100k Followers100k500k Followers500k+1 (510) 706-9331+1 (510) 706-9331
Schedule Your Free Exam Readiness Analysis Session!
Testprepkart Logo
Sign InEnroll NowEnroll
Select an exam to view its content.
  • Blog
  • Download
  • Course
  • Result
  • Video Library
  • Pages
  • Notifications

Loading...

Preparing content

Testprepkart Logo

Enabling students prepare and crack toughest examinations worldwide for over a decade with problem solving aptitude!

Contact Us

Useful Links

  • Connect With Counselor
  • University Admissions
  • Prime Videos
  • Enrollment Form
  • Online Fee Payment
  • Testprepkart Operations
  • Faculty Registration

Our Company

  • Contact Us
  • Work With Us
  • Blogs
  • Facultie
  • Partner

Contact Details

  • Phone: +91 0120 4525484
  • Whatsapp: +1 (510) 706-9331
  • Admission: +91 8800123492
  • E-mail: info@testprepkart.com
  • Head Office: F 377, Sector 63, Noida, Uttar Pradesh, India

Copyright © 2024 CounselKart Educational Services Pvt. Ltd.. All Rights Reserved

Terms of service|Privacy policy|Refund Policy|Login & Register

Types of Friction

NEET > Physics > Laws of Motion > Friction > Types of Friction

Unit Progress

0%

Overview content

NEET Physics — Friction

Types of Friction – Complete Notes, Revision, Important Questions & Downloads

Types of Friction classifies friction into four distinct categories based on the state of motion between surfaces: Static Friction (self-adjusting, acts when there is no relative motion, f_s ≤ μ_s N), Limiting Friction (maximum static friction at the threshold of motion, f_l = μ_s N), Kinetic / Dynamic Friction (acts during relative sliding, f_k = μ_k N with μ_k < μ_s), and Rolling Friction (opposes rolling, F_rolling = μ_r R/r, smallest of all types). NEET tests: (1) identifying which type of friction acts in a given scenario; (2) applying the correct formula — f_l = μ_s N for limiting, f_k = μ_k N for kinetic, F_rolling = μ_r R/r for rolling; (3) the fundamental inequality μ_rolling < μ_kinetic < μ_static demonstrating that rolling friction is least and static the greatest; (4) properties of kinetic friction — constant magnitude, independent of velocity and contact area, always less than limiting friction; (5) why rolling friction exists despite no surface rubbing — due to deformation at the contact region. Understanding all four types with their formulas, conditions, and mutual comparisons is the complete foundation for all NEET friction problems.

⬇ Download Notes PDFView Important Questions →
Static, Limiting, Kinetic, RollingFriction Ch.5μ_k < μ_s
Expected QuestionsQ
1–2
Types of Friction is the most foundational and high-yield section of the Friction chapter. NEET regularly tests: identifying type of friction from a scenario; applying f = μN for limiting and kinetic; the μ_k < μ_s inequality; properties of kinetic friction (velocity independence); and rolling friction formula. Friction as a chapter contributes 1–3 questions per NEET paper.
Time Required⏱
45 min
15 min to master all four types with definitions, conditions, and formulas. 15 min on the laws: μ_k < μ_s; friction independent of area and velocity; properties of rolling friction. 15 min working NEET-style MCQs on all four types.
Difficulty⚡
Medium
Multiple friction types and three separate formulas (f_l = μ_s N, f_k = μ_k N, F_rolling = μ_r R/r) must be distinguished clearly. NEET traps: confusing which type acts in a scenario; forgetting that μ_k < μ_s; confusing rolling friction proportionality (inversely proportional to radius). Once the four-type taxonomy is clear, application is straightforward.
NRI USA Curriculum GapUS
Low
AP Physics 1 covers static and kinetic friction thoroughly. Rolling friction is mentioned but formulas are not always derived. The term 'limiting friction' for maximum static friction is specific to Indian curricula; US courses call it 'maximum static friction'. The four-type classification (static, limiting, kinetic, rolling) is more explicit in NCERT than in AP Physics 1 textbooks.
4Subtopics
4+Practice Questions
4Free Downloads
45 minPrep Time
⬇ Get Free Downloads

NEET Weightage — Types of Friction

Friction (Chapter 5)
NEET YearQuestions from this TopicBarMarks
20242
 
2 Q
8
20231
 
1 Q
4
20222
 
2 Q
8
20211
 
1 Q
4
20202
 
2 Q
8
20191
 
1 Q
4
6-Year Total (2019–2024)7–10 28–40
Static friction (f_s): acts when body is at rest with an applied force. Self-adjusting: f_s = P (applied force) up to f_l = μ_s N. If P = 0, f_s = 0. NEET scenario: 'A block rests on a surface under a 5 N applied force. μ_s = 0.6, N = 50 N. Friction force = ?' → f_s = 5 N (static, self-adjusting, since 5 N < f_l = 30 N). Never apply f = μN when the block is at rest and the applied force is less than limiting friction.
Limiting friction (f_l = μ_s N): maximum static friction. At this value, the body is at the verge of motion (impending motion). Once P > f_l, motion begins. Transition: at the instant motion starts, friction drops from f_l (= μ_s N) to f_k (= μ_k N). Since μ_k < μ_s, kinetic friction is less than limiting friction. This transition is clearly shown on the friction vs applied force graph.

Kinetic friction (f_k = μ_k N): constant magnitude once in motion. Key properties: (a) independent of velocity; (b) independent of contact area; (c) depends on μ_k (surface materials); (d) always less than limiting friction (μ_k < μ_s). Rolling friction (F_rolling = μ_r R/r): directly proportional to normal reaction R; inversely proportional to radius r of the rolling body. μ_r has dimensions of length (metres). Rolling < Kinetic < Limiting (Static) in general.
📊
1.5
Avg Questions / Year
🎯
36
Total Marks (6 yrs)
📈
Direct
Pattern
⚠️
Medium
Difficulty

How to Prepare Types of Friction for NEET

1

Build a clear four-type taxonomy with exact conditions Static friction (body at rest, P ≤ f_l, f_s = P): the self-adjusting type. Limiting friction (body at verge of motion, P = f_l, f_l = μ_s N): the threshold. Kinetic friction (body in motion, f_k = μ_k N): constant and velocity-independent. Rolling friction (body rolling, F_rolling = μ_r R/r): least of all. Write these four side-by-side with their formulas and conditions. NEET question: given P and μ, determine which type acts and what its magnitude is.

2

Memorise the three friction inequalities Three key inequalities: (1) f_k < f_l (kinetic < limiting); (2) μ_k < μ_s (coefficient comparison); (3) μ_rolling < μ_kinetic in practical systems. The first two are tested as True/False MCQs in NEET. 'Kinetic coefficient is equal to static coefficient' → FALSE. 'More force is needed to start motion than to maintain it' → TRUE (because f_l > f_k). 'Rolling friction is less than sliding friction' → TRUE.

3

Practice the four friction type identification problems Given a scenario, identify: (a) Is the body at rest? → Static (f_s = P) or at verge (f_l = μ_s N). (b) Is the body sliding? → Kinetic (f_k = μ_k N). (c) Is the body rolling? → Rolling (F_rolling = μ_r R/r). The most common NEET trap is applying f = μ_s N when the body is at rest but P < f_l. Correct: f_s = P (not μ_s N) when the block hasn't reached the verge of motion.

Study Materials — Types of Friction

PDF · Cheat Sheet · MCQ Set · PYQ
📘
Full Notes
All four friction types: static (f_s = P, self-adjusting), limiting (f_l = μ_s N, threshold), kinetic (f_k = μ_k N, constant), rolling (F_rolling = μ_r R/r, least). Key inequalities: μ_k < μ_s, rolling < sliding. Properties of kinetic friction (velocity-independent, area-independent). Rolling friction mechanism (deformation at contact). All formulas with dimensions.
4 subtopics2 pagesAll formulas
Download Notes
📗
Formula Sheet
f_s ≤ μ_s N (static, range); f_l = μ_s N (limiting, at verge); f_k = μ_k N (kinetic, in motion); F_rolling = μ_r R/r (rolling); μ_k < μ_s; μ_r has dimensions of length [L].
6 formulas1 pageQuick reference
Download Sheet
📙
MCQ Practice
10 MCQs: identify friction type from scenario, apply f = μN, compare μ_k and μ_s, rolling friction formula, velocity independence, area independence, friction graph interpretation.
10 MCQsAll 4 typesSolved
Download MCQs
📒
PYQ
Year-tagged NEET questions on friction type identification, coefficient comparison, properties of kinetic friction, and rolling vs sliding friction.
4+ year-tagged Qs2015–2024Solved
Download PYQs

2-Column Table
Column AColumn B
Static Friction↗
Limiting Friction↗
Kinetic / Dynamic Friction↗
Rolling Friction↗

Rapid Revision — Types of Friction

Concept → Trap → Example

1) Static Friction — Self-Adjusting Nature and Range

Static Friction

Static friction is the friction force that acts when a body is at rest but a force P is applied — the body remains stationary because static friction exactly cancels P. This is the 'self-adjusting' nature: f_s = P (equals applied force) for any P from 0 to the limiting value f_l = μ_s N. Key range: 0 ≤ f_s ≤ μ_s N. At P = 0: f_s = 0 (no applied force, no tendency of motion → no friction). At P = f_l: the body is on the verge of motion (impending motion, limiting condition). At P > f_l: the body starts moving — static friction is replaced by kinetic friction at the lower value f_k = μ_k N. The word 'static' refers to the body's state (at rest), not the force being constant — in fact, static friction is the only friction type that VARIES with applied force.

  • Self-adjusting mechanism: static friction is a reactive force — it responds to the applied force to maintain the no-slip condition at the contact surface. If P = 3 N and f_l = 20 N, the body stays at rest and f_s = 3 N (not 20 N). The friction 'chooses' the exact value needed to balance the applied force. This is fundamentally different from kinetic friction which is fixed at μ_k N regardless of the applied force. NEET trap: applying f = μN to a body at rest when P < f_l gives the wrong answer. The correct friction for a body at rest is f_s = P (unless on the verge of motion).
  • Static friction arises from microscopic adhesive bonding at the contact asperities. When a force is applied, the asperities deform elastically — the surfaces 'stretch' at the atomic scale without sliding. As long as the elastic restoring force (friction) can balance P, the body stays at rest. Near P = f_l, the asperities are about to shear. At P = f_l, all asperities simultaneously reach their shear limit — this is why it takes the maximum force to initiate motion. Static friction increases with P because more asperities deform, storing more elastic energy as the applied force grows.
  • NEET scenario: 'A 5 kg block on a horizontal surface with μ_s = 0.4, μ_k = 0.3 (g = 10 m/s²). What friction acts if P = 10 N?' → f_l = μ_s N = 0.4×50 = 20 N. P = 10 N < f_l = 20 N. Block at rest. f_s = P = 10 N (NOT 20 N). Students commonly answer 20 N by mistake. The 20 N value (μ_s N) only applies when P = f_l (verge of motion). For P < f_l, static friction = P always.
Example (NEET-style)A 4 kg block on a horizontal surface (μ_s = 0.5, g = 10 m/s²). N = 40 N. f_l = μ_s N = 20 N. Scenario A: P = 8 N → f_s = 8 N (body at rest, P < f_l). Scenario B: P = 15 N → f_s = 15 N (still at rest). Scenario C: P = 20 N → f_s = f_l = 20 N (at verge of motion; this is limiting friction). Scenario D: P = 25 N → body starts moving; friction drops to f_k = μ_k N = 0.4×40 = 16 N (kinetic). Static friction VARIES from 0 to 20 N; it only equals 20 N when P = 20 N (exactly). For all P < 20 N, f_s = P.

2) Limiting Friction — Maximum Static Friction at Onset of Motion

Limiting Friction

Limiting friction is the MAXIMUM value of static friction, achieved when the body is at the verge of (impending) motion. Once the applied force P exceeds f_l, the body begins to slide and kinetic friction takes over. Formula: f_l = μ_s × R = μ_s × N (for horizontal surface, N = mg). The coefficient of static friction μ_s = F_l/R (ratio of limiting friction to normal reaction), is dimensionless, has no units, and has dimensions [M⁰L⁰T⁰]. Properties of limiting friction: (1) directly proportional to normal reaction: f_l ∝ N; (2) opposes the direction in which the body would move (always opposite to impending motion direction); (3) independent of apparent contact area — a key experimental result (Coulomb's law of friction); (4) depends on materials and surface condition (μ_s changes with material pairing).

  • Mathematical relation: f_l = μ_s N where N is the normal reaction force. For a body on a horizontal surface: N = mg (for vertical equilibrium). So f_l = μ_s mg. For an inclined surface: N = mg cosθ (component of gravity normal to incline), so f_l = μ_s mg cosθ. NEET problems frequently involve inclined planes where N ≠ mg — students must resolve forces correctly to find N before computing f_l.
  • Direction of limiting friction: opposite to the direction of IMPENDING motion (intended motion). If a block tends to slide to the right, limiting friction acts to the left. If a block on an incline tends to slide down the incline, limiting friction acts up the incline. On an incline: at the limiting condition, mg sinθ (component down the incline) equals μ_s mg cosθ (limiting friction up the incline), giving tan θ = μ_s — this is the angle of repose condition (tested in a separate topic but rooted in limiting friction).
  • Why limiting friction is independent of contact area (Coulomb's law): total friction = (friction per asperity) × (number of asperities). When contact area increases at constant normal force N: pressure per asperity decreases proportionally, reducing friction per asperity; but number of asperities increases proportionally. Net effect: total friction = μ_s N is independent of area. NEET classic trap: 'If the same block is placed on its smaller face vs larger face, does limiting friction change?' → NO, both faces yield f_l = μ_s mg (same N, same μ_s, same f_l). Area is irrelevant.
Example (NEET-style)A block of mass 10 kg on horizontal surface, μ_s = 0.5 (g = 10 m/s²). N = 100 N. (a) Limiting friction = f_l = 0.5 × 100 = 50 N. (b) If block placed on edge (area halved), limiting friction = still 50 N (area-independent). (c) If μ_s doubles to 1.0 (rough surface): f_l = 1.0 × 100 = 100 N (equals the weight). (d) Block tilted 30°: N = mg cos30° = 100×(√3/2) = 86.6 N; f_l = 0.5 × 86.6 = 43.3 N. The key insight: f_l = μ_s N; N must be recalculated for inclined surfaces since N ≠ mg on an incline.

3) Kinetic (Dynamic) Friction — Properties, Formula, and Key Comparisons

Kinetic / Dynamic Friction

Kinetic friction (also called dynamic friction or sliding friction) acts when the body is IN MOTION with relative sliding between surfaces. Formula: f_k = μ_k × N, where μ_k is the coefficient of kinetic friction. Key comparisons: μ_k < μ_s (always); f_k < f_l (always). Why? Once in motion, micro-asperities break and reform continuously during sliding — the average resistance is less than the maximum static resistance needed to initiate motion. Properties of kinetic friction: (1) magnitude is constant at μ_k N regardless of speed; (2) independent of contact area; (3) independent of velocity (over practical speed ranges); (4) depends on the nature of the two surfaces (μ_k is a property of the surface pair); (5) opposes the direction of relative motion (acts opposite to velocity of the sliding surface).

  • Velocity independence: f_k = μ_k N is the same whether the body slides at 1 m/s or 100 m/s (Coulomb's kinetic friction law). This is a major NEET test point — 'kinetic friction depends on speed' is a FALSE statement. Physically: at typical mechanics speeds, the bonding/breaking rate at asperities scales with speed but the net friction force averages out to a constant μ_k N. At extreme speeds (brake fade in cars) μ_k decreases — but NEET always assumes Coulomb kinetic friction (velocity-independent).
  • Two subtypes of kinetic friction: (a) SLIDING friction — when one body slides over the surface of another (e.g., a block dragged across a table). (b) ROLLING friction (see next card) — when the body rolls over a surface. For identical surfaces, rolling friction is much less than sliding friction. This is why wheels are used to transport loads — rolling replaces sliding, dramatically reducing friction. Ball bearings in machinery convert sliding friction at shafts into rolling friction, reducing energy loss.
  • Net force and acceleration when kinetic friction acts: If a force P is applied to a sliding body, net force = P − f_k = P − μ_k N. Acceleration a = (P − μ_k N) / m. NEET calculation: 10 kg block, μ_k = 0.3, P = 40 N, g = 10 m/s². N = 100 N. f_k = 0.3 × 100 = 30 N. Net force = 40 − 30 = 10 N. a = 10/10 = 1 m/s². If P = 30 N (= f_k): net force = 0; body moves at constant velocity (a = 0). If P < 30 N but body already in motion: a is negative (deceleration). f_k = 30 N regardless of whether P = 20 N or 50 N.
Example (NEET-style)A block of mass 8 kg is pushed across a horizontal floor with μ_k = 0.25 (g = 10 m/s²). (a) N = 80 N. f_k = 0.25 × 80 = 20 N. (b) Applied force P = 30 N: net force = 30 − 20 = 10 N; a = 10/8 = 1.25 m/s². (c) If speed doubles (P maintained at 30 N): f_k is still 20 N (velocity-independent); a = 1.25 m/s² unchanged. (d) If block area is doubled (same mass, same P): f_k is still 20 N (area-independent). Kinetic friction is fixed at μ_k N = 20 N regardless of speed or area — only μ_k and N matter.

4) Rolling Friction — Formula, Mechanism, and Why It Is Least

Rolling Friction

Rolling friction acts when a body (wheel, cylinder, sphere) rolls over a surface. Formula: F_rolling = μ_r × R / r, where R = normal reaction, r = radius of the rolling body, μ_r = coefficient of rolling friction. Note: μ_r has dimensions of LENGTH ([L] = metres), not dimensionless like μ_s and μ_k. Rolling friction is proportional to normal reaction R (directly proportional) and inversely proportional to radius r. Physical mechanism: rolling friction arises from deformation of the rolling body or surface at the contact region, not from sliding. The contact zone for a rolling body is very small (theoretically a point for rigid spheres), so the interlocking of asperities that creates large sliding friction is absent. The velocity of the contact point with respect to the surface is zero (no sliding at contact), so kinetic-friction type resistance doesn't apply. Rolling friction is much smaller than sliding friction for the same surfaces.

  • Why is rolling friction much smaller than sliding friction? In sliding, all contact asperities undergo shear (breaking of adhesive welds) simultaneously, creating large resistance. In rolling, at any instant only a tiny contact area exists (theoretically a point for rigid cylinders), and no sliding occurs there. The resistance comes from: (a) micro-deformation of the surface material at the contact point (energy stored and released per rotation); (b) slight hysteresis in the deformation-recovery cycle; (c) micro-vibrations. All of these are small compared to the massive shear of asperities in sliding. Practical result: it takes ~100 times less force to roll a heavy load than to slide it.
  • Rolling friction formula: F_rolling = μ_r R/r. Inversely proportional to radius → larger wheels roll more easily (less rolling friction) for the same normal force. This is why bicycle wheels and cart wheels are large — they minimise rolling friction per unit load. μ_r depends on material properties (hardness, elasticity) of the surfaces. Steel wheels on steel rails: μ_r ≈ 0.0001–0.001 m; rubber tyres on concrete: μ_r ≈ 0.001–0.01 m. These are very small numbers confirming rolling friction is tiny.
  • Practical applications of rolling friction concept: (1) Heavy loads are transported on carts with wheels — rolling replaces sliding, reducing friction dramatically. (2) Ball bearings in machines convert sliding friction (at axles) into rolling friction, improving efficiency. (3) Wheels of vehicles use rolling contact with the road — energy loss due to rolling friction is much less than equivalent sliding. NEET question: 'Why are ball bearings used in machines?' → They convert sliding friction into rolling friction, reducing friction and energy loss significantly. 'Why do heavy loads roll more easily than slide?' → Rolling friction < sliding (kinetic) friction.
Example (NEET-style)A solid cylinder (mass 5 kg, radius r = 0.1 m) rolls on a floor (g = 10 m/s²). μ_r = 0.002 m (SI units). R = mg = 50 N. F_rolling = μ_r R/r = 0.002×50/0.1 = 1.0 N. Compare: if the cylinder SLIDES (μ_k = 0.3): f_k = μ_k N = 0.3×50 = 15 N. Rolling friction (1.0 N) is 15 times less than sliding friction (15 N). This illustrates why rolling is used in transport. A larger radius cylinder (r = 0.2 m): F_rolling = 0.002×50/0.2 = 0.5 N — half the rolling friction with double the radius, confirming the inverse relationship with r.

US Curriculum Gaps — Types of Friction

Topics in this section are tested in NEET but organised differently in standard US physics courses.

Four-Type Classification vs Two-Type in AP Physics 1

NEET formally classifies friction into four named types: static, limiting, kinetic (sliding), and rolling. AP Physics 1 uses a two-type model: static friction and kinetic friction, with maximum static friction as a property of static friction (not a separately named type). AP Physics 1 mentions rolling friction briefly but does not derive F_rolling = μ_r R/r or emphasise μ_r having dimensions of length. US students may be unfamiliar with 'limiting friction' as a distinct named category or with the rolling friction formula involving radius. NEET questions specifically ask students to name the four types and identify conditions for each.

  • NEET: four named types — static (f_s = P), limiting (f_l = μ_s N), kinetic (f_k = μ_k N), rolling (F_r = μ_r R/r)
  • AP Physics 1: static and kinetic friction; maximum static = μ_s N at boundary; rolling friction formula not formally tested
  • μ_r has dimensions of length in NEET formula; this is not emphasised in AP Physics 1

Sliding vs Rolling Friction Distinction in University Physics (Physics 101)

University Physics (Halliday & Resnick, Serway) covers rolling friction in the context of rotational dynamics and energy, not as a standalone formula in the forces chapter. The formula F_rolling = μ_r R/r is specific to the NCERT/Indian physics curriculum treatment. US university courses (Physics 101/102) typically address rolling friction as part of torque and rotational equilibrium. NEET tests this formula directly in the Friction chapter context — students must apply it to find rolling friction force given μ_r, R, and r, without the rotational dynamics framework that US courses use.

  • NEET: F_rolling = μ_r R/r tested directly in Friction chapter; μ_r in metres is required
  • University Physics (Halliday & Resnick): rolling friction covered in rotational dynamics chapters with different framing
  • NEET specifically tests: rolling friction is LESS than sliding friction (key comparison); wheeled transport reduces friction

NEET-Style Practice Questions — Types of Friction

4 Questions
1A block of mass 5 kg is placed on a horizontal surface with μ_s = 0.6 and μ_k = 0.4. A horizontal force of 20 N is applied. What is the friction force acting on the block? (g = 10 m/s²)Static vs Kinetic
30 N (limiting)
20 N (static)
20 N (kinetic)
0 N
N = mg = 5×10 = 50 N. Limiting friction f_l = μ_s N = 0.6×50 = 30 N. Applied force P = 20 N. Since P = 20 N < f_l = 30 N, the block does NOT move. Static friction acts and is self-adjusting: f_s = P = 20 N. The friction is 20 N (static), not 30 N (that would be limiting friction at verge of motion), and not 20 N kinetic (block is at rest, not sliding). Key NEET distinction: when block is at rest and P < f_l, apply f = P (not f = μN).
2Which of the following correctly describes the relationship between coefficients of friction?Coefficient Comparison
μ_s < μ_k < μ_rolling
μ_k < μ_s and μ_rolling < μ_k
μ_s = μ_k always
μ_rolling > μ_k always
The correct ordering is μ_rolling < μ_k < μ_s. Rolling friction coefficient is smallest (rolling friction is much less than sliding), kinetic coefficient is less than static (μ_k < μ_s — more force needed to start than maintain motion). Option B correctly states both: μ_k < μ_s (kinetic less than static) AND μ_rolling < μ_k (rolling less than kinetic). Option A reverses the correct order. Option C is false (μ_k < μ_s always). Important: μ_r (rolling) has dimensions of length [m], while μ_k and μ_s are dimensionless.
3The force of kinetic friction between two surfaces does NOT depend on:Properties of Kinetic Friction
Normal reaction between the surfaces
Nature of surfaces in contact
Velocity of the sliding body
Coefficient of kinetic friction
Kinetic friction f_k = μ_k N. It depends on: (1) N (normal reaction) — directly proportional ✓; (2) μ_k (nature of surfaces) — μ_k depends on material pairing ✓. It does NOT depend on: (3) velocity — Coulomb's kinetic friction law: f_k is velocity-independent; (4) contact area — f_k is area-independent. Option C (velocity) is the correct answer. NEET frequently tests this as 'kinetic friction does not depend upon the velocity of the body' — a direct quote from NCERT.
4Rolling friction is directly proportional to normal reaction R and inversely proportional to radius r. If the radius of a rolling cylinder doubles (keeping same load), rolling friction will:Rolling Friction
Double
Remain same
Become half
Become one-fourth
F_rolling = μ_r R/r. If r doubles (r → 2r) and R remains unchanged: F_rolling_new = μ_r R/(2r) = (1/2) × (μ_r R/r) = (1/2) × F_rolling_original. Rolling friction becomes HALF. This inverse relationship with radius explains why larger wheels roll more easily. Example: if r = 0.1 m gives F_rolling = 2 N, then r = 0.2 m gives F_rolling = 1 N (half). Option C (become half) is correct.

Practice Problems — Types of Friction

Click "Reveal Answer" after attempting
1A 10 kg block rests on a horizontal floor. μ_s = 0.5, μ_k = 0.4, g = 10 m/s². (a) What is the limiting friction? (b) What horizontal force P makes the block just start moving? (c) Once P = 60 N is applied (block moving), find the acceleration.
(a) 50 N; (b) 50 N; (c) 2 m/s²
(a) 40 N; (b) 50 N; (c) 2 m/s²
(a) 50 N; (b) 40 N; (c) 2 m/s²
(a) 50 N; (b) 50 N; (c) 1 m/s²
👁 Reveal Answer
(a) N = mg = 100 N. f_l = μ_s N = 0.5 × 100 = 50 N (limiting friction). (b) To just start motion, P must equal limiting friction = 50 N. (c) Once block moves with P = 60 N: f_k = μ_k N = 0.4 × 100 = 40 N. Net force = 60 − 40 = 20 N. Acceleration a = 20/10 = 2 m/s². Answer (a): 50 N; (b): 50 N; (c): 2 m/s².
2A cylinder of mass 4 kg and radius 0.05 m rolls on a horizontal surface. μ_r = 0.003 m (rolling friction coefficient). g = 10 m/s². If the same cylinder were to slide on this surface (μ_k = 0.2), compare rolling friction to sliding friction. Find both forces.
F_rolling = 2.4 N, F_sliding = 8 N
F_rolling = 0.24 N, F_sliding = 8 N
F_rolling = 2.4 N, F_sliding = 4 N
F_rolling = 0.12 N, F_sliding = 8 N
👁 Reveal Answer
R = mg = 4×10 = 40 N. Rolling: F_rolling = μ_r R/r = 0.003×40/0.05 = 0.12/0.05 = 2.4 N. Wait — 0.003×40 = 0.12; 0.12/0.05 = 2.4 N. Sliding: f_k = μ_k N = 0.2×40 = 8 N. Rolling friction (2.4 N) is much less than sliding friction (8 N) — confirming rolling is more efficient. Ratio: 8/2.4 ≈ 3.3×. This is why wheels are used in transport.
3A block is on a rough horizontal surface. An external force is gradually increased from zero. At F = 12 N the block just starts moving, and kinetic friction is 9 N. Find: (a) coefficient of static friction; (b) coefficient of kinetic friction; (c) how much force maintains constant velocity motion. (m = 3 kg, g = 10 m/s²)
(a) 0.4; (b) 0.3; (c) 9 N
(a) 0.3; (b) 0.4; (c) 9 N
(a) 0.4; (b) 0.3; (c) 12 N
(a) 0.5; (b) 0.3; (c) 9 N
👁 Reveal Answer
N = mg = 3×10 = 30 N. (a) Block just starts at F = 12 N → limiting friction = 12 N. μ_s = f_l/N = 12/30 = 0.4. (b) Kinetic friction = 9 N. μ_k = f_k/N = 9/30 = 0.3. Confirm: μ_k = 0.3 < μ_s = 0.4 ✓. (c) For constant velocity (a = 0): applied force must equal kinetic friction = 9 N (net force = 0). Answers: (a) 0.4; (b) 0.3; (c) 9 N.
4A 6 kg block rests on a rough surface (μ_s = 0.45, μ_k = 0.35, g = 10 m/s²). A student applies 25 N horizontally. (a) Does the block move? (b) What is the friction force? (c) If the block is already moving at 4 m/s and the 25 N force is suddenly removed, does friction change in magnitude?
(a) No; (b) 25 N static; (c) Yes, friction increases
(a) No; (b) 27 N limiting; (c) No, friction remains 21 N
(a) Yes; (b) 21 N kinetic; (c) No, friction remains 21 N until stop
(a) No; (b) 25 N static; (c) No, friction remains 21 N until stop
👁 Reveal Answer
N = 6×10 = 60 N. f_l = μ_s N = 0.45×60 = 27 N. P = 25 N < f_l = 27 N. (a) Block does NOT move. (b) Friction = f_s = P = 25 N (static, self-adjusting). (c) If block is already moving at 4 m/s and P removed: f_k = μ_k N = 0.35×60 = 21 N. Friction magnitude does NOT change when P is removed (as long as block moves, kinetic friction = 21 N until the block decelerates to rest). Answer: (a) No; (b) 25 N static; (c) No, friction remains 21 N until stop.

Physics — Friction Revision Checklist

Check off chapters as you revise

Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

FAQ — Types of Friction

Notes · Downloads · Revision · Important Questions
What is the difference between static friction and limiting friction?
Static friction is the friction force that acts on a body at rest when a force P is applied. It is self-adjusting: f_s = P, varying from 0 to the maximum value f_l. Limiting friction is the MAXIMUM value of static friction — the value at which the body is about to start moving (impending motion). f_l = μ_s N. Think of it this way: static friction is the CURRENT value of friction for any applied force P < f_l; limiting friction is the MAXIMUM value of static friction at the threshold. For P < f_l: f_s = P (static, variable). At P = f_l: f_s = f_l = μ_s N (limiting, maximum). For P > f_l: body moves, friction drops to f_k < f_l.
Why is kinetic friction less than limiting (maximum static) friction?
When the body is at rest (static regime), microscopic adhesive welds form fully at the contact asperities — the surfaces have time to form stable bonds. Initiating motion requires breaking ALL these welds simultaneously, demanding maximum force f_l = μ_s N. Once motion begins, surfaces slide relative to each other — asperities no longer have time to form complete bonds before being sheared apart. The average resistance (kinetic friction f_k) is less than the maximum static resistance (f_l). Result: f_k < f_l, so μ_k < μ_s. Practically: it takes more force to START sliding a heavy box than to KEEP it sliding — the box 'comes free' once motion starts.
Why is rolling friction much less than sliding friction?
In sliding friction, all contact asperities undergo shear (molecular bonds break) simultaneously, creating large resistance. In rolling, at any instant the contact is theoretically a point (for a rigid cylinder on a rigid surface) — no sliding occurs at the contact point (velocity of contact point = 0 relative to surface in pure rolling). Rolling friction arises from surface deformation/recovery cycles (elastic hysteresis), which dissipates much less energy than continuous asperity shearing in sliding. Practically: μ_r (rolling) << μ_k (kinetic). This is why wheels and ball bearings are used — they replace sliding with rolling, reducing friction by factors of 10–100.
What are the units and dimensions of the coefficient of rolling friction?
Unlike μ_s and μ_k (which are dimensionless ratios), μ_r has dimensions of LENGTH and is measured in metres. This follows from the formula F_rolling = μ_r R/r: F and R are forces, r is length, so μ_r = F_rolling × r / R = (force × length)/force = length → [L] = metres. Typical values: steel wheel on steel rail: μ_r ≈ 0.0005–0.001 m; rubber tyre on concrete: μ_r ≈ 0.002–0.01 m. These tiny values confirm rolling friction is small. NEET may test: 'μ_r has units of...' → answer: metre (SI unit of length).
Does increasing the contact area increase friction?
No. Both limiting friction and kinetic friction are independent of the apparent contact area (Coulomb's law of friction). f_l = μ_s N depends only on μ_s and N — not on area. f_k = μ_k N depends only on μ_k and N. Physical explanation: larger contact area → more contact asperities → more friction per unit area × more area → these effects cancel exactly → total friction = μN regardless of area. Classic NEET trap: 'A block placed on its larger face vs. smaller face — is friction different?' Answer: NO, friction is the same (same μ, same N = mg, same f_l = μ_s mg). Contact area is irrelevant.
Does the velocity of a sliding body affect kinetic friction?
No — kinetic friction is velocity-independent (Coulomb's kinetic friction law). f_k = μ_k N is the same at 1 m/s and at 100 m/s. This is directly stated in NCERT: 'kinetic friction does not depend upon the velocity of the body.' This is one of the most tested properties in NEET. Note: in real systems (not NEET), at very high velocities, friction can change due to thermal effects (brake fade), but for all NEET problems, assume f_k is velocity-independent.
What does 'kinetic friction is of two types' mean?
Kinetic friction has two subtypes based on the nature of relative motion: (1) Sliding friction: one body slides over the surface of another (e.g., a block dragged across a table). Formula: f_k = μ_k N. (2) Rolling friction: one body rolls over the surface of another (e.g., a wheel on a road). Formula: F_rolling = μ_r R/r. Both are types of kinetic friction because they act when there IS relative motion between surfaces. Rolling friction is a subset of kinetic friction, but it is much smaller because the contact mechanism differs fundamentally (no sliding at the contact point in pure rolling).
Why are ball bearings used in machines, and what type of friction do they reduce?
Ball bearings convert SLIDING friction into ROLLING friction at rotating axles and joints. Without bearings, metal shaft rotates inside a metal housing — continuous sliding between shaft and housing generates kinetic (sliding) friction: large heat generation, energy loss, and wear. Ball bearings replace this sliding with rolling — small spheres roll between the shaft and housing rings. Rolling friction is much less than sliding friction (F_rolling << f_k for same surfaces and normal force). Result: significantly less energy loss per rotation, less heat, less wear. NEET question: 'Ball bearings are used to reduce friction by converting _____ friction to _____ friction.' Answer: sliding (kinetic) friction to rolling friction.
For NRI / OCI / U.S.-Based Families

NEET NRI Counseling & Admission eBook Download

A practical guide covering sponsor rules, document checklist, verification traps, NRI quota reality, and step-by-step counselling flow. Designed to prevent last-minute rejections and wrong choice filling.

Sponsor + Proof ClarityDocuments ChecklistState-wise Traps
↓ Download eBook (PDF)→ See What's Inside
Tip: Keep this eBook open during verification + choice filling week for quick cross-checking.
NEET Prep (India + NRI-USA)

Schedule Trial Session For NEET Prep

Get a short diagnostic + study roadmap: syllabus gaps (NCERT vs U.S. curriculum), weak chapters, and the exact weekly plan needed to improve accuracy under time.

Gap MappingWeekly PlanAccuracy Fix
→ Book Trial Session→ WhatsApp Us
Best for: Students in Grade 10–12 (U.S. / India) who want a clear NEET timeline and daily practice structure.

Static Friction

Limiting Friction

Kinetic / Dynamic Friction

Rolling Friction

Kinetic friction depends upon the normal reaction

Types of kinetic friction

Advantages of friction

Two body sticks together due to friction

Brake works on the basis of friction

Kinetic or dynamic friction

Subtopics

Static Friction

Limiting Friction

Kinetic / Dynamic Friction

Rolling Friction

Kinetic friction depends upon the normal reaction

Types of kinetic friction

Advantages of friction

Two body sticks together due to friction

Brake works on the basis of friction

Kinetic or dynamic friction

Previous
Types of Friction > Kinetic or dynamic friction > Kinetic or dynamic friction
Next
Static Friction

Loading tests...

NEET > Physics > Laws of Motion Chapters

Review your status and progress for each chapter in this unit. Use the slider to set progress or click "Mark as Done" to complete.

ChapterStatusProgress

Newton's Laws of Motion

Weightage: 02.2K
0%

Friction

Weightage: 02.2K
0%

Comments

Leave a comment

0/2000Comments are moderated

You can comment without logging in. We'll ask for your name and email before submitting.

Comments (0)

No comments yet. Be the first to comment!