Acceleration

NEET > Physics > Kinematics > Motion In One Dimension > Acceleration

Unit Progress

NEET Physics — Motion In One Dimension

Acceleration – Complete Notes, Revision, Important Questions & Downloads

Acceleration is the time rate of change of velocity — the kinematic quantity that links the force-and-motion chapters. One subtopic is covered: Definition and Types. Key definitions: average acceleration = Δv/Δt; instantaneous acceleration a = dv/dt = d²x/dt² = v·dv/dx. Types: uniform acceleration (constant magnitude and direction), non-uniform, positive, negative (retardation), and zero. NEET tests acceleration in three standard forms: (1) compute acceleration from v(t) by differentiation; (2) identify the type of motion from a given a-t or v-t description; (3) use the relationship between acceleration sign and velocity sign to describe the motion — a positive body decelerates when velocity and acceleration have opposite signs, even if acceleration is positive in magnitude.

⬇ Download Notes PDF View Important Questions →

4 SubtopicsRate of Change of Velocitya = dv/dt = v·dv/dx

Expected QuestionsQ

Acceleration is tested every year in NEET, either as a standalone definition/type question or embedded in a v-t graph, kinematics equation, or projectile problem. Expect at least 1 question per paper involving acceleration directly.

Time Required⏱

1 hour

30 minutes for definitions, types, and the three acceleration formulas; 30 minutes for 6–8 numericals combining a = dv/dt, a = v·dv/dx, and sign analysis for retardation.

Difficulty⚡

Easy–Medium

The formulas are short; the marks are lost interpreting sign of acceleration vs sign of velocity — students confuse 'negative acceleration' (a < 0) with 'deceleration' (speed decreasing). These are not always the same: a body with negative velocity and negative acceleration is speeding up in the negative direction.

NRI USA Curriculum GapUS

Low

US AP Physics covers acceleration thoroughly; however, the formula a = v·dv/dx (used when acceleration is a function of position rather than time) and the sign interpretation for retardation (decelerating vs accelerating in negative direction) are less explicitly drilled.

4Subtopics

8+Practice Questions

4Free Downloads

1 hrPrep Time

⬇ Get Free Downloads

NEET Weightage — Acceleration

Motion In One Dimension (Chapter 2)

NEET Year	Questions from this Topic	Bar	Marks
2024	1	1 Q	4
2023	1	1 Q	4
2022	1	1 Q	4
2021	1	1 Q	4
2020	0	0 Q	0
2019	1	1 Q	4
6-Year Total (2019–2024)	2–5		8–20

First form: a = dv/dt. Given v(t), differentiate to get a(t). Given v-t graph, slope = acceleration. Uniform acceleration = constant slope on v-t graph.
Second form: a = v·dv/dx. Useful when acceleration is given as a function of x, not t. Derived from chain rule: a = dv/dt = (dv/dx)(dx/dt) = v·dv/dx.
Retardation (deceleration): body is retarding when velocity and acceleration have opposite signs. A body moving right (v > 0) with a < 0 decelerates — positive velocity, negative acceleration. A body moving left (v < 0) with a > 0 also decelerates — negative velocity, positive acceleration.

📊

~0.8

Avg Questions / Year

🎯

8–20

Total Marks (6 yrs)

📈

Direct

Pattern

⚠️

Easy–Medium

Difficulty

Exam Strategy — Acceleration in NEET

Fix the signs: velocity sign and acceleration sign determine motion description Positive acceleration (a > 0) does NOT always mean the particle is speeding up — it means velocity is increasing algebraically. If v < 0 and a > 0: speed |v| is decreasing (particle decelerating while moving in negative direction). If v > 0 and a > 0: speed is increasing (accelerating). If v > 0 and a < 0: speed decreasing (decelerating). If v < 0 and a < 0: speed increasing (accelerating further in negative direction). Rule: a particle decelerates when v and a have opposite signs.

Know all three acceleration formulas and when to use each a = dv/dt — use when v is given as a function of t or when time is the independent variable. a = d²x/dt² — use when position x is given as a function of t; differentiate x twice. a = v·dv/dx — use when acceleration is given or needed as a function of x, or in energy-based problems. In NEET: if x(t) is given, compute a = d²x/dt². If v(x) is given, compute a = v·dv/dx.

Distinguish uniform from variable acceleration by the shape of v-t and a-t graphs Uniform acceleration: constant a, so v increases linearly with time — v-t graph is a straight line (non-zero slope). Acceleration-time graph: horizontal line at value a. Non-uniform acceleration: v-t graph is a curve (not straight line). a-t graph changes with time. Key: uniform acceleration does not mean the body is moving at constant velocity — velocity is changing (at constant rate).

Download Study Notes — Acceleration

PDF · Cheat Sheet · MCQ Set · PYQ

📘

Acceleration — Full Notes

Complete notes covering the formal definition, three acceleration formulas (a=dv/dt, a=d²x/dt², a=v·dv/dx), types (uniform, variable, positive, negative, zero), retardation definition and sign rule, g values, and 8 worked examples.

4 subtopics8 worked examplesAll three formulas

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📗

Acceleration — Formula Sheet

One-page reference: three acceleration formulas, sign rule for retardation, key NCERT statements, g values in m/s², cm/s², ft/s², and a rapid worked example for each formula form.

1 pageAll formulas + g values

Download PDF

📙

Acceleration — MCQ Practice

12 NEET-style MCQs: compute a from v(t) and x(t), identify motion type from sign analysis, apply the v·dv/dx form, interpret v-t graph slopes, and select correct statement about acceleration types.

12 MCQsDetailed solutions

Download PDF

📕

Acceleration — NEET-Style PYQ Practice

NEET-style practice questions on acceleration types, formulas, and sign interpretation with complete answer key.

NEET-styleAnswer key included

Download PDF

Subtopics in Acceleration

2-Column Table

Column A	Column B
Definition and Types↗	Types of acceleration↗
Uniform acceleration↗	For a moving body there↗

Rapid Revision — Acceleration

Concept → Trap → Example

1) Definition and Types

Rate of Change of Velocity

Acceleration = time rate of change of velocity. Average: a_av = Δv/Δt. Instantaneous: a = dv/dt = d²x/dt² = v·dv/dx. Units: m/s². Positive a: velocity increasing (algebraically). Negative a (retardation in context): velocity decreasing. Zero a: uniform velocity. Uniform acceleration: both magnitude and direction of a are constant.

Three equivalent forms for instantaneous acceleration: a = dv/dt (most direct); a = d²x/dt² (when position given as function of t); a = v·dv/dx (when need a as function of x, using chain rule).
Sign rule for retardation: a body is decelerating (speed decreasing) when velocity and acceleration have opposite signs. v>0 and a<0 → decelerating. v<0 and a>0 → also decelerating. NOT just when a<0.
Key g values: 9.8 m/s² = 980 cm/s² = 32 ft/s². For approximate NEET calculations, g = 10 m/s² unless specified.

Example (NEET-style)v(t) = 6t² − 12t + 3. a(t) = dv/dt = 12t − 12. At t = 1 s: a = 0 (velocity momentarily not changing). At t = 2 s: a = 12 m/s² (positive, velocity increasing). At t = 0.5 s: a = −6 m/s² (negative; if v > 0 here, the body is decelerating).

US Curriculum Gaps — Acceleration for NEET

US AP Physics students may encounter these gaps when approaching acceleration in NEET.

The formula a = v·dv/dx is not used in AP Physics 1 (non-calculus course)

AP Physics 1 does not use calculus explicitly; acceleration is always computed as Δv/Δt numerically or read from the slope of a v-t graph. The formula a = v·dv/dx (derived from the chain rule: a = dv/dt = (dv/dx)(dx/dt) = v·dv/dx) appears in NEET when acceleration is naturally expressed as a function of position — for example, in problems where v varies with x according to v = f(x).

Example NEET problem: 'The velocity of a particle varies as v = 3x. Find the acceleration as a function of x.' Solution: a = v·dv/dx = 3x · d(3x)/dx = 3x · 3 = 9x. This requires both the formula and chain rule — not practised in AP Physics 1.
The three acceleration formulas should be learnt as a unit: a = dv/dt (time-domain), a = d²x/dt² (position-time domain), a = v·dv/dx (position-velocity domain).
Practise recognising which formula to apply: if x(t) is given → use d²x/dt². If v(x) is given → use v·dv/dx. If v(t) is given → use dv/dt.

Sign-based retardation analysis is taught differently in US vs NEET curriculum

AP Physics 1 and US high school physics define 'deceleration' as a situation where the magnitude of velocity (speed) is decreasing — this requires checking whether v and a have opposite signs. However, US courses sometimes informally equate 'negative acceleration' with 'deceleration', which is incorrect when the velocity is also negative. NEET tests this precisely: a body with v = −10 m/s and a = −2 m/s² is accelerating (speed increasing), not decelerating.

Retardation (deceleration): speed decreasing → v and a must have opposite signs. Not just 'a is negative'.
NEET trap: 'a body has negative acceleration, is it retarding?' — Answer: only if v is positive. If v is also negative, the body is accelerating (speed increasing in negative direction).
Practise sign tables: for all four sign combinations of v and a, state whether speed is increasing or decreasing.

NEET-Style Practice Questions — Acceleration

4 NEET-style practice questions

1A particle's velocity is given by v(t) = 4t³ − 6t (in m/s, t in seconds). The instantaneous acceleration at t = 2 s is:NEET-style practice

18 m/s²

42 m/s²

24 m/s²

6 m/s²

a(t) = dv/dt = d(4t³ − 6t)/dt = 12t² − 6. At t = 2 s: a = 12(2²) − 6 = 12(4) − 6 = 48 − 6 = 42 m/s². Option (a) 18: uses 12(2) − 6 = 18 — incorrect, substitutes t not t². Option (c) 24: uses 12t² only = 12(4) = 48 — forgets the −6 term. Option (d) 6: uses only the constant term of the derivative. The key step is differentiating correctly: d(4t³)/dt = 12t² and d(−6t)/dt = −6.

2The velocity of a particle varies with its x-position as v = 2x + 1 (m/s, x in m). The acceleration of the particle at x = 3 m is:NEET-style practice

2 m/s²

7 m/s²

14 m/s²

21 m/s²

Use a = v·dv/dx. Here v = 2x + 1, so dv/dx = 2. At x = 3 m: v = 2(3)+1 = 7 m/s. Therefore a = v·dv/dx = 7 × 2 = 14 m/s². Option (a) uses only dv/dx = 2 without multiplying by v. Option (b) is just the value of v at x = 3. Option (d) is v×(dv/dx)² = 7×3 = 21 — incorrect formula application. The chain rule form a = v·dv/dx is essential for v(x) problems.

3A car is moving in the positive x-direction with velocity +20 m/s and has acceleration −3 m/s². Which of the following is correct?NEET-style practice

The car is accelerating in the positive direction

The car is retarding (speed is decreasing)

The car will immediately stop

The car's speed is increasing

v = +20 m/s (positive direction), a = −3 m/s² (negative direction). Since v and a have opposite signs, the car is decelerating — speed is decreasing. Option (a) is wrong: acceleration is in the negative direction. Option (c) is wrong: stopping requires time, not immediate: time to stop = v/|a| = 20/3 ≈ 6.7 s. Option (d) is directly contradicted by the opposing signs — speed decreases when v and a point in opposite directions.

4A particle is in uniform acceleration. Which of the following graphs represents this motion correctly?NEET-style practice

a-t graph: a straight line with positive slope

v-t graph: a horizontal straight line (no slope)

v-t graph: a straight line with non-zero constant slope and a-t graph: a horizontal line

x-t graph: a straight line

Uniform acceleration = constant acceleration magnitude and direction. On v-t graph: constant slope = constant acceleration → v-t graph is a straight line with non-zero slope. On a-t graph: constant value → horizontal line. Option (a) describes non-uniform acceleration (a is changing). Option (b) describes uniform velocity (a = 0), not uniform acceleration. Option (d) a straight-line x-t graph means constant velocity (a = 0). Option (c) correctly identifies both: v-t straight line (non-horizontal) and a-t horizontal line.

Practice Problems — Acceleration

Click "Reveal Answer" after attempting

1A particle's position is given by x(t) = t³ − 6t² + 9t + 5 (in m, t in s). Find the acceleration at t = 2 s and determine if the particle is accelerating or decelerating.

a = −6 m/s², decelerating (v > 0 and a < 0)

a = 0 m/s², moving with uniform velocity

a = 6 m/s², accelerating

a = −6 m/s², accelerating (v < 0 and a < 0)

👁 Reveal Answer

Option (a): v = dx/dt = 3t² − 12t + 9. At t = 2 s: v = 3(4) − 12(2) + 9 = 12 − 24 + 9 = −3 m/s (moving in negative direction). a = dv/dt = 6t − 12. At t = 2 s: a = 6(2) − 12 = 0. Wait — a = 0 at t = 2 s. Rechecking: a = 6(2) − 12 = 12 − 12 = 0. So the correct answer is a = 0 m/s² at t = 2 s. (NOTE: Option b is correct for this calculation — at t = 2 s the particle has zero acceleration. The particle has v = −3 m/s and a = 0, meaning constant velocity at that instant.)

2The acceleration of a particle is given by a = 3v, where v is velocity in m/s. If the initial velocity is v₀ = 2 m/s, find the acceleration at the initial instant and how the acceleration changes as the particle speeds up.

Initial a = 6 m/s²; as v increases, a also increases

Initial a = 3 m/s²; a remains constant

Initial a = 6 m/s²; a remains constant as v is constant

Initial a = 2/3 m/s²; a decreases as v increases

👁 Reveal Answer

Option (a): At v₀ = 2 m/s: a = 3×2 = 6 m/s². Since a = 3v and a > 0, velocity increases. As v increases, a = 3v increases too — this is a non-uniform, ever-increasing acceleration. This is a case of non-uniform acceleration where acceleration depends on velocity.

3A particle starts from rest and moves with uniform acceleration 4 m/s². What is its velocity and acceleration at t = 5 s?

v = 20 m/s, a = 20 m/s²

v = 20 m/s, a = 4 m/s²

v = 4 m/s, a = 4 m/s²

v = 25 m/s, a = 5 m/s²

👁 Reveal Answer

Option (b): Uniform acceleration means a = constant = 4 m/s² at all times. Velocity at t = 5 s: v = u + at = 0 + 4×5 = 20 m/s. Acceleration remains 4 m/s² — it does not change for uniform acceleration regardless of velocity or time.

4A ball is thrown upward with initial velocity 20 m/s. Taking upward as positive and g = 10 m/s² downward: when the ball is at its highest point, what are its velocity and acceleration?

v = 0, a = 0 (no motion at highest point)

v = 0, a = −10 m/s²

v = 20 m/s, a = −10 m/s²

v = −20 m/s, a = 10 m/s²

👁 Reveal Answer

Option (b): At the highest point, velocity = 0 (the ball momentarily stops before falling back). But acceleration = −g = −10 m/s² (gravitational acceleration acts downward at ALL points during the flight, including the highest point). The common error: students say acceleration = 0 at the highest point because v = 0. This is wrong — a zero velocity does not imply zero acceleration. The ball immediately starts moving downward because acceleration is non-zero even at v = 0.

Physics — Acceleration Revision Checklist

Check off chapters as you revise

Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Definition and Types: Write all three forms of instantaneous accelerationWrite: a = dv/dt; a = d²x/dt²; a = v·dv/dx. State when to use each form. For x(t) problems: use d²x/dt². For v(x) problems: use v·dv/dx.

Definition and Types: Apply the sign rule for retardationState: 'A body decelerates (speed decreases) when velocity and acceleration have opposite signs.' Give all four sign combinations and their motion descriptions.

Definition and Types: Define uniform acceleration and identify it on a-t and v-t graphsState: uniform acceleration = constant magnitude and direction of a. On v-t graph: constant slope (straight line). On a-t graph: horizontal line (constant value).

Definition and Types: Compute acceleration from v(t) by differentiationGiven v(t) = at² + bt + c, compute a = dv/dt = 2at + b. Evaluate at specified time value.

Definition and Types: Apply a = v·dv/dx for position-velocity problemsGiven v = f(x), compute dv/dx and then a = v·(dv/dx). Evaluate at specified x. Verify units: v (m/s) × (dv/dx) (s⁻¹) = m/s².

Frequently Asked Questions — Acceleration

Notes · Downloads · Revision · Important Questions

What is the difference between negative acceleration and deceleration (retardation)?

Negative acceleration means the acceleration vector points in the negative direction (a < 0 in 1D). Deceleration (retardation) means the speed (magnitude of velocity) is decreasing. These are the same thing only when velocity is positive. If v > 0 and a < 0: decelerating. If v < 0 and a < 0: actually accelerating (speed increasing in the negative direction). Deceleration occurs when v and a have opposite signs — regardless of which is positive and which is negative.

Can a body have zero velocity but non-zero acceleration?

Yes. A ball thrown upward reaches zero velocity at its highest point, but gravity gives it an acceleration of g = 9.8 m/s² downward at all times including that instant. Velocity = 0 does not mean acceleration = 0. Acceleration is the rate of change of velocity — even when velocity is momentarily zero, velocity can be changing (which requires non-zero acceleration). This is one of the most common misconceptions tested in NEET.

Why are there three different formulas for acceleration (dv/dt, d²x/dt², v·dv/dx)?

They are equivalent forms derived from the definition a = dv/dt using different mathematical transforms. a = d²x/dt² follows because v = dx/dt, so differentiating again gives a = d(dx/dt)/dt = d²x/dt². a = v·dv/dx uses the chain rule: a = dv/dt = (dv/dx)(dx/dt) = v·dv/dx. Which form to use depends on what is given: x(t) → d²x/dt²; v(t) → dv/dt; v(x) → v·dv/dx. All three give the same acceleration — they are just computed differently based on what information is available.

What is uniform acceleration and what are its graph signatures?

Uniform acceleration: both magnitude and direction of acceleration are constant. Graph signatures: (1) a-t graph: horizontal line at constant value a₀ — acceleration does not change with time. (2) v-t graph: straight line with constant slope = a₀ — velocity changes at a constant rate. (3) x-t graph: parabola (x = ut + ½at²) — concave up if a > 0, concave down if a < 0. The equations v = u + at, s = ut + ½at², v² = u² + 2as apply only for uniform acceleration.

What is the physical significance of acceleration being the second derivative of position?

a = d²x/dt² means: first derivative of position is velocity (rate of position change); second derivative is acceleration (rate of velocity change). Conceptually: position tells us where; velocity tells us how fast position is changing; acceleration tells us how fast velocity is changing. In Newton's second law, F = ma, it is acceleration (second derivative of position) that is linked to force — not position or velocity itself. This is why kinematics and dynamics are connected at the level of d²x/dt².

When would a NEET problem require using a = v·dv/dx instead of a = dv/dt?

Use a = v·dv/dx when: (1) velocity is given as a direct function of position v = f(x), and you need to find acceleration at a specific position; (2) you are solving energy-based or spring-like problems where the restoring force (and hence acceleration) naturally depends on displacement; (3) the problem gives v(x) instead of v(t). Example: 'A particle's velocity varies as v = 4√x. Find acceleration at x = 9 m.' Solution: dv/dx = 4/(2√x) = 2/√x. a = v·dv/dx = 4√x·(2/√x) = 8 m/s² — constant in this case.

What is retardation and can retardation be positive?

Retardation is the term used when acceleration causes a body to slow down (speed decreases). Retardation is always positive as a magnitude — it tells you the rate at which the object slows down. However, the acceleration vector itself may point in the positive or negative direction. Example: a car moving at v = +30 m/s with a = −5 m/s² is retarding at 5 m/s². A car moving at v = −30 m/s with a = +5 m/s² is also retarding at 5 m/s². In both cases, retardation = 5 m/s² (magnitude), even though the acceleration direction differs.

How is acceleration calculated from a velocity-time graph?

Acceleration = slope of the velocity-time (v-t) graph. For straight-line v-t graphs (uniform acceleration): a = (v₂ − v₁)/(t₂ − t₁) = Δv/Δt. For curved v-t graphs (non-uniform acceleration): instantaneous acceleration at a point = slope of the tangent to the curve at that point. Positive slope (rising v-t line) → positive acceleration. Negative slope (falling v-t line) → negative acceleration. Zero slope (horizontal line) → zero acceleration (uniform velocity).

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Motion In One Dimension

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Acceleration

NEET > Physics > Kinematics > Motion In One Dimension > Acceleration

Unit Progress

NEET Physics — Motion In One Dimension

Acceleration – Complete Notes, Revision, Important Questions & Downloads

⬇ Download Notes PDF View Important Questions →

4 SubtopicsRate of Change of Velocitya = dv/dt = v·dv/dx

Expected QuestionsQ

Time Required⏱

1 hour

30 minutes for definitions, types, and the three acceleration formulas; 30 minutes for 6–8 numericals combining a = dv/dt, a = v·dv/dx, and sign analysis for retardation.

Difficulty⚡

Easy–Medium

NRI USA Curriculum GapUS

Low

4Subtopics

8+Practice Questions

4Free Downloads

1 hrPrep Time

⬇ Get Free Downloads

NEET Weightage — Acceleration

Motion In One Dimension (Chapter 2)

NEET Year	Questions from this Topic	Bar	Marks
2024	1	1 Q	4
2023	1	1 Q	4
2022	1	1 Q	4
2021	1	1 Q	4
2020	0	0 Q	0
2019	1	1 Q	4
6-Year Total (2019–2024)	2–5		8–20

📊

~0.8

Avg Questions / Year

🎯

8–20

Total Marks (6 yrs)

📈

Direct

Pattern

⚠️

Easy–Medium

Difficulty

Exam Strategy — Acceleration in NEET

Download Study Notes — Acceleration

PDF · Cheat Sheet · MCQ Set · PYQ

📘

Acceleration — Full Notes

4 subtopics8 worked examplesAll three formulas

Download PDF

📗

Acceleration — Formula Sheet

One-page reference: three acceleration formulas, sign rule for retardation, key NCERT statements, g values in m/s², cm/s², ft/s², and a rapid worked example for each formula form.

1 pageAll formulas + g values

Download PDF

📙

Acceleration — MCQ Practice

12 NEET-style MCQs: compute a from v(t) and x(t), identify motion type from sign analysis, apply the v·dv/dx form, interpret v-t graph slopes, and select correct statement about acceleration types.

12 MCQsDetailed solutions

Download PDF

📕

Acceleration — NEET-Style PYQ Practice

NEET-style practice questions on acceleration types, formulas, and sign interpretation with complete answer key.

NEET-styleAnswer key included

Download PDF

Subtopics in Acceleration

2-Column Table

Column A	Column B
Definition and Types↗	Types of acceleration↗
Uniform acceleration↗	For a moving body there↗

Rapid Revision — Acceleration

Concept → Trap → Example

1) Definition and Types

Rate of Change of Velocity

Three equivalent forms for instantaneous acceleration: a = dv/dt (most direct); a = d²x/dt² (when position given as function of t); a = v·dv/dx (when need a as function of x, using chain rule).
Sign rule for retardation: a body is decelerating (speed decreasing) when velocity and acceleration have opposite signs. v>0 and a<0 → decelerating. v<0 and a>0 → also decelerating. NOT just when a<0.
Key g values: 9.8 m/s² = 980 cm/s² = 32 ft/s². For approximate NEET calculations, g = 10 m/s² unless specified.

US Curriculum Gaps — Acceleration for NEET

US AP Physics students may encounter these gaps when approaching acceleration in NEET.

The formula a = v·dv/dx is not used in AP Physics 1 (non-calculus course)

Example NEET problem: 'The velocity of a particle varies as v = 3x. Find the acceleration as a function of x.' Solution: a = v·dv/dx = 3x · d(3x)/dx = 3x · 3 = 9x. This requires both the formula and chain rule — not practised in AP Physics 1.
The three acceleration formulas should be learnt as a unit: a = dv/dt (time-domain), a = d²x/dt² (position-time domain), a = v·dv/dx (position-velocity domain).
Practise recognising which formula to apply: if x(t) is given → use d²x/dt². If v(x) is given → use v·dv/dx. If v(t) is given → use dv/dt.

Sign-based retardation analysis is taught differently in US vs NEET curriculum

Retardation (deceleration): speed decreasing → v and a must have opposite signs. Not just 'a is negative'.
NEET trap: 'a body has negative acceleration, is it retarding?' — Answer: only if v is positive. If v is also negative, the body is accelerating (speed increasing in negative direction).
Practise sign tables: for all four sign combinations of v and a, state whether speed is increasing or decreasing.

NEET-Style Practice Questions — Acceleration

4 NEET-style practice questions

1A particle's velocity is given by v(t) = 4t³ − 6t (in m/s, t in seconds). The instantaneous acceleration at t = 2 s is:NEET-style practice

18 m/s²

42 m/s²

24 m/s²

6 m/s²

2The velocity of a particle varies with its x-position as v = 2x + 1 (m/s, x in m). The acceleration of the particle at x = 3 m is:NEET-style practice

2 m/s²

7 m/s²

14 m/s²

21 m/s²

3A car is moving in the positive x-direction with velocity +20 m/s and has acceleration −3 m/s². Which of the following is correct?NEET-style practice

The car is accelerating in the positive direction

The car is retarding (speed is decreasing)

The car will immediately stop

The car's speed is increasing

4A particle is in uniform acceleration. Which of the following graphs represents this motion correctly?NEET-style practice

a-t graph: a straight line with positive slope

v-t graph: a horizontal straight line (no slope)

v-t graph: a straight line with non-zero constant slope and a-t graph: a horizontal line

x-t graph: a straight line

Practice Problems — Acceleration

Click "Reveal Answer" after attempting

1A particle's position is given by x(t) = t³ − 6t² + 9t + 5 (in m, t in s). Find the acceleration at t = 2 s and determine if the particle is accelerating or decelerating.

a = −6 m/s², decelerating (v > 0 and a < 0)

a = 0 m/s², moving with uniform velocity

a = 6 m/s², accelerating

a = −6 m/s², accelerating (v < 0 and a < 0)

👁 Reveal Answer

Initial a = 6 m/s²; as v increases, a also increases

Initial a = 3 m/s²; a remains constant

Initial a = 6 m/s²; a remains constant as v is constant

Initial a = 2/3 m/s²; a decreases as v increases

👁 Reveal Answer

3A particle starts from rest and moves with uniform acceleration 4 m/s². What is its velocity and acceleration at t = 5 s?

v = 20 m/s, a = 20 m/s²

v = 20 m/s, a = 4 m/s²

v = 4 m/s, a = 4 m/s²

v = 25 m/s, a = 5 m/s²

👁 Reveal Answer

4A ball is thrown upward with initial velocity 20 m/s. Taking upward as positive and g = 10 m/s² downward: when the ball is at its highest point, what are its velocity and acceleration?

v = 0, a = 0 (no motion at highest point)

v = 0, a = −10 m/s²

v = 20 m/s, a = −10 m/s²

v = −20 m/s, a = 10 m/s²

👁 Reveal Answer

Physics — Acceleration Revision Checklist

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Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Definition and Types: Compute acceleration from v(t) by differentiationGiven v(t) = at² + bt + c, compute a = dv/dt = 2at + b. Evaluate at specified time value.

Frequently Asked Questions — Acceleration

Notes · Downloads · Revision · Important Questions

What is the difference between negative acceleration and deceleration (retardation)?

Can a body have zero velocity but non-zero acceleration?

Why are there three different formulas for acceleration (dv/dt, d²x/dt², v·dv/dx)?

What is uniform acceleration and what are its graph signatures?

What is the physical significance of acceleration being the second derivative of position?

When would a NEET problem require using a = v·dv/dx instead of a = dv/dt?

What is retardation and can retardation be positive?

How is acceleration calculated from a velocity-time graph?

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Subtopics

Definition and Types

Types of acceleration

Uniform acceleration

For a moving body there

Motion In One Dimension

Weightage: 02.2K

Motion In Two Dimension

Weightage: 02.2K

Acceleration

Overview content

Acceleration – Complete Notes, Revision, Important Questions & Downloads

1) Definition and Types

The formula a = v·dv/dx is not used in AP Physics 1 (non-calculus course)

Sign-based retardation analysis is taught differently in US vs NEET curriculum

Physics — Acceleration Revision Checklist

NEET NRI Counseling & Admission eBook Download

Schedule Trial Session For NEET Prep

Definition and Types

Types of acceleration

Uniform acceleration

For a moving body there

Subtopics

Definition and Types

Types of acceleration

Uniform acceleration

For a moving body there

NEET > Physics > Kinematics Chapters

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Acceleration

Overview content

Acceleration – Complete Notes, Revision, Important Questions & Downloads

1) Definition and Types

The formula a = v·dv/dx is not used in AP Physics 1 (non-calculus course)

Sign-based retardation analysis is taught differently in US vs NEET curriculum

Physics — Acceleration Revision Checklist

NEET NRI Counseling & Admission eBook Download

Schedule Trial Session For NEET Prep

Definition and Types

Types of acceleration

Uniform acceleration

For a moving body there

Subtopics

Definition and Types

Types of acceleration

Uniform acceleration

For a moving body there

NEET > Physics > Kinematics Chapters

Comments

Leave a comment

Comments (0)