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Force on Current Carrying Conductors

NEET > Physics > Magnetic Effects of Current and Magnetism > Magnetic Effect of Current > Force on Current Carrying Conductors

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Overview content

Topic 6 of 8 • Chapter: Magnetic Effect of Current • Physics

Force on Current Carrying Conductors – Complete Notes, Revision, Important Questions & Downloads

Force on Current Carrying Conductors begins with Force on Current Carrying Conductor, where the vector form dF = i(dl x B) sets direction and magnitude, then moves to Force Between Two Parallel Current Carrying Conductors, and finally closes with Standard Cases for Force on Current Carrying Conductors such as springs, suspended wires, and rods on rails. NEET tests this topic through force on a straight conductor, attraction versus repulsion of parallel currents, and quick equilibrium setups where magnetic force balances weight or tension. A typical example is F = BiL sin theta for a straight rod, but the real trap is deciding whether the question is about one conductor in an external field, two conductors acting on each other, or a special balance condition.

⬇ Download Notes PDFView Important Questions →
Vector ForceApplication HeavyNEET Core
Expected QuestionsQ
1-2
questions from straight-conductor force, parallel wires, or equilibrium cases
Time Required⏱
4 Hours
to separate the three force settings and practise balance-based numericals
Difficulty⚡
Medium
the formulas are short, but direction rules and special cases create frequent sign errors
NRI USA Curriculum GapUS
Moderate
many curricula cover the basic motor-force law but do less timed drill on parallel-wire force and textbook equilibrium variants
3Subtopics
42+Practice Questions
4Free Downloads
4 hrsPrep Time
⬇ Get Free Downloads

NEET Weightage & Exam Pattern

Magnetic Effect of Current
NEET YearQuestions from this TopicBarMarks
20241
 
1 Q
4
20232
 
2 Qs
8
20221
 
1 Q
4
20212
 
2 Qs
8
20201
 
1 Q
4
Topic Weightage7 28
Straight-conductor force and parallel-wire attraction or repulsion are the two most common direct-test patterns from this topic.
NEET often wraps the force law inside an equilibrium setup, so students must translate mg, tension, or rail geometry into magnetic-force balance.

The most reliable distinction is this: external magnetic field gives F = iL x B for one conductor, while another current-carrying wire first creates B and then exerts a force on the second wire.
📊
1.2
Avg Questions / Year
🎯
28
Total Marks (6 yrs)
📈
Mixed
Pattern
⚠️
Medium
Difficulty

Preparation Strategy

1

Classify the Source of the Magnetic Field Ask first whether the conductor is placed in a given external field or whether another wire is creating that field. This prevents mixing F = BiL sin theta with the force-per-length formula for parallel currents.

2

Fix Direction Before Magnitude Use Fleming's left-hand rule or the vector product direction before doing algebra. When the direction is wrong, the final sign of attraction, repulsion, or balancing current is usually wrong too.

3

Memorise the Parallel-Wire Rule Verbally Same-direction currents attract and opposite-direction currents repel. Saying this aloud before a numerical is faster and safer than trying to infer it from the diagram under time pressure.

4

Treat Standard Cases as Force Balance Problems For springs, suspended wires, and rods on rails, write the relevant force-balance equation first and only then substitute the magnetic-force expression. These questions are mechanics plus magnetism, not magnetism alone.

Download Topic Notes

PDF · Cheat Sheet · MCQ Set · PYQ
📄
Full Topic Notes
Detailed notes on conductor force, parallel-wire interaction, and standard equilibrium cases from the chapter.
PDF10 Pages
Download Notes
📝
Formula Sheet
One-page sheet for dF = i(dl x B), F = BiL sin theta, force per unit length between wires, and balance formulas.
PDF1 Page
Download Formulas
🎯
MCQ Practice
Practice set on rule-based direction, attraction-repulsion logic, and wire-equilibrium numericals.
PDF42 Questions
Download MCQs
⏳
Previous Year Questions
Selected PYQs on motor force, force between parallel wires, and balance of a current-carrying conductor.
PDF16 Questions
Download PYQs

Topic Coverage

2-Column Table
Column AColumn B
Force on Current Carrying Conductor↗
Force Between Two Parallel Current Carrying Conductors↗
Standard Cases for Force on Current Carrying Conductors↗

Quick Revision

Concept → Trap → Example

1) Force on Current Carrying Conductor

Motor Force

A current element in a magnetic field experiences dF = i(dl x B). For a straight conductor in uniform B, the magnitude becomes F = BiL sin theta, and the force stays perpendicular to both current direction and field.

  • Fleming's left-hand rule gives the force direction when current and field are perpendicular.
  • If the conductor is parallel to the field, sin theta becomes zero and no magnetic force acts.
  • Trap: a closed loop in a uniform field can have zero net force even though different segments still experience forces.
Example (NEET-style)A 0.2 m conductor carrying 3 A in a 0.5 T field at 90 degree experiences a force of BiL = 0.5 x 3 x 0.2 = 0.3 N.

2) Force Between Two Parallel Current Carrying Conductors

Wire Interaction

Two long parallel wires separated by distance a exert force per unit length mu0 i1 i2 divided by 2pi a on each other. Same-direction currents attract, while opposite-direction currents repel.

  • Each wire first produces a magnetic field at the location of the other, and that field then acts on the current in the second wire.
  • The force grows with both currents and falls as separation increases.
  • Trap: students often remember the magnitude formula but reverse attraction and repulsion when currents are opposite.
Example (NEET-style)If i1 = 5 A, i2 = 4 A, and a = 0.1 m, the force per unit length is proportional to 20 divided by 0.1, and the nature of force is attractive only if the currents run in the same direction.

3) Standard Cases for Force on Current Carrying Conductors

Equilibrium Cases

Springs, suspended wires, and rods on rails reduce to magnetic-force balance with weight, tension, or the component of gravity along the incline. The method is always to write equilibrium first and then substitute the correct magnetic-force expression.

  • A current-carrying spring contracts because adjacent turns carry current in the same direction and attract each other.
  • For a tensionless string or suspended conductor, balance requires magnetic force to equal the weight of the rod.
  • Trap: in inclined-rail problems, only the component of magnetic force along the motion balance matters, so geometry must be resolved before substitution.
Example (NEET-style)If a horizontal conductor of length L hangs in a field B and becomes tensionless, the balancing condition is BiL = mg, so the current needed is mg/BL.

US Curriculum Gaps

Note for NRI/OCI students studying abroad.

Parallel-Wire Force Is Often Under-Used

Some school treatments emphasise the single-wire motor-force law but spend less time on force per unit length between two long current-carrying wires, which NEET treats as a standard result.

  • same direction means attraction
  • inverse dependence on wire separation

Special Cases Are Really Mechanics-Magnetism Hybrids

The chapter's spring, suspended-wire, and rail examples are not pure formula recall; they require balancing magnetic force with weight or tension under the correct geometry.

  • equilibrium of a freely suspended conductor
  • component-wise balance on inclined rails

Concept IQ Check

Exam-style checks
1Two long parallel conductors carry equal currents in the same direction. The force between them is:Parallel wires
attractive
repulsive
zero
alternating in direction
Same-direction currents attract. Each wire produces a magnetic field that acts on the current in the other wire, and the resulting force directions are toward each other. This is a standard NEET memory check because the rule is short, frequently used, and easy to reverse under pressure.
2A rectangular closed loop is placed in a uniform magnetic field. Which statement is correct about the net magnetic force on the loop?Closed loop
It is always BiL.
It is always zero in a uniform field.
It depends only on the area of the loop.
It is maximum when the loop is circular.
Different segments of the loop do feel magnetic forces, but for a closed loop in a uniform magnetic field the vector sum of all length elements is zero, so the net translational force vanishes. The trap is to think zero net force means no segment force exists; torque can still be present in other contexts.

NEET Practice Questions

Click "Reveal Answer" after attempting
1A straight conductor carrying current I is placed perpendicular to a uniform magnetic field B. If its active length is doubled, the force becomes:
half
double
unchanged
zero
👁 Reveal Answer
Double. For a straight conductor at 90 degree, F = BiL. If B and I remain the same, doubling L doubles the magnetic force directly.
2Two long parallel wires carry equal currents in opposite directions. The force between them is:
attractive
repulsive
zero
independent of current
👁 Reveal Answer
Repulsive. Opposite-direction currents repel. This is the companion rule to the attraction of same-direction currents and should be recalled instantly in NEET problems.
3A conductor in a uniform magnetic field is parallel to the field direction. The magnetic force on it is:
BiL
BiL/2
zero
maximum
👁 Reveal Answer
Zero. The force on a straight conductor is F = BiL sin theta. When the conductor is parallel to B, theta is zero and sin theta becomes zero.
4A spring contracts when current passes through it because adjacent turns carry currents that are:
in opposite directions and repel
in the same direction and attract
zero everywhere
perpendicular to each other
👁 Reveal Answer
In the same direction and attract. Each neighbouring turn behaves like a nearby current-carrying loop segment with current in the same sense, so the magnetic interaction pulls the turns closer and the spring contracts.
5A suspended rod of mass m and length L becomes tensionless in a uniform magnetic field B when current i flows. The balancing condition is:
BiL = mg
Bi = mgL
B = mg/i
iL = mg
👁 Reveal Answer
BiL = mg. Tensionless means the magnetic force supports the full weight of the rod, so the upward magnetic force equals the downward gravitational force. From that relation one can solve for i = mg/BL if needed.

Physics Revision Checklist

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Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

Frequently Asked Questions

Notes · Downloads · Revision · Important Questions
What is the simplest formula for force on a straight conductor?
For a straight conductor in a uniform magnetic field, the magnitude is F = BiL sin theta, where theta is the angle between the current direction and the magnetic field.
How do I find the direction of force on a current-carrying wire?
Use Fleming's left-hand rule or the vector product direction for I L x B. The force is perpendicular to both the current direction and the magnetic field.
Why is the net force on a closed loop zero in a uniform field?
Because the vector sum of all small length elements around a closed loop is zero, so the integrated magnetic force cancels. Individual segments can still experience forces, but the total translational force vanishes.
Why do same-direction currents attract?
Each wire produces a magnetic field that exerts a force on the current in the other wire. For currents in the same direction, the force directions turn out to be toward each other.
What happens when the currents are opposite in parallel wires?
The wires repel. The magnitude formula stays the same, but the direction of the force reverses because the current direction in one wire is reversed.
Why does a current-carrying spring contract?
Neighbouring turns of the spring carry current in the same direction, so they attract each other magnetically. That attraction shortens the spring.
How do equilibrium questions become easy in this topic?
Treat them as force-balance problems. First decide which forces act and in what directions, then equate magnetic force to weight, tension, or the relevant component of gravity.
What is the most common trap in this topic?
Students often mix one-conductor force in an external field with the two-wire interaction formula. The geometry may look similar, but the source of the magnetic field and the required formula are different.
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Force on Current Carrying Conductor

Force Between Two Parallel Current Carrying Conductors

Standard Cases for Force on Current Carrying Conductors

Subtopics

Force on Current Carrying Conductor

Force Between Two Parallel Current Carrying Conductors

Standard Cases for Force on Current Carrying Conductors

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Force on Current Carrying Conductors > Standard Cases for Force on Current Carrying Conductors > Tensionless String Condition
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Force on Current Carrying Conductor

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NEET > Physics > Magnetic Effects of Current and Magnetism Chapters

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