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Speed and Velocity

NEET > Physics > Kinematics > Motion In One Dimension > Speed and Velocity

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NEET Physics — Motion In One Dimension

Speed and Velocity – Complete Notes, Revision, Important Questions & Downloads

Speed and Velocity are the first kinematic rates — how fast position and distance change with time. Two subtopics are covered: Speed (rate of distance with time, scalar, always ≥ 0) and Velocity (rate of displacement with time, vector, can be positive, negative, or zero). The critical inequality is: Average Speed ≥ |Average Velocity|, with equality only for straight-line motion in one direction. Instantaneous velocity is always tangential to the path; its magnitude equals instantaneous speed. NEET tests this topic in three patterns: (1) compute average speed and average velocity from a described journey; (2) identify which statement about speed/velocity is correct; (3) calculate instantaneous velocity from a given x(t) expression by differentiation.

⬇ Download Notes PDFView Important Questions →
7 SubtopicsScalar vs Vector RateAvg Speed ≥ |Avg Velocity|
Expected QuestionsQ
1–2
Speed and velocity rank among the top 3 most-tested topics in NEET Chapter 2. Questions combine path description with time to compute both average quantities or ask for instantaneous velocity from x(t) = at² + bt + c.
Time Required⏱
1.5 hours
45 minutes for definitions and 6–8 average-speed/velocity numericals; 45 minutes for instantaneous velocity via differentiation and 4–5 mixed problems comparing average and instantaneous quantities.
Difficulty⚡
Easy–Medium
Definitions are straightforward; difficulty lies in multi-segment journeys where a particle reverses direction (displacement ≠ distance) and in differentiation for instantaneous velocity. The average-speed trap (using displacement instead of distance, or vice versa) is the most frequent cause of errors.
NRI USA Curriculum GapUS
Low–Medium
US AP Physics covers speed and velocity; however, NEET's emphasis on instantaneous velocity from x(t) by differentiation (not taught until AP Calculus/BC contexts) and the formal inequality proof for average speed vs |average velocity| may require extra practice.
7Subtopics
8+Practice Questions
4Free Downloads
1.5 hrsPrep Time
⬇ Get Free Downloads

NEET Weightage — Speed and Velocity

Motion In One Dimension (Chapter 2)
NEET YearQuestions from this TopicBarMarks
20241
 
1 Q
4
20231
 
1 Q
4
20221
 
1 Q
4
20211
 
1 Q
4
20201
 
1 Q
4
20191
 
1 Q
4
6-Year Total (2019–2024)3–6 12–24
Most common NEET framing: 'A particle travels half the total distance at speed v₁ and the remaining half at speed v₂. Find average speed.' Answer: harmonic mean 2v₁v₂/(v₁+v₂) — NOT arithmetic mean.
Instantaneous velocity from x(t): differentiate position to get v(t) = dx/dt. If x = 3t² − 2t + 5, then v = 6t − 2. Evaluate at the required t.

Key property: instantaneous velocity is always tangential to the path of the particle — this is why a particle moving in a circle has speed tangential to the circle at every point.
📊
~1.0
Avg Questions / Year
🎯
12–24
Total Marks (6 yrs)
📈
Direct
Pattern
⚠️
Easy–Medium
Difficulty

Exam Strategy — Speed and Velocity in NEET

1

Always compute distance (for speed) and displacement (for velocity) separately Average speed = total distance / total time. Average velocity = total displacement / total time. If the particle reverses direction, distance and displacement diverge — and so do average speed and |average velocity|. The average-speed trap: students use displacement in the numerator of average speed, getting |average velocity| instead of average speed. Draw a number line for every 1D problem and mark the particle's path before computing.

2

Harmonic mean formula for equal-distance, different-speed segments If a particle travels equal distances at speed v₁ and speed v₂: average speed = 2v₁v₂/(v₁+v₂). This is the harmonic mean, not the arithmetic mean (v₁+v₂)/2. The trap: using arithmetic mean for equal-distance segments. Note: if equal time at different speeds, then average speed = arithmetic mean (v₁+v₂)/2. The distinction is crucial — NEET specifically tests both forms.

3

Instantaneous velocity via differentiation v = dx/dt Given x(t) = at² + bt + c: differentiate to get v(t) = 2at + b. Evaluate at t = t₁ for instantaneous velocity at that moment. If x given in metres and t in seconds, then v is in m/s. If asked for speed (not velocity), take |v(t)|. NEET may also give v(t) and ask for instantaneous acceleration: a = dv/dt.

4

Know the scalar vs vector properties and use them to eliminate options quickly Speed is scalar (no direction, always ≥ 0). Velocity is vector (has direction, can be negative). Instantaneous speed = |instantaneous velocity| always. Average speed and |average velocity| are equal only when the motion is in one direction (no reversal). Any NEET option saying 'average speed can be less than |average velocity|' is always false and can be eliminated immediately.

Download Study Notes — Speed and Velocity

PDF · Cheat Sheet · MCQ Set · PYQ
📘
Speed and Velocity — Full Notes
Complete notes covering speed definition (uniform, variable, average, instantaneous), velocity definition (average, instantaneous), scalar vs vector, key inequality, tangential velocity direction, harmonic and arithmetic mean formulas for average speed, and differentiation for instantaneous velocity.
7 subtopics8 worked examplesHarmonic mean derivation
Download PDF
📗
Speed and Velocity — Formula Sheet
One-page reference: all speed/velocity formulas, harmonic mean, instantaneous velocity (v = dx/dt), key inequality Avg Speed ≥ |Avg Velocity|, special cases (equal distance, equal time), and 2 rapid examples.
1 pageAll formulas
Download PDF
📙
Speed and Velocity — MCQ Practice
12 NEET-style MCQs: average speed/velocity from described journeys, equal-distance harmonic mean, x(t) differentiation for instantaneous velocity, correct statement identification, and circular path average speed vs velocity.
12 MCQsDetailed solutions
Download PDF
📕
Speed and Velocity — NEET-Style PYQ Practice
NEET-style practice questions on speed and velocity with full answer key and step-by-step solutions for each question.
NEET-styleAnswer key included
Download PDF

Subtopics in Speed and Velocity

2-Column Table
Column AColumn B
Unit : metre (S.I.)↗
Comparison between distance and displacement↗
Types of speed↗
Types of velocity↗
Comparison between instantaneous speed and instantaneous velocity↗
Comparison between average speed and average velocity↗
The magnitude of displacement↗

Rapid Revision — Speed and Velocity

Concept → Trap → Example

1) Speed

Scalar Rate — Distance / Time

Speed = rate of distance covered with time. Scalar, always ≥ 0. Average speed = total distance / total time. Instantaneous speed = |dx/dt| = |v|. Uniform speed: equal distances in equal time intervals. Variable speed: distance per unit time changes.

  • Uniform speed: 'When a particle covers equal distances in equal intervals of time, (no matter how small the intervals are) then it is said to be moving with uniform speed.' — verbatim NCERT.
  • Average speed for equal distance at speeds v₁ and v₂: harmonic mean = 2v₁v₂/(v₁+v₂). Average speed for equal time at speeds v₁ and v₂: arithmetic mean = (v₁+v₂)/2.
  • Speed cannot be negative. If a particle returns to start, average velocity = 0 but average speed = total distance / total time > 0.
Example (NEET-style)Particle covers 60 km at 30 km/h then 60 km at 60 km/h. Time₁ = 60/30 = 2 h; Time₂ = 60/60 = 1 h. Average speed = 120/3 = 40 km/h. (Harmonic mean: 2×30×60/(30+60) = 3600/90 = 40 km/h ✓).

2) Velocity

Vector Rate — Displacement / Time

Velocity = rate of change of position (rate of displacement with time). Vector, can be positive, negative, or zero. Average velocity = total displacement / total time. Instantaneous velocity = dx/dt (derivative of position). Instantaneous velocity is always tangential to the path.

  • A particle may have constant instantaneous speed but variable instantaneous velocity — e.g., uniform circular motion (speed constant, direction always changing means velocity continually changes).
  • Instantaneous speed = magnitude of instantaneous velocity: |v_inst| = |dx/dt| — this equality always holds, for any path.
  • Average speed ≥ |average velocity|. Equality holds only when displacement equals distance (straight-line, no reversal). For a closed path (return to start): average velocity = 0, average speed > 0.
Example (NEET-style)x(t) = 3t² − 6t + 2 (in metres, t in seconds). Instantaneous velocity: v = dx/dt = 6t − 6 m/s. At t = 2 s: v = 6(2) − 6 = 6 m/s. At t = 1 s: v = 0 (particle momentarily at rest). At t = 0.5 s: v = 6(0.5) − 6 = −3 m/s (moving in negative direction).

US Curriculum Gaps — Speed and Velocity for NEET

US AP Physics 1 students may find these specific gaps when preparing for NEET speed and velocity questions.

Harmonic mean formula for equal-distance segments is not explicitly taught in AP Physics 1

US AP Physics 1 computes average speed as total distance / total time directly, without needing to separately derive or memorise the harmonic mean formula. NEET frequently presents the equal-distance scenario in the form 'a car travels from A to B at v₁ and returns at v₂, find average speed for the round trip' — a standard NEET MCQ that requires 2v₁v₂/(v₁+v₂) directly or an arithmetic risk of using (v₁+v₂)/2 incorrectly.

  • AP Physics: average speed = total distance / total time (always). This can be computed directly from values given. However, memorising the harmonic mean formula 2v₁v₂/(v₁+v₂) saves vital seconds in NEET time constraints.
  • The arithmetic mean (v₁+v₂)/2 is only valid for equal-time (not equal-distance) segments. NEET specifically traps students by presenting equal-distance problems where arithmetic mean is the wrong answer.
  • Practise: round-trip problem (go at v₁, return at v₂) → answer is always the harmonic mean, regardless of v₁ and v₂ values.

Instantaneous velocity by differentiation of x(t) is not drilled in AP Physics 1 (non-calculus course)

AP Physics 1 is explicitly a non-calculus course. Instantaneous velocity is introduced conceptually (limit of Δx/Δt as Δt→0) but students do not compute it by differentiating x(t) algebraically. NEET problems routinely provide x(t) = at² + bt + c and ask for v at a specific time — requiring v = dx/dt = 2at + b. This is a standard calculus step that AP Physics 1 students may not have practised in a physics problem context.

  • AP Physics 1: instantaneous velocity is read from the slope of a position-time graph only (graphical method).
  • NEET: instantaneous velocity often requires differentiating a polynomial position function — a skill from AP Calculus AB/BC or IB Math.
  • Practise: x = 5t³ − 2t + 1 → v = dx/dt = 15t² − 2. At t = 1 s: v = 15(1) − 2 = 13 m/s. Comfort with this 2-step process (differentiate, then substitute) is essential.

NEET-Style Practice Questions — Speed and Velocity

4 NEET-style practice questions
1A car travels from city A to city B (distance d) at speed 30 km/h and returns from B to A at speed 60 km/h. The average speed for the entire journey is:NEET-style practice
45 km/h
40 km/h
50 km/h
35 km/h
For a round trip with equal distances at two speeds: Average speed = 2v₁v₂/(v₁+v₂) = 2×30×60/(30+60) = 3600/90 = 40 km/h. Option (a) 45 km/h is the arithmetic mean (30+60)/2 = 45 km/h — correct only for equal-time segments, not equal-distance. The round trip covers equal distances (d going, d returning), so harmonic mean applies. Note: average speed 40 km/h < arithmetic mean 45 km/h — harmonic mean is always ≤ arithmetic mean for positive values.
2A particle's position is given by x(t) = 4t² − 8t + 3 (in metres, t in seconds). The instantaneous velocity at t = 3 s is:NEET-style practice
16 m/s
8 m/s
32 m/s
0 m/s
v(t) = dx/dt = d(4t² − 8t + 3)/dt = 8t − 8. At t = 3 s: v = 8(3) − 8 = 24 − 8 = 16 m/s. Option (b) 8 m/s is the velocity at t = 2 s. Option (c) 32 m/s is 8×(3+1) — incorrect substitution. Option (d) 0 m/s is the velocity at t = 1 s (when particle momentarily stops). Note: x(1) = 4−8+3 = −1 m; v(1) = 8−8 = 0 — the particle momentarily rests at t = 1 s before accelerating back in the positive direction.
3A particle executes uniform circular motion with constant speed 5 m/s at radius 2 m. After completing half a revolution (half-circle), the average speed and magnitude of average velocity are:NEET-style practice
Average speed = 5 m/s, |Average velocity| = 5 m/s
Average speed = 5 m/s, |Average velocity| = 10/π m/s
Average speed = 10/π m/s, |Average velocity| = 5 m/s
Average speed = 0, |Average velocity| = 0
Speed is constant at 5 m/s — average speed = 5 m/s (constant speed means instantaneous speed = average speed over any interval). For half a revolution: distance = πr = 2π m; displacement = 2r = 4 m (diameter). Time for half-revolution = πr/v = 2π/5 s. |Average velocity| = |displacement|/time = 4/(2π/5) = 4×5/(2π) = 20/(2π) = 10/π m/s ≈ 3.18 m/s. Note: average speed (5 m/s) > |average velocity| (10/π ≈ 3.18 m/s) as expected.
4Which of the following statements about speed and velocity is correct?NEET-style practice
Average speed can be less than |average velocity| in some cases
Instantaneous speed can be greater than instantaneous velocity magnitude
A particle can have constant instantaneous speed but variable instantaneous velocity
For uniform circular motion, both average speed and average velocity are zero after one full revolution
Option (c): A particle in uniform circular motion has constant instantaneous speed (|v| = constant) but variable instantaneous velocity (because direction changes at every point on the circle). This is the standard NEET example. Option (a) is false — average speed ≥ |average velocity| always. Option (b) is false — instantaneous speed = |instantaneous velocity| always (by definition: speed is the magnitude of the velocity vector). Option (d) is partially correct (average velocity = 0 after one revolution) but average speed = 2πr/T ≠ 0 — average speed is never zero for a moving particle.

Practice Problems — Speed and Velocity

Click "Reveal Answer" after attempting
1A particle travels 100 m north in 5 s, then 60 m south in 3 s. Find: (a) average speed, (b) magnitude of average velocity.
(a) 20 m/s; (b) 5 m/s
(a) 20 m/s; (b) 6.25 m/s (south)
(a) 5 m/s; (b) 5 m/s
(a) 20 m/s; (b) 20 m/s
👁 Reveal Answer
Option (a): Total distance = 100 + 60 = 160 m; total time = 5 + 3 = 8 s. Average speed = 160/8 = 20 m/s. Displacement: 100 north − 60 south = 40 m north. |Average velocity| = 40/8 = 5 m/s. Average speed (20 m/s) >> |average velocity| (5 m/s) because the particle reversed direction.
2Two cars travel from A to B. Car 1 travels at uniform speed 80 km/h. Car 2 travels the first half time at 60 km/h and the second half time at 100 km/h. Which car has a higher average speed?
Car 1 — because uniform speed means no time is wasted
Car 2 — average speed = (60+100)/2 = 80 km/h, same as Car 1
Car 2 — average speed = (60+100)/2 = 80 km/h; same as Car 1, not higher
They have the same average speed: 80 km/h
👁 Reveal Answer
Option (d): For equal-time segments: average speed = arithmetic mean = (60+100)/2 = 80 km/h = Car 1 speed. They have the same average speed. The trap: students would apply the harmonic mean formula, but that formula is only for equal-distance segments. For equal time, arithmetic mean applies.
3A particle moves according to the equation x = 2t³ − 9t² + 12t + 5 (m). At what time is its instantaneous velocity zero?
t = 1 s only
t = 2 s only
t = 1 s and t = 2 s
t = 0 s
👁 Reveal Answer
Option (c): v = dx/dt = 6t² − 18t + 12. Set v = 0: 6t² − 18t + 12 = 0 → t² − 3t + 2 = 0 → (t−1)(t−2) = 0 → t = 1 s and t = 2 s. At both these moments the particle momentarily stops before reversing or accelerating again.
4The position of a particle is given by x = 5 m at t = 0 and x = 11 m at t = 3 s. The average velocity and average speed are both 2 m/s. What can you conclude about the particle's path?
The particle moved in a curved path
The particle reversed direction during the 3 s
The particle moved in a straight line in one direction without reversal
The particle returned to its starting position
👁 Reveal Answer
Option (c): If average speed = |average velocity| = 2 m/s, then distance = |displacement| = 6 m. Distance equals |displacement| only when the particle moves in a straight line in one direction without reversal. If it reversed or curved, distance > |displacement|. The particle moved 6 m in one direction from x = 5 m to x = 11 m.

Physics — Speed and Velocity Revision Checklist

Check off chapters as you revise

Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

Frequently Asked Questions — Speed and Velocity

Notes · Downloads · Revision · Important Questions
What is the difference between speed and velocity?
Speed is a scalar — it measures how fast the object is moving without regard to direction. Velocity is a vector — it specifies both the rate of motion and its direction. In 1D: velocity = dx/dt (can be positive or negative); speed = |dx/dt| (always ≥ 0). In everyday language they are used interchangeably, but in physics, they are fundamentally different. A car going around a bend at 60 km/h has constant speed but changing velocity (direction changes with the bend).
Why is average speed = 2v₁v₂/(v₁+v₂) for an equal-distance journey?
Let d = distance for each leg. Time for first half: t₁ = d/v₁. Time for second half: t₂ = d/v₂. Average speed = total distance / total time = 2d/(d/v₁ + d/v₂) = 2d / [d(1/v₁ + 1/v₂)] = 2/(1/v₁ + 1/v₂) = 2v₁v₂/(v₁+v₂). This is the harmonic mean of v₁ and v₂. It is always less than or equal to the arithmetic mean: harmonic mean ≤ geometric mean ≤ arithmetic mean. For v₁ = 40, v₂ = 60: arithmetic = 50, harmonic = 2×40×60/100 = 48. Harmonic mean (48) < arithmetic mean (50).
Can instantaneous speed exceed instantaneous velocity?
No — instantaneous speed = magnitude of instantaneous velocity, always. |v_inst| = |dx/dt|. They are numerically equal; the difference is that speed is a non-negative scalar while velocity (in 1D) is a signed scalar (or a vector in 2D/3D). Speed is never the larger of the two — they are the same number. One might say '|velocity| is a speed' and be correct about the magnitude. NEET may frame this as a trap: 'speed can be greater than velocity' — false: speed equals the magnitude of velocity, and magnitude ≤ the quantity itself holds only for absolute values in arithmetic, but here they are literally the same number.
Why is instantaneous velocity always tangential to the path?
Instantaneous velocity is the derivative of position with respect to time: v = dr/dt. As Δt → 0, the displacement Δr = r(t+Δt) − r(t) points along the direction the particle is currently moving — and as the time interval shrinks to zero, this direction approaches the tangent to the curve at that point. The tangent to a curve at any point is the direction the curve is locally heading at that instant. Hence v is always tangential. This is why for circular motion, the velocity at every point is tangential to the circle — perpendicular to the radius at that point.
Can a particle have zero velocity but non-zero speed?
No — speed is the magnitude of velocity. If velocity = 0 at a particular instant, then speed = |velocity| = |0| = 0 at the same instant. A particle cannot have non-zero speed while having zero velocity. The converse is possible in some conceptual phrasing: if average velocity = 0 (particle returns to start), average speed > 0. But for instantaneous quantities, speed = 0 if and only if velocity = 0 at that instant.
What is uniform velocity and how does it differ from uniform speed?
Uniform velocity: both magnitude AND direction of velocity are constant. This means straight-line motion at constant speed — neither the magnitude nor the direction changes. Uniform speed: only the magnitude of velocity is constant; direction may change. A particle in uniform circular motion has uniform speed but non-uniform velocity (direction constantly changes). Uniform velocity requires straight-line motion; uniform speed does not require a straight line.
In a NEET problem, a particle covers the first and second halves of the journey in times T/2 each. What is the average speed?
If a total journey covers distances d₁ and d₂ in equal times T/2 each: average speed = (d₁+d₂)/T. If the speeds are v₁ = d₁/(T/2) = 2d₁/T and v₂ = d₂/(T/2) = 2d₂/T, then average speed = (v₁T/2 + v₂T/2)/T = (v₁+v₂)/2 = arithmetic mean. This is the equal-time case. Contrast with equal-distance (harmonic mean). The key: identify whether the problem states equal time or equal distance — the formula changes completely.
How do I find when a particle is momentarily at rest from its x(t) equation?
A particle is at rest when its instantaneous velocity v = dx/dt = 0. Step 1: Find v(t) = dx/dt. Step 2: Set v(t) = 0. Step 3: Solve for t. For x = 2t² − 8t + 6: v = 4t − 8. Setting v = 0: 4t − 8 = 0 → t = 2 s. The particle stops momentarily at t = 2 s, then reverses direction (v > 0 for t > 2 s). This technique applies to any polynomial x(t).
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Unit : metre (S.I.)

Comparison between distance and displacement

Types of speed

Types of velocity

Comparison between instantaneous speed and instantaneous velocity

Comparison between average speed and average velocity

The magnitude of displacement

Subtopics

Unit : metre (S.I.)

Comparison between distance and displacement

Types of speed

Types of velocity

Comparison between instantaneous speed and instantaneous velocity

Comparison between average speed and average velocity

The magnitude of displacement

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