheet
Fast sheet for nu' and lambda' in both directions, Delta lambda relations, and radar frequency shift.
PDF1 Page
Download Formulas
๐ŸŽฏ
MCQ Practice
Question set on red-violet shift logic, low-speed approximation, Doppler broadening, and radar target motion.
PDF28 Questions
Download MCQs
โณ
Previous Year Questions
PYQ-style revision for astronomy shifts, wavelength change, and radar frequency-sign questions.
PDF10 Questions
Download PYQs

Topic Coverage

2-Column Table
Column AColumn B
Source Moving Towards Observerโ†—
Source Moving Away from Observerโ†—
Doppler Broadening and Radarโ†—

Quick Revision

Concept โ†’ Trap โ†’ Example

1) Source Moving Towards Observer

Violet Shift

For an approaching source, nu' = nu sqrt((1 + v/c)/(1 - v/c)) and lambda' = lambda sqrt((1 - v/c)/(1 + v/c)); for v much less than c, nu' approximately nu(1 + v/c) and lambda' approximately lambda(1 - v/c).

  • Approach makes apparent frequency larger and apparent wavelength smaller.
  • The spectral line shifts toward the violet end, so this case is called violet shift.
  • Trap: thinking approach means wavelength increases because the source is coming closer.
Example (NEET-style)If lambda = 600 nm and v/c = 10^-4, the approximate shift is Delta lambda = lambda v/c = 0.06 nm, so the observed wavelength becomes about 599.94 nm for an approaching source.

2) Source Moving Away from Observer

Red Shift

For a receding source, nu' = nu sqrt((1 - v/c)/(1 + v/c)) and lambda' = lambda sqrt((1 + v/c)/(1 - v/c)); for v much less than c, lambda' approximately lambda(1 + v/c).

  • Recession makes apparent frequency smaller and wavelength larger.
  • The spectrum shifts toward the red end, so this case is called red shift.
  • Trap: keeping the same sign pattern as the approaching case and getting the opposite spectral direction.
Example (NEET-style)If lambda = 500 nm and v/c = 2 x 10^-4 for a receding source, then lambda' is about 500.1 nm, showing a small red shift.

3) Doppler Broadening and Radar

Applications

Random thermal motion broadens spectral lines by plus or minus Delta nu = plus or minus (v/c)nu and plus or minus Delta lambda = plus or minus (v/c)lambda, while radar uses Delta nu = (2v/c)nu for an approaching target because of reflection.

  • Doppler broadening increases with particle speed and therefore with the square root of temperature.
  • Radar distinguishes moving from stationary targets by measuring the frequency change between transmitted and received waves.
  • Trap: forgetting the factor 2 in radar and using the one-way Doppler shift directly.
Example (NEET-style)If a radar sends microwaves of frequency nu to a target approaching with speed v, the reflected signal returns shifted by 2v nu / c, not v nu / c, because the effect occurs on the way to the target and again on return.

US Curriculum Gaps

Note for NRI/OCI students studying abroad.

Sound-Doppler Intuition Can Mislead

Students often carry sound-wave intuition into light questions and forget that the chapter gives exact square-root relations for light plus low-speed approximations.

  • approach means higher frequency and lower wavelength
  • exact relativistic-looking forms must be recognized

Radar Factor 2 Is a Frequent Exam Trap

Radar applications appear as short conceptual numericals, and the reflected-wave double shift is often the entire point of the question.

  • single-pass shift is not enough
  • approaching and receding targets carry opposite signs

Concept IQ Check

3 Concept MCQs
1A source of light moves toward a stationary observer. Which statement is correct?Source Moving Towards Observer
nu' < nu and lambda' > lambda
nu' > nu and lambda' < lambda
nu' = nu and lambda' = lambda
Only amplitude changes, not wavelength
For an approaching source the apparent frequency increases and the apparent wavelength decreases. That is the blue or violet shift case in the local text. Option A is the receding-source result. Option C would require no relative motion, and option D ignores that Doppler effect is explicitly about frequency and wavelength change rather than amplitude change.
2Which expression gives the approximate wavelength shift for v much less than c?Source Moving Away from Observer
Delta lambda = lambda c/v
Delta lambda = lambda v/c
Delta lambda = v/lambda c
Delta lambda = 2lambda v/c only for every case
For low speeds, the magnitude of Doppler wavelength shift is Delta lambda = lambda v/c. The sign depends on whether the source approaches or recedes, but the absolute form stays this simple. Option D overuses the radar factor 2, which belongs to reflected-wave target detection rather than every optical Doppler case. The other expressions are dimensionally or physically wrong.
3Why does the radar shift contain a factor of 2?Doppler Broadening and Radar
Because two observers are used
Because the wave is reflected, giving a double Doppler effect
Because light travels twice as fast in radar
Because the wavelength is always doubled first
The radar signal experiences Doppler change when it reaches the moving target and again when the reflected wave returns. That is why the frequency shift becomes Delta nu = 2v nu/c for an approaching target. Option A invents an extra observer, option C is false because the wave speed does not double, and option D mistakes the result for a wavelength rule rather than a reflection effect.

Practice Questions

Click "Reveal Answer" after attempting
1A source approaches an observer with v/c = 10^-4 and emits light of wavelength 500 nm. What is the approximate observed wavelength?
499.95 nm
500.05 nm
500 nm
499.5 nm
๐Ÿ‘ Reveal Answer
Correct option: A. For an approaching source, lambda' approximately lambda(1 - v/c). Therefore lambda' = 500 x (1 - 10^-4) nm = 499.95 nm. The wavelength decreases because the shift is toward the violet end.
2A receding source has actual frequency nu. Which approximate expression is correct for v much less than c?
nu' = nu(1 + v/c)
nu' = nu(1 - v/c)
nu' = nu c/v
nu' = 2nu(1 - v/c)
๐Ÿ‘ Reveal Answer
Correct option: B. For recession the apparent frequency decreases, so nu' approximately nu(1 - v/c). This is the frequency counterpart of redshift in wavelength.
3Which phenomenon explains the width of a spectral line increasing with temperature in a discharge tube?
Interference only
Doppler broadening
Polarization only
Total internal reflection
๐Ÿ‘ Reveal Answer
Correct option: B. Thermal motion causes atoms to move randomly toward and away from the detector, producing a spread in observed frequencies or wavelengths. Since the particle speed increases with temperature, the broadening also increases.
4A radar detects an approaching target. If the target speed doubles, what happens to the radar frequency shift magnitude?
It halves
It doubles
It remains unchanged
It becomes four times
๐Ÿ‘ Reveal Answer
Correct option: B. The radar shift is Delta nu = 2v nu/c, so it is directly proportional to v. Doubling the target speed therefore doubles the frequency shift magnitude.
5A star shows a redshift. What does this tell you first?
It is moving toward Earth
It is moving away from Earth
Its brightness increased
Its temperature became zero
๐Ÿ‘ Reveal Answer
Correct option: B. Redshift means the observed wavelength is larger than the actual wavelength, which occurs when the source recedes. The effect says nothing directly about brightness or zero temperature.

Physics Revision Checklist Revision Checklist

Check off chapters as you revise

Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

Frequently Asked Questions

Notes ยท Downloads ยท Revision ยท Important Questions
What is the fastest way to decide between redshift and violet shift?
Ignore the formula for one second and ask only whether the source is approaching or receding. Approach means observed wavelength decreases and the shift moves toward violet. Recession means observed wavelength increases and the shift moves toward red. That sign decision should come before any substitution.
Why does wavelength decrease when the source approaches?
Because the arriving wave crests are effectively compressed in the observer's frame, so the apparent wavelength is smaller and the apparent frequency is higher. In the chapter's language, this is the violet-shift case. The same physics with opposite motion gives redshift.
Do I always need the exact square-root formulas?
Not always. For v much less than c, NEET often allows the simpler approximate forms nu' approximately nu(1 plus or minus v/c) and lambda' approximately lambda(1 minus or plus v/c). But you should still recognize the exact expressions because some questions ask for the correct relation rather than a numerical value.
Why is the radar shift twice the ordinary shift?
Because the wave is Doppler-shifted once when it reaches the moving target and again when the reflected wave returns to the receiver. That two-step process introduces the factor 2. Students often lose this mark by using the one-way result only once.
What causes Doppler broadening in spectral lines?
Atoms in a hot gas move randomly in all directions. Some move toward the detector and some away from it, so the emitted spectral line is not observed at one exact frequency or wavelength but over a spread of values. The broader the speed distribution, the broader the line.
How is Doppler effect used in astronomy?
By measuring whether spectral lines shift toward red or violet and by how much. That lets astronomers infer whether stars or galaxies are receding or approaching and estimate their radial speeds. In the chapter, this application sits naturally beside the radar application on Earth.
Why is this topic placed in Wave Optics?
Because frequency and wavelength are wave quantities, and the observed shift is described in terms of them. Even though the applications include astronomy and radar, the underlying language remains that of waves: lambda, nu, and the change caused by relative motion.
What is the easiest mistake to avoid here?
Using the right formula with the wrong motion direction. Many students remember the algebra but substitute the approaching relation into a recession question or vice versa. The safer order is motion direction first, then shift direction, then the formula.
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Source Moving Towards Observer

Source Moving Away from Observer

Doppler Broadening and Radar

Subtopics

Source Moving Towards Observer

Source Moving Away from Observer

Doppler Broadening and Radar

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