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Transformer

NEET > Physics > Electromagnetic Induction and Alternating Currents > Electromagnetic Induction > Transformer

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Overview content

Topic 18 of 18 โ€ข Chapter: Electromagnetic Induction โ€ข Physics

Transformer โ€“ Complete Notes, Revision, Important Questions & Downloads

Transformer is the chapter's mutual-induction device topic, and the OCR block covers Transformer Function and Operating Principle, Transformer Equations and Transformation Ratio, Step-up and Step-down Transformers, Efficiency and Losses, and Applications of Transformers. NEET tests this topic through the AC-only condition, the turn-ratio relations Vs by Vp = Ns by Np = Ip by Is, power conservation in the ideal case, identification of step-up versus step-down machines, and the physical reason common losses are reduced by design choices such as laminated cores and soft iron. The topic rewards relational thinking more than memorisation: once the student knows what stays same, what increases, and what must trade off, most transformer questions become one-step decisions.

โฌ‡ Download Notes PDFView Important Questions โ†’
Mutual InductionTurn RatioPower Systems
Expected QuestionsQ
0-1
usually direct on turn ratio, step-up versus step-down identification, AC-only operation, or transformer losses
Time Requiredโฑ
2.5 Hours
enough to lock the ratio formulas, power relation, loss-minimisation logic, and one round of step-up or step-down numericals
Difficultyโšก
Medium
the formulas are compact, but students lose marks by trying to increase both voltage and current together or by mixing primary-secondary turn and current relations
NRI USA Curriculum GapUS
Moderate
students may know transformers from household power examples, but NEET expects exact relations, phase statement, and loss-reduction mechanisms in one coordinated topic
5Subtopics
30Practice Questions
4Free Downloads
2.5 hrsPrep Time
โฌ‡ Get Free Downloads

NEET Weightage & Exam Pattern

Electromagnetic Induction
NEET YearQuestions from this TopicBarMarks
20241
ย 
1 Q
4
20230
ย 
0 Q
0
20220
ย 
0 Q
0
20210
ย 
0 Q
0
20201
ย 
1 Q
4
Topic Weightage2ย 8
Transformer questions are usually direct once the turn ratio and power conservation are applied in the correct direction from primary to secondary.
The most common conceptual trap is to assume a transformer can increase both voltage and current at the same time, which would violate the ideal power relation.

Loss questions are not random facts; each reduction method is paired with a specific physical loss mechanism such as eddy currents, hysteresis, copper heating, or flux leakage.
๐Ÿ“Š
0.4
Avg Questions / Year
๐ŸŽฏ
8
Total Marks (6 yrs)
๐Ÿ“ˆ
Direct
Pattern
โš ๏ธ
Medium
Difficulty

Preparation Strategy

1

Start With The AC-Only Principle A transformer needs changing flux, so the first check is always whether the supply is AC. If the source is DC, the whole operating principle collapses for steady-state transfer.

2

Memorise The Ratio Chain In One Line Keep Vs by Vp = Ns by Np = Ip by Is together. Splitting these into separate memories often causes students to reverse the current relation while correctly remembering the voltage relation.

3

Use Power Conservation To Sanity-Check Answers In the ideal transformer, Vs Is = Vp Ip. If your answer increases both voltage and current on the same side without adding power, it is wrong immediately.

4

Pair Each Loss With Its Remedy Lamination reduces eddy-current loss, soft iron or permalloy reduces hysteresis loss, thick copper wire reduces I squared R loss, and compact winding arrangement reduces flux leakage.

5

Finish With Real Uses The applications section is easier once step-up and step-down behavior is already clear: long-distance transmission needs high voltage and low current, while welding and domestic supply need stepped-down voltage.

Download Topic Notes

PDF ยท Cheat Sheet ยท MCQ Set ยท PYQ
๐Ÿ“„
Full Topic Notes
Detailed notes on transformer principle, ratio relations, step-up and step-down behavior, losses, efficiency, and common applications.
PDF6 Pages
Download Notes
๐Ÿ“
Formula Sheet
One-page sheet for k = Vs by Vp = Ns by Np = Ip by Is, Vs Is = Vp Ip, and efficiency = Pout by Pin into 100.
PDF1 Page
Download Formulas
๐ŸŽฏ
MCQ Practice
Practice set on turn ratio, current-voltage tradeoff, AC-only condition, losses, and device applications.
PDF30 Questions
Download MCQs
โณ
Previous Year Questions
Selected direct questions on ideal transformer relations, step-up or step-down identification, and transformer losses.
PDF10 Questions
Download PYQs

Topic Coverage

2-Column Table
Column AColumn B
Transformer Function and Operating Principleโ†—
Transformer Equations and Transformation Ratioโ†—
Step-up and Step-down Transformersโ†—
Efficiency and Lossesโ†—
Applications of Transformersโ†—

Quick Revision

Concept โ†’ Trap โ†’ Example

1) Transformer Function and Operating Principle

Mutual Induction Device

A transformer raises or lowers voltage in AC circuits through mutual induction. Alternating current in the primary creates changing flux in the core, and that changing flux induces alternating emf in the secondary.

  • It works on AC only because only changing current gives the changing flux needed for induction.
  • There is no electrical connection between primary and secondary; they are linked magnetically through the core.
  • Trap: thinking a transformer can operate on DC after the first instant in the same way it operates on AC.
Example (NEET-style)If a primary coil is connected to a 50 Hz AC source, the magnetic flux in the core changes continuously and induces emf in the secondary. If the same coil is connected to steady DC, the changing-flux condition disappears after the switching transient.

2) Transformer Equations and Transformation Ratio

Voltage Current Turns

For the ideal transformer, Vs by Vp = Ns by Np = Ip by Is = k and the power relation is Vs Is = Vp Ip. The flux per turn of each coil is taken as the same in the textbook model.

  • Voltage ratio follows turn ratio directly, while current ratio is inverse to the turn ratio relation.
  • The page also notes that primary and secondary voltages are in opposite phase.
  • Trap: writing Is by Ip = Ns by Np instead of using the inverse current relation given on the page.
Example (NEET-style)If Np = 100 and Ns = 500 with Vp = 220 V, then Vs = 220 x 500/100 = 1100 V. In the ideal case, the current must then reduce so that Vs Is still equals Vp Ip.

3) Step-up and Step-down Transformers

Direction Of Change

A step-up transformer increases voltage and decreases current with Ns greater than Np and k greater than 1. A step-down transformer decreases voltage and increases current with Ns less than Np and k less than 1.

  • Step-up means higher secondary voltage but lower secondary current.
  • Step-down means lower secondary voltage but higher secondary current.
  • Trap: saying both voltage and current increase in a step-up transformer, which violates ideal power conservation.
Example (NEET-style)If a transformer changes 220 V to 22 V, it is step-down. In the ideal model, the secondary current becomes ten times the primary current because the voltage has become one-tenth.

4) Efficiency and Losses

Real Device Limits

Efficiency is eta = Pout by Pin into 100. The page lists copper loss, eddy-current loss, hysteresis loss, flux leakage, and humming losses, and gives a separate design fix for each major loss.

  • Copper loss comes from I squared R heating and is reduced by thick copper wires.
  • Eddy-current loss is reduced by laminated silicon-steel cores, and hysteresis loss is reduced by soft iron or permalloy core material.
  • Trap: mixing core-related losses with winding-resistance loss and then applying the wrong remedy.
Example (NEET-style)If Pin = 500 W and Pout = 400 W, then efficiency is 400/500 x 100 = 80 percent. The missing 100 W is not one single mechanism; it can be distributed among copper, core, leakage, and mechanical sound losses.

5) Applications of Transformers

Where Each Type Is Used

Transformers are used in voltage regulators, induction furnaces, welding, long-distance AC transmission, electrical power distribution, audio and radio-frequency applications, and impedance matching. The application always follows whether voltage must be stepped up or stepped down.

  • Long-distance transmission prefers high voltage and low current to reduce line loss.
  • Domestic and equipment-side uses usually require step-down action from transmission levels.
  • Trap: memorising applications as a list without linking each one to whether higher or lower output voltage is needed.
Example (NEET-style)In transmission lines, power is stepped up so that the same power can be sent with smaller current, reducing I squared R losses in the wires. Near the user end, transformers step the voltage down again for safe distribution.

US Curriculum Gaps

Note for NRI/OCI students studying abroad.

AP Physics C Often Covers Ideal Ratio Fast But Not The Full Loss Table

Students may know the ideal transformer equations but may not have revised the separate remedies for copper loss, eddy-current loss, hysteresis loss, flux leakage, and humming loss with the same exam specificity expected here.

  • pair each loss with its design fix
  • keep ideal ratio formulas separate from practical losses

Power-System Context Is Sometimes Taught Without Exam-Style Step-Up Or Step-Down Decisions

NEET often reduces transformer applications to one crisp judgment: should voltage increase or decrease here, and what happens to current in the ideal case? Students who know only qualitative household examples can hesitate on that tradeoff.

  • high transmission voltage means lower current for same power
  • domestic and welding uses usually require stepped-down output

Concept IQ Check

Exam-style checks
1Why does a transformer not work on steady DC in normal operation?Operating principle
because DC cannot flow in copper wires
because transformer action needs changing magnetic flux, which steady DC does not provide after switching
because the secondary has infinite capacitance
because magnetic cores work only at high frequency
A transformer works through mutual induction, so the secondary emf appears only when the magnetic flux through the core changes with time. Alternating current in the primary naturally provides that changing flux. Steady DC may create a transient only at switching, but after that the flux stops changing and sustained transformer action disappears. Option B is therefore correct, while the other choices introduce reasons unrelated to the page's operating principle.
2For an ideal transformer, which ratio relation is correct?Transformation ratio
Vs by Vp = Ns by Np = Is by Ip
Vs by Vp = Ns by Np = Ip by Is
Vs by Vp = Np by Ns = Ip by Is
Vs by Vp = Is by Ip = Np by Ns
The OCR page states the transformation ratio as k = Vs by Vp = Ns by Np = Ip by Is. Voltage follows turn ratio directly, but current follows the inverse relation so that ideal power stays conserved. Option B is the only one that preserves both parts of the textbook statement. The other options either reverse the turns ratio or misuse the current relation.
3A transformer increases voltage from primary to secondary. Which description must be true in the ideal case?Step-up or step-down
it is step-up, Ns > Np, and Is < Ip
it is step-down, Ns < Np, and Is < Ip
it is step-up, Ns < Np, and Is > Ip
it is step-up, and both voltage and current increase
If the transformer raises voltage, it is by definition a step-up transformer, so the secondary turns must exceed the primary turns. In the ideal case power is conserved, so a rise in voltage requires a drop in current; hence Is is less than Ip. Option A matches this chain exactly. Option D is the classic trap because it ignores the power relation Vs Is = Vp Ip.
4Which design change mainly reduces eddy-current loss in a transformer core?Losses
using thick copper wire in windings
using laminated silicon-steel core
keeping secondary outside primary
removing the iron core completely
The page states that eddy-current loss is reduced by laminating the core and increasing its resistivity by adding silicon, giving silicon-iron steel. Option B is therefore correct. Thick copper wire helps with copper loss, not eddy currents. Keeping the secondary inside the primary addresses leakage flux, and removing the core destroys the intended magnetic coupling rather than solving the listed design problem.
5Which transformer use is most directly linked with stepping up voltage before long-distance transmission?Applications
welding transformer
audio transformer inside radio circuits
power transmission over long distance
impedance matching only in low-power devices
The OCR page lists transmission of AC over long distance and electrical power distribution among the important uses of transformers. Long-distance transmission uses step-up action so that current becomes smaller for the same power, reducing line loss. Option C therefore follows directly from the application logic. Welding typically uses stepped-down voltage, and the other uses are real but not the main long-distance high-voltage application.

Practice Questions

Click "Reveal Answer" after attempting
1An ideal transformer has Np = 100, Ns = 500, and primary voltage 220 V. Find the secondary voltage.
44 V
220 V
440 V
1100 V
๐Ÿ‘ Reveal Answer
Correct option: D. Use Vs by Vp = Ns by Np. Hence Vs = 220 x 500/100 = 1100 V. Because the number of turns in the secondary is five times the primary, the transformer is step-up and the voltage also becomes five times.
2An ideal transformer has primary voltage 200 V, primary current 2 A, and secondary voltage 1000 V. Find the secondary current.
0.2 A
0.4 A
2 A
10 A
๐Ÿ‘ Reveal Answer
Correct option: B. In the ideal case, Vp Ip = Vs Is. So 200 x 2 = 1000 x Is. That gives Is = 400/1000 = 0.4 A. The answer is smaller than the primary current because this is a step-up transformer, so voltage increases while current decreases.
3Which set correctly describes a step-down transformer?
Vs > Vp, Ns > Np, Is < Ip
Vs < Vp, Ns < Np, Is > Ip
Vs < Vp, Ns > Np, Is < Ip
Vs > Vp, Ns < Np, Is > Ip
๐Ÿ‘ Reveal Answer
Correct option: B. A step-down transformer decreases voltage and therefore must also have fewer turns in the secondary than in the primary. In the ideal case, since power is conserved, the secondary current becomes larger than the primary current when voltage is stepped down.
4A transformer has input power 500 W and output power 400 W. What is its efficiency?
20%
50%
80%
125%
๐Ÿ‘ Reveal Answer
Correct option: C. Efficiency = Pout by Pin into 100 = 400/500 x 100 = 80 percent. The answer must be less than 100 percent for a practical transformer because some input power is lost through copper loss, eddy-current loss, hysteresis, leakage, and other practical effects.
5Which pairing of transformer loss and remedy is correct?
Copper loss - laminated core
Hysteresis loss - thick copper wire
Eddy-current loss - laminated silicon-steel core
Flux leakage - soft iron only
๐Ÿ‘ Reveal Answer
Correct option: C. Eddy-current loss is reduced by using laminated cores and increasing core resistivity, commonly through silicon-steel construction. Thick copper wire helps reduce copper loss, not hysteresis loss. Hysteresis is reduced by suitable magnetic materials such as soft iron or permalloy, and flux leakage is reduced by winding arrangement rather than by that single incomplete statement.

Physics Revision Checklist

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Transformer FAQs

Notes ยท Downloads ยท Revision ยท Important Questions
Why does a transformer work only on AC and not on steady DC?
A transformer needs changing magnetic flux in the core to induce emf in the secondary. Alternating current in the primary naturally produces this changing flux again and again. Steady DC can give only a transient at the instant of switching; after that the flux becomes constant and sustained induction in the secondary disappears.
What is the easiest way to remember the transformation ratio?
Keep the whole chain together: Vs by Vp equals Ns by Np equals Ip by Is. Voltage follows turns directly, while current follows inversely so that ideal power remains conserved. Remembering only one part of the chain is what causes most exam errors.
Can a transformer increase both voltage and current at the same time?
Not in the ideal relation used on the page. If voltage increases, current must decrease so that Vs Is remains equal to Vp Ip. A claim that both rise together would create extra output power from nowhere, which would violate the conservation law built into the ideal transformer model.
Why is there no direct electrical connection between primary and secondary?
The page says the windings are not connected electrically; they are linked magnetically. That is the whole point of mutual induction. Energy transfer occurs through the common changing magnetic flux in the core rather than by direct conduction from one winding into the other.
How do you identify a step-up transformer quickly?
Look for secondary turns greater than primary turns and secondary voltage greater than primary voltage. In the ideal case, that also means the secondary current is smaller. If those three statements do not agree with one another, the interpretation is wrong.
Which transformer loss is reduced by lamination of the core?
Lamination mainly reduces eddy-current loss. Breaking the core into insulated thin layers increases the effective resistance for circulating eddy currents, so less electrical energy is wasted as heating inside the core. This remedy should not be confused with thick copper wire, which targets winding-resistance loss instead.
Why are soft iron or permalloy preferred for transformer cores?
They reduce hysteresis loss because they have a narrow hysteresis loop and can be magnetised and demagnetised repeatedly with smaller energy loss. Since the core experiences alternating magnetisation during AC operation, the choice of magnetic material directly affects practical efficiency.
What is the most efficient way to revise transformer applications before NEET?
Do not revise applications as an isolated list. Connect each one to whether the transformer must raise voltage, lower voltage, or provide matching. Once you classify long-distance transmission as step-up and household or welding uses as step-down, most application questions become straightforward.
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Transformer Function and Operating Principle

Transformer Equations and Transformation Ratio

Step-up and Step-down Transformers

Efficiency and Losses

Applications of Transformers

Subtopics

Transformer Function and Operating Principle

Transformer Equations and Transformation Ratio

Step-up and Step-down Transformers

Efficiency and Losses

Applications of Transformers

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