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Modification of Newton's Laws — Special Relativity

NEET > Physics > Laws of Motion > Newton's Laws of Motion > Modification of Newton's Laws — Special Relativity

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NEET Physics — Newton's Laws of Motion

Modification of Newton's Laws — Special Relativity – Complete Notes, Revision, Important Questions & Downloads

Modification of Newton's Laws under Special Relativity covers the breakdown of classical mechanics at velocities approaching the speed of light. NEET tests: (1) the relativistic mass formula m = m₀/√(1−v²/c²) and identifying what happens to mass as v → c; (2) the concept that Newton's second law takes the form F = dp/dt (rate of change of relativistic momentum p = mv = m₀v/√(1−v²/c²)) — not F = ma at relativistic speeds; (3) qualitative effects — length contraction (L = L₀√(1−v²/c²)), time dilation (t = t₀/√(1−v²/c²)) — and the experimental evidence supporting Special Relativity. This topic marks the boundary of classical mechanics and introduces the ideas that led Einstein to the Special Theory of Relativity.

⬇ Download Notes PDFView Important Questions →
Relativistic Mass and MomentumNewton's Laws Ch.4m = m₀/√(1−v²/c²)
Expected QuestionsQ
0–1
Special Relativity modifications to Newton's Laws appear very rarely in NEET — typically as a conceptual or single-formula MCQ (e.g., 'what increases without bound as v → c?'). The topic is included as a conceptual boundary note at the end of Newton's Laws chapters in coaching material rather than as a deeply tested topic.
Time Required⏱
20 min
10 min for the three key formulas: relativistic mass, relativistic momentum (p = m₀v/√(1−v²/c²)), and the statement of F = dp/dt. 5 min for length contraction and time dilation qualitative descriptions. 5 min for conceptual MCQ practice — 'what happens as v → c?' type questions.
Difficulty⚡
Easy
NEET tests this at purely conceptual or simple substitution level. No deep derivation is expected. The three formulas must be memorised and the qualitative trends (mass → ∞, length → 0, time → ∞ as v → c) must be known. No calculus required for NEET.
NRI USA Curriculum GapUS
Low
Special Relativity is covered in AP Physics (Modern Physics unit) at a similar conceptual level — relativistic mass, time dilation, length contraction. US students typically encounter this in AP Physics C or AP Physics 2. The NEET coverage is analogous to the introductory modern physics module in US high school physics. No significant gap.
0Subtopics
4+Practice Questions
4Free Downloads
20 minPrep Time
⬇ Get Free Downloads

NEET Weightage — Modification of Newton's Laws (Special Relativity)

Newton's Laws of Motion (Chapter 4)
NEET YearQuestions from this TopicBarMarks
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Relativistic mass: m = m₀/√(1−v²/c²) = γm₀ where γ = Lorentz factor = 1/√(1−v²/c²) ≥ 1. At v = 0: m = m₀ (rest mass). As v → c: m → ∞. At v = 0.6c: γ = 1/√(1−0.36) = 1/√0.64 = 1/0.8 = 1.25, so m = 1.25m₀. At v = 0.8c: γ = 1/√(1−0.64) = 1/√0.36 = 1/0.6 = 5/3, so m = (5/3)m₀.
Newton's modified second law: F = dp/dt = d(mv)/dt = d(m₀v/√(1−v²/c²))/dt. Since m changes with v and v changes with t, this is NOT equal to m₀a. At low speeds (v << c): m ≈ m₀, dp/dt ≈ m₀a → classical F = ma recovered.

Length contraction: L = L₀√(1−v²/c²) = L₀/γ. Moving object appears shortened in the direction of motion. Time dilation: t = t₀/√(1−v²/c²) = γt₀. Moving clock appears to tick slower — time appears dilated. Energy: E = mc² = γm₀c²; rest energy E₀ = m₀c²; kinetic energy K = (γ−1)m₀c².
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How to Prepare Special Relativity Modifications for NEET

1

Memorise the three core relativistic formulas 1. Relativistic mass: m = m₀/√(1−v²/c²). 2. Relativistic momentum: p = mv = m₀v/√(1−v²/c²). 3. Modified second law: F = dp/dt (NOT F = ma). These three, plus length contraction (L = L₀/γ) and time dilation (t = γt₀), cover the entire NEET scope for this topic. Write them on a card and memorise them.

2

Know the qualitative trends as v → c As v approaches c: (a) mass m → ∞; (b) momentum p → ∞; (c) it becomes impossible to accelerate the object further (infinite force needed); (d) length (in direction of motion) → 0; (e) time interval → ∞ (clock runs infinitely slow). These trends are the most commonly tested conceptual points in NEET and competitive exams.

3

Understand why F ≠ ma at relativistic speeds At low speeds (v << c): m ≈ m₀ = constant, so F = dp/dt = d(m₀v)/dt = m₀(dv/dt) = m₀a → classical Newton's law recovered. At high speeds: m = γm₀ changes as v changes, so dp/dt = d(mv)/dt has both a (dm/dt) and a (m × dv/dt) term. The correct relativistic equation is F = dp/dt. Newton's second law is a low-velocity approximation of relativistic mechanics.

Study Materials — Modification of Newton's Laws (Special Relativity)

PDF · Cheat Sheet · MCQ Set · PYQ
📘
Full Notes
Why Newton's laws fail at high speeds. Relativistic mass derivation. Modified second law F = dp/dt. Length contraction, time dilation, mass-energy equivalence. Classical limit recovery. NEET formulas.
Single topic2 pagesConcept + Formula
Download Notes
📗
Formula Sheet
m = γm₀; p = γm₀v; F = dp/dt; L = L₀/γ; t = γt₀; E = γm₀c²; γ = 1/√(1−v²/c²); at v ≪ c: m → m₀, F → ma.
6 formulas1 pageQuick reference
Download Sheet
📙
MCQ Practice
10 MCQs: relativistic mass at given v, momentum comparison, conceptual questions on what happens as v → c, F = dp/dt application, length contraction and time dilation comparisons.
10 MCQsAll variantsSolved
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📒
PYQ
Year-tagged NEET questions on relativistic mechanics concepts.
1+ year-tagged Qs2015–2024Solved
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2-Column Table
Column AColumn B

Rapid Revision — Modification of Newton's Laws (Special Relativity)

Concept → Trap → Example

1) Why Newton's Laws Break Down at High Speeds

Core Concept

Newton's second law F = ma was derived from classical mechanics where mass is constant. Einstein's Special Theory of Relativity (1905) showed that mass is NOT constant — it increases with velocity. The correct relativistic relation is: m = m₀/√(1−v²/c²) where m₀ is the rest mass (mass when the object is at rest) and c is the speed of light (≈ 3×10⁸ m/s). As v → c, the denominator → 0, so m → ∞. This means infinite force would be needed to accelerate an object to the speed of light — explaining why no material object can reach c. Newton's second law is thus an approximation valid only when v << c.

  • The Lorentz factor γ = 1/√(1−v²/c²) ≥ 1 for all velocities (equals 1 at v = 0; increases without bound as v → c). All relativistic quantities are expressed in terms of γ: m = γm₀, p = γm₀v, E = γm₀c², L = L₀/γ, t = γt₀. γ is the 'correction factor' that classical mechanics ignores. For everyday motions (even airplane at 900 km/h = 250 m/s): v/c ≈ 250/(3×10⁸) ≈ 10⁻⁶ — negligible. γ ≈ 1 to 1 part in 10¹². Classical mechanics is perfectly adequate.
  • The modified Newton's second law: F = dp/dt where p = γm₀v is the relativistic momentum. At low speeds (v << c): γ ≈ 1, p ≈ m₀v, so F = d(m₀v)/dt = m₀(dv/dt) = m₀a. Classical law recovered. At high speeds: dp/dt has two contributions — the mass−acceleration term AND the velocity×(dm/dt) term. Expanding: F = m(dv/dt) + v(dm/dt). Both terms matter at relativistic speeds.
  • Experimental evidence for relativistic mass: (1) Particle accelerators — protons in the LHC are accelerated to 0.9999999c. At this speed γ ≈ 7461, so m ≈ 7461×m_proton. It takes enormously more energy to increase velocity slightly (the 'wall' near c). (2) Muon decay — muons created in the upper atmosphere by cosmic rays travel far enough to reach the Earth's surface. In their rest frame, they should decay before reaching Earth. But time dilation (their 'clock runs slow' relative to Earth) allows them to survive. (3) Mass-energy equivalence E = mc² confirmed in nuclear reactions.
Example (NEET-style)An electron (rest mass m₀ = 9.1×10⁻³¹ kg) moves at v = 0.9c. Find its relativistic mass. γ = 1/√(1−(0.9c)²/c²) = 1/√(1−0.81) = 1/√0.19 ≈ 1/0.436 ≈ 2.294. m = γm₀ = 2.294 × 9.1×10⁻³¹ ≈ 2.09×10⁻³⁰ kg. The electron's relativistic mass is about 2.3 times its rest mass at 90% of the speed of light. At v = 0.99c: γ ≈ 7.09. At v = 0.999c: γ ≈ 22.4. As v → c, the mass required increases dramatically, making further acceleration increasingly difficult.

2) Length Contraction and Time Dilation

Relativistic Effects

Two equally important consequences of Special Relativity, both following from γ: (1) Length contraction: an object moving at speed v appears (to a stationary observer) to be contracted in the direction of motion: L = L₀√(1−v²/c²) = L₀/γ. The object's proper length L₀ (measured in its rest frame) shrinks by factor γ when measured from a frame in which it moves. (2) Time dilation: a clock moving at speed v appears (to a stationary observer) to run slow: time interval t = t₀/√(1−v²/c²) = γt₀ where t₀ is the proper time (time in the rest frame of the clock). Moving clocks run slow — a moving person ages more slowly relative to a stationary observer.

  • Length contraction is only in the direction of motion. Dimensions perpendicular to the motion are unaffected. A moving sphere remains a sphere — wait, it actually becomes an oblate shape because the direction of motion contracts while perpendicular dimensions remain the same. For NEET: a rod moving along its length contracts to L = L₀/γ. A rod moving perpendicular to its length has unchanged length. Key test: direction matters.
  • Time dilation: t_moving = γ × t_rest. If t₀ = 1 second on a moving clock, a stationary observer measures γ seconds. The twin paradox: one twin travels at near-c, returns to find the other twin aged more — the travelling twin's clock ran slower. Muon experiment: the muon's lifetime is dilated from the Earth's perspective — it 'lives longer' in the Earth's frame due to time dilation, allowing it to reach the surface. Time dilation is well verified experimentally (GPS clocks, particle accelerators, muon experiments).
  • Mass-energy equivalence: E = mc² = γm₀c². Rest energy: E₀ = m₀c² (energy equivalent of rest mass). Kinetic energy (relativistic): K = (γ−1)m₀c² (NOT ½m₀v² except at low speeds). Total energy E = rest energy + kinetic energy = m₀c² + K = γm₀c². Note: at low speeds γ ≈ 1 + v²/(2c²), so K ≈ m₀c²(1 + v²/2c² − 1) = m₀v²/2 = ½m₀v² ✓ (classical KE recovered).
Example (NEET-style)A spaceship of proper length L₀ = 300 m moves at v = 0.8c relative to Earth. What length does an Earth observer measure? γ = 1/√(1−0.64) = 1/√0.36 = 1/0.6 = 5/3. L = L₀/γ = 300/(5/3) = 300×3/5 = 180 m. The spaceship appears 180 m long to Earth observers (contracted from 300 m to 180 m). Time dilation: if the spaceship's clock shows t₀ = 10 years, Earth observers measure t = γt₀ = (5/3)×10 = 16.7 years for the same journey. The astronaut ages 10 years; Earth ages 16.7 years for the same trip — the core of the twin paradox.

3) Recovering Classical Mechanics: Low Velocity Limit

Conceptual

All relativistic formulas reduce to their classical counterparts when v << c. This is called the classical limit or correspondence principle: new physics (relativity, quantum mechanics) must replicate old physics (Newton's laws) in the appropriate limit. For v << c: v²/c² ≈ 0, so √(1−v²/c²) ≈ 1 − v²/(2c²) ≈ 1 (first order). Therefore: (1) m ≈ m₀ (mass is constant — Newton's assumption) (2) p ≈ m₀v (linear momentum) (3) F = dp/dt ≈ m₀(dv/dt) = m₀a (Newton's second law). (4) K ≈ ½m₀v² (classical KE). The entire framework of classical mechanics is an approximation valid when v << c.

  • Why we don't notice relativistic effects in daily life: the fastest human-made object is the Voyager 1 spacecraft at ~17 km/s = 1.7×10⁴ m/s. v/c ≈ 5.7×10⁻⁵. γ = 1/√(1−(5.7×10⁻⁵)²) ≈ 1 + (1.6×10⁻⁹) ≈ 1.0000000016. The relativistic correction is less than 2 parts per billion — completely unmeasurable in classical experiments. Even at 10,000 km/s (Earth-Sun distance in about 15 seconds), v/c ≈ 0.033 and γ ≈ 1.0006. Only at v > 0.1c (10% of light speed) do relativistic effects become noticeable (γ ≈ 1.005).
  • NEET context: the reason this topic appears at the end of Newton's Laws chapters is to acknowledge the scope of classical mechanics, not to require deep relativistic calculations. NEET tests: (a) the formula m = m₀/√(1−v²/c²) — usually a substitution; (b) the qualitative fact that mass increases with velocity (not decreases); (c) F = dp/dt is the more general form (not F = ma); (d) the concept of rest mass vs observed mass. Complex tensor-form relativistic mechanics is NOT in NEET scope.
  • Mass-energy equivalence E = mc² and nuclear physics: although E = mc² is derived from Special Relativity, NEET covers it primarily in the Nuclear Physics chapter (Binding Energy, Mass Defect). When Δm of mass is converted: ΔE = Δm×c². For NEET's Newton's Laws chapter, the focus is on relativistic mass increasing with velocity. The nuclear applications are tested separately.
Example (NEET-style)At what velocity is the relativistic mass of a particle exactly twice its rest mass? Set m = 2m₀: 2m₀ = m₀/√(1−v²/c²) → √(1−v²/c²) = 1/2 → 1−v²/c² = 1/4 → v²/c² = 3/4 → v = (√3/2)c ≈ 0.866c. At v ≈ 86.6% of the speed of light, the particle's relativistic mass is twice its rest mass. This is a standard NEET-level question — the algebra involves setting up m = nm₀ and solving for v.

US Curriculum Gaps — Modification of Newton's Laws (Special Relativity)

Topics in this section are tested in NEET but organised differently in standard US physics courses.

Relativistic Mass Formula in Newton's Laws Context (Moderate Overlap with AP Physics)

AP Physics 2 and AP Physics C both cover Special Relativity concepts including relativistic mass, time dilation, and length contraction. However, AP Physics 1 does not. The NEET context is slightly different — NEET introduces relativistic mechanics at the end of Newton's Laws (Chapter 4) as a 'modification/limitation' of classical mechanics. AP Physics 2 covers Special Relativity as a separate standalone unit. The scope overlap is high for AP Physics 2 students; students who only took AP Physics 1 would find this concept new.

  • NEET: m = m₀/√(1−v²/c²) — relativistic mass increases with velocity
  • NEET: F = dp/dt (more general form, reduces to F = ma at low speeds)
  • AP Physics 2: same formulas tested at comparable conceptual level

Connection Between Newton's Laws and Relativistic Mechanics (Pedagogical Gap)

NEET explicitly teaches relativistic mechanics as a 'modification of Newton's Laws' — showing that F = dp/dt is more fundamental, and F = ma is a special case. This explicit pedagogical connection (classical → relativistic) is less emphasized in AP Physics, where Special Relativity is typically taught as a separate topic in Modern Physics, disconnected from Newton's Laws chapters. NEET students see a unified view: Newton is an approximation; Einstein is the complete theory.

  • NEET: explicitly frames relativity as modifying Newton's second law
  • NEET: derivation of classical law recovery from F = dp/dt at v << c
  • AP: relativity treated as separate modern physics unit without explicit connection to Newton's law limitations

NEET-Style Practice Questions — Modification of Newton's Laws (Special Relativity)

4 Questions
1According to the special theory of relativity, as a body moves with velocity approaching the speed of light, its mass:Relativistic Mass
Increases and approaches infinity
Decreases and approaches zero
Remains constant (equal to rest mass)
Increases and approaches twice the rest mass
m = m₀/√(1−v²/c²). As v → c: the denominator √(1−v²/c²) → 0, so m → ∞. Relativistic mass increases without bound as velocity approaches c. This is why no material object can reach the speed of light — it would require infinite energy to do so. Option B is wrong: mass never decreases. Option C is the classical (wrong) assumption. Option D is wrong — mass doesn't stop at 2m₀; it continues to increase.
2An electron travels at a speed v = 0.6c. If the rest mass of the electron is m₀, what is its relativistic mass?Relativistic Mass Calculation
1.25 m₀
1.6 m₀
0.8 m₀
2.0 m₀
γ = 1/√(1−v²/c²) = 1/√(1−(0.6c)²/c²) = 1/√(1−0.36) = 1/√0.64 = 1/0.8 = 1.25. m = γm₀ = 1.25m₀. At 60% of the speed of light, the electron's mass is 25% greater than its rest mass. Common mistake: computing 1−v²/c² = 1−0.6 = 0.4 (wrong — must square: (0.6c)²/c² = 0.36). √0.64 = 0.8 exactly (a perfect Pythagorean triple: 3-4-5 gives 0.6c, 0.8, 1.0).
3The correct form of Newton's second law at relativistic speeds is:Modified Newton's Law
F = dp/dt where p = m₀v/√(1−v²/c²)
F = m₀a always
F = ma where m is constant
F = d(m₀v)/dt where m₀ is rest mass
At relativistic speeds, mass m = m₀/√(1−v²/c²) varies with velocity. The correct relativistic form of Newton's second law is F = dp/dt where p = mv = m₀v/√(1−v²/c²) is the relativistic momentum. Option B (F = m₀a) is the classical limit valid only when v << c. Option C says mass is constant — incorrect at relativistic speeds. Option D is also incorrect because it uses d(m₀v)/dt = m₀(dv/dt) = m₀a, ignoring the variation of mass — this is the classical approximation.
4A body of rest mass m₀ moves at velocity v = (√3/2)c. Its kinetic energy at this speed is approximately:Relativistic KE
m₀c²
½m₀v² ≈ 3m₀c²/8
2m₀c²
m₀c²/2
v = (√3/2)c. γ = 1/√(1−v²/c²) = 1/√(1−3/4) = 1/√(1/4) = 1/(1/2) = 2. Relativistic KE = (γ−1)m₀c² = (2−1)m₀c² = m₀c². The kinetic energy equals m₀c² (the rest energy). Classical KE = ½m₀v² = ½m₀×(3/4)c² = (3/8)m₀c² (underestimates: 0.375m₀c² vs 1.0m₀c² — classical is 62% low at this speed). The formula K = (γ−1)m₀c² is the exact relativistic kinetic energy. At low speeds: γ ≈ 1 + v²/2c², so K ≈ ½m₀v² (classical ✓).

Practice Problems — Modification of Newton's Laws (Special Relativity)

Click "Reveal Answer" after attempting
1A particle moves with velocity v = 0.8c. Calculate: (a) the Lorentz factor γ, (b) its relativistic mass if rest mass = 2 kg, (c) ratio of relativistic KE to classical KE (½m₀v²).
(a) γ = 5/3; (b) m = 10/3 kg; (c) ratio ≈ 1.94
(a) γ = 4/3; (b) m = 8/3 kg; (c) ratio = 2.0
(a) γ = 5/3; (b) m = 4 kg; (c) ratio = 1.5
(a) γ = 2; (b) m = 4 kg; (c) ratio = 2.0
👁 Reveal Answer
(a) v = 0.8c: γ = 1/√(1−0.64) = 1/√0.36 = 1/0.6 = 5/3 ≈ 1.667. (b) m = γm₀ = (5/3)×2 = 10/3 ≈ 3.33 kg. (c) Relativistic KE = (γ−1)m₀c² = (5/3−1)×2c² = (2/3)×2c² = 4c²/3. Classical KE = ½m₀v² = ½×2×(0.8c)² = 0.64c². Ratio = (4c²/3)/(0.64c²) = (4/3)/0.64 = 4/(3×0.64) = 4/1.92 ≈ 2.08. Note: classical KE underestimates by about 50% at v = 0.8c. Answer: γ = 5/3, m = 10/3 kg, ratio ≈ 2.08.
2A spaceship of rest length 500 m moves at v = 0.6c. (a) What is its measured length from Earth? (b) If the ship's clock shows a journey time of 4 years, how many years pass on Earth?
(a) 400 m; (b) 5 years
(a) 300 m; (b) 5 years
(a) 400 m; (b) 4 years
(a) 250 m; (b) 6.67 years
👁 Reveal Answer
(a) γ = 1/√(1−0.36) = 1/0.8 = 1.25. L = L₀/γ = 500/1.25 = 400 m. The spaceship appears 400 m long from Earth (contracted from 500 m). (b) t_Earth = γ × t_ship = 1.25 × 4 = 5 years. Earth clocks run 25% faster relative to the moving ship's clock. The astronaut experiences 4 years; 5 years pass on Earth. Note: the spaceship's clock is 'dilated' — it runs slow from Earth's perspective. Correct answer: (a) 400 m; (b) 5 years.
3Show that the relativistic kinetic energy formula K = (γ−1)m₀c² reduces to the classical formula K = ½m₀v² when v << c. Hence, for v = 0.01c, find the fractional error in using the classical formula.
Error ≈ 0.0025 (0.25%)
Error = 0.01 (1%)
Error = 0.005 (0.5%)
Error ≈ 0.0075 (0.75%)
👁 Reveal Answer
Expansion: γ = (1−v²/c²)^(−1/2) ≈ 1 + v²/(2c²) + 3v⁴/(8c⁴) + ... for v << c. K = (γ−1)m₀c² ≈ [v²/(2c²) + 3v⁴/(8c⁴)]m₀c² = ½m₀v² + 3m₀v⁴/(8c²) + ... → classical KE ½m₀v² as leading term ✓. For v = 0.01c: v²/c² = 10⁻⁴. Classical K = ½m₀(0.01c)² = 5×10⁻⁵m₀c². Relativistic K = (γ−1)m₀c² where γ ≈ 1 + 5×10⁻⁵ + 3/(8)×10⁻⁸ → K_rel ≈ m₀c²×5×10⁻⁵(1 + 3v²/(4c²)) ≈ 5×10⁻⁵m₀c²×(1 + 7.5×10⁻⁵). Fractional error = 3v²/(4c²) = 3×10⁻⁴/4 = 7.5×10⁻⁵ ≈ 0.0075% (very small). The classical formula is extremely accurate at 1% of c — confirms why we don't notice relativistic effects in everyday life.
4A proton (rest mass m₀) is accelerated to v = (4/5)c in a particle accelerator. Compare: (a) its relativistic momentum to classical momentum (m₀v), (b) its total energy to its rest energy.
(a) p_rel/p_classical = 5/3; (b) E_total/E_rest = 5/3
(a) p_rel/p_classical = 4/3; (b) E_total/E_rest = 4/3
(a) p_rel/p_classical = 5/4; (b) E_total/E_rest = 5/3
(a) p_rel/p_classical = 5/3; (b) E_total/E_rest = 4/3
👁 Reveal Answer
v = 4c/5 = 0.8c. γ = 1/√(1−0.64) = 1/0.6 = 5/3. (a) p_rel = γm₀v = (5/3)m₀v. p_classical = m₀v. Ratio = 5/3. The relativistic momentum is 5/3 times the classical momentum at v = 0.8c. (b) E_total = γm₀c² = (5/3)m₀c². E_rest = m₀c². Ratio = 5/3. The total energy (including kinetic energy contribution) is 5/3 of the rest energy. Kinetic energy = (γ−1)m₀c² = (2/3)m₀c² = (2/3)E_rest. So: Total Energy = Rest Energy + (2/3) Rest Energy = 5/3 Rest Energy ✓.

Physics — Newton's Laws of Motion Revision Checklist

Check off chapters as you revise

Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

FAQ — Modification of Newton's Laws (Special Relativity)

Notes · Downloads · Revision · Important Questions
Why does mass increase with velocity? Is this real or just apparent?
In Einstein's Special Relativity, as an object's velocity increases relative to an observer, its 'relativistic mass' (or inertia) increases. This is a real physical effect — more force is required to increase the velocity by the same amount as the object speeds up. In modern physics language, physicists often prefer to say that the rest mass m₀ is constant and it's the momentum p = γm₀v that accounts for the increased inertia, but the net result is the same: the object resists acceleration more as v → c. This has been directly measured in particle accelerators.
What is 'rest mass' and why does it matter?
Rest mass (m₀) is the mass of an object when measured in its own rest frame (when it is not moving relative to the observer). It is an intrinsic property of the particle — a fundamental constant for particles like proton (1.67×10⁻²⁷ kg), electron (9.1×10⁻³¹ kg). The relativistic mass m = γm₀ depends on the reference frame (depends on v, which depends on who is observing). Rest mass is a Lorentz invariant — all observers agree on m₀, regardless of relative velocity. NEET uses m₀ for rest mass in the relativistic mass formula.
Can anything travel at the speed of light?
Photons (light quanta) travel at exactly c and have zero rest mass. For photons: m = m₀/√(1−v²/c²) = 0/0 (indeterminate form) — the formula breaks down because photons are always at c and have zero rest mass. Photons have relativistic energy E = pc (not E = mc²) and relativistic mass m_rel = E/c² = hf/c² (where h is Planck's constant, f is frequency). Material objects (non-zero rest mass) can never reach c: it would require infinite energy. No object with mass has ever been observed to reach c.
Is F = dp/dt always valid, even relativistically?
Yes — F = dp/dt is the fundamental form of Newton's second law that remains valid in Special Relativity (with relativistic momentum p = γm₀v). It is valid for all speeds from v = 0 to v ≈ c. At low speeds: p ≈ m₀v, dp/dt ≈ m₀a → classical F = ma. The only regime where even F = dp/dt breaks down is at quantum scales (quantum mechanics replaces classical mechanics) or in curved spacetime (General Relativity replaces Special Relativity). For NEET, F = dp/dt is the accepted general form of Newton's second law.
What is time dilation and why does it happen?
Time dilation: a moving clock runs slower than a stationary one. If a clock in a rocket measures time interval t₀ (proper time), a stationary (Earth) observer measures t = γt₀ > t₀. The rocket astronaut ages more slowly. This is not a trick of optics — it is a real physical effect caused by the constancy of the speed of light. Einstein derived it from two postulates: (1) the laws of physics are the same in all inertial frames; (2) the speed of light is the same in all inertial frames. Time dilation has been confirmed by: atomic clocks on airplanes (measured difference from ground clocks), GPS satellite clock corrections, muon lifetime experiments.
For NEET, what level of depth is required for Special Relativity?
NEET requires: (1) The relativistic mass formula m = m₀/√(1−v²/c²) — ability to calculate m given m₀ and v; (2) The qualitative trend: mass increases as v → c; (3) F = dp/dt is more general than F = ma; (4) Length contraction: L = L₀/γ (qualitative understanding, possibly one calculation); (5) Time dilation: t = γt₀ (qualitative understanding). NEET does NOT require: derivation of the Lorentz transformation, four-vectors, tensor formulation of relativistic mechanics, relativistic collision problems beyond simple one-line calculations, or jet any detailed relativistic quantum mechanics.
How is E = mc² connected to Newton's Laws?
Einstein derived E = mc² from Special Relativity — specifically from the work-energy theorem applied to a relativistic particle. The total energy of a particle E = γm₀c²; at rest (v=0, γ=1): E = m₀c² (rest energy, even when not moving). When the particle moves: E = γm₀c² includes both rest energy and kinetic energy. The 'modification' to Newton's laws introduces the concept that mass itself is a form of energy. For NEET's Newton's Law chapter: E = mc² is mentioned as a consequence of relativistic modifications. The detailed nuclear energy applications are in the Nuclear Physics chapter.
Why is γ always ≥ 1?
γ = 1/√(1−v²/c²). For any real material object, 0 ≤ v < c (objects with mass always move slower than c). So 0 ≤ v²/c² < 1, meaning 0 < (1−v²/c²) ≤ 1, meaning 1 ≥ √(1−v²/c²) > 0, meaning γ = 1/[something ≤ 1] ≥ 1. At v = 0: γ = 1 (minimum). As v → c: γ → ∞ (maximum). γ = 1 exactly only for a particle at rest. γ > 1 for any moving particle. Therefore relativistic mass m = γm₀ ≥ m₀ always — mass never decreases with velocity.
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Perfect physical balance

Force cause acceleration

A single isolated force cannot exist

The beam balance compares masses

None of the above

Change the direction

Keep it moving with uniform velocity

He leans forward as a matter of habit

Speed of motion

Both (b) and (c)

False balance

A system or a body

Absolute units of force

A particle

Subtopics

Perfect physical balance

Force cause acceleration

A single isolated force cannot exist

The beam balance compares masses

None of the above

Change the direction

Keep it moving with uniform velocity

He leans forward as a matter of habit

Speed of motion

Both (b) and (c)

False balance

A system or a body

Absolute units of force

A particle

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Modification of Newton's Laws — Special Relativity > A particle > A particle
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Perfect physical balance

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